Home |
Search |
Today's Posts |
|
#1
![]() |
|||
|
|||
![]()
Most of you wrote that your antennas work below the voltage necessary to
start the electron emission. But in reality the emission take place at all voltages. " Attempts to understand autoelectronic emission included plotting experimental current-voltage (i - V) data in different ways, to look for a straight-line relationship. Current increased with voltage more rapidly than linearly, but plots of type (log(i) vs. V) were not straight" "A breakthrough came when Lauritsen[13] (and Oppenheimer independently[14]) found that plots of type (log(i) vs. 1/V) yielded good straight lines. This result, published by Millikan and Lauritsen[13] in early 1928, was known to Fowler and Nordheim. Oppenheimer had predicted[14] that the field-induced tunneling of electrons from atoms (the effect now called field ionization) would have this i(V) dependence, had found this dependence in the published experimental field emission results of Millikan and Eyring,[10] and proposed that CFE was due to field-induced tunneling of electrons from atomic-like orbitals in surface metal atoms. From: http://en.wikipedia.org/wiki/Field_electron_emission Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Best Regards, S* |
#2
![]() |
|||
|
|||
![]()
Szczepan Bialek wrote:
Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Of course not. Not only is this effect too small to be measured at voltages common on a transmitter antenna, the voltage is also AC so these effects will cancel out along the cycle of the AC wave. The net result will be zero. There can only be a net current when there is a (large) DC voltage on the charged body, which is not the case on a transmitter antenna. |
#3
![]() |
|||
|
|||
![]() "Rob" napisal w wiadomosci ... Szczepan Bialek wrote: Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Of course not. Not only is this effect too small to be measured at voltages common on a transmitter antenna, the voltage is also AC so these effects will cancel out along the cycle of the AC wave. The net result will be zero. No. "Once liberated, electrons are strongly repelled by the high electric field near the electrode during negative voltage peaks from the oscillating HV output " There can only be a net current when there is a (large) DC voltage on the charged body, which is not the case on a transmitter antenna. In a transmitter antenna is the "oscillatory flow of electrons" with the net current from the earth into air. S* |
#4
![]() |
|||
|
|||
![]()
On Sat, 21 Apr 2012 09:24:03 +0200, "Szczepan Bialek"
wrote: Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Great theory. If antennas emitted electrons, and electrons have mass, we could then build a rotating antenna powered by the electron belching reaction mass. Put the antenna on a hub, and watch the electron emissions turn the antenna as they fly off the antenna at ummm... the speed of light. A few hundred watts of power should be more than enough to move the antenna around. Yeah, great physics you have there. Hint: How fast do electrons travel in a wire? No, it's not the speed of light. It's called electron drift velocity. http://en.wikipedia.org/wiki/Drift_velocity http://www.jensign.com/JavaScience/www/cuwire/cuwire.html For the above example, it takes about 12 hours for an electron to travel 1 meter in a copper wire. Not exactly at RF speeds. Keep trying. Eventually, you'll get something correct. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#5
![]() |
|||
|
|||
![]() "Jeff Liebermann" napisal w wiadomosci ... On Sat, 21 Apr 2012 09:24:03 +0200, "Szczepan Bialek" wrote: Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Great theory. If antennas emitted electrons, and electrons have mass, we could then build a rotating antenna powered by the electron belching reaction mass. Put the antenna on a hub, and watch the electron emissions turn the antenna as they fly off the antenna at ummm... the speed of light. A few hundred watts of power should be more than enough to move the antenna around. Yeah, great physics you have there. Hint: How fast do electrons travel in a wire? No, it's not the speed of light. It's called electron drift velocity. http://en.wikipedia.org/wiki/Drift_velocity http://www.jensign.com/JavaScience/www/cuwire/cuwire.html For the above example, it takes about 12 hours for an electron to travel 1 meter in a copper wire. Not exactly at RF speeds. The air molecules travel with the speed of the wind. But they oscillate if there is the sound source. The speed of sound and the speed the wind are the different things. The same is with the electron waves speed and the electron beam (drift) speed. Keep trying. Eventually, you'll get something correct. S* |
#6
![]() |
|||
|
|||
![]()
Szczepan Bialek wrote:
The air molecules travel with the speed of the wind. But they oscillate if there is the sound source. The speed of sound and the speed the wind are the different things. The same is with the electron waves speed and the electron beam (drift) speed. Nope, this is babbling nonsense and disproven long ago. |
#7
![]() |
|||
|
|||
![]()
On Sat, 21 Apr 2012 17:51:31 +0200, "Szczepan Bialek"
wrote: "Jeff Liebermann" napisal w wiadomosci .. . On Sat, 21 Apr 2012 09:24:03 +0200, "Szczepan Bialek" wrote: Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Great theory. If antennas emitted electrons, and electrons have mass, we could then build a rotating antenna powered by the electron belching reaction mass. Put the antenna on a hub, and watch the electron emissions turn the antenna as they fly off the antenna at ummm... the speed of light. A few hundred watts of power should be more than enough to move the antenna around. Yeah, great physics you have there. Hint: How fast do electrons travel in a wire? No, it's not the speed of light. It's called electron drift velocity. http://en.wikipedia.org/wiki/Drift_velocity http://www.jensign.com/JavaScience/www/cuwire/cuwire.html For the above example, it takes about 12 hours for an electron to travel 1 meter in a copper wire. Not exactly at RF speeds. The air molecules travel with the speed of the wind. But they oscillate if there is the sound source. The speed of sound and the speed the wind are the different things. Please let me know how far you can communicate using air molecules. There is a momentum transfer when moving air, but it dissipates rather quickly. Comparing electron dynamics with pneumatics just doesn't work.[1] The same is with the electron waves speed and the electron beam (drift) speed. Same as what? There is no such thing as an electron wave. There are electron beams, and radio waves, with very little overlap. If think that electrons fly off the ends of an antenna, there should be a way to directly detect those electrons. For example, a CRT has a phosphor screen that lights up when hit by electrons from the electron gun. If your mythical electrons are really there, you should also be able to place a phosphor screen near a transmitting antenna, and have it light up. Also, if your electrons are leaving the antenna, and flying off into the ether, there should be a rather large positive charge left on the antenna. If you then claim that the transmitter is replacing the electrons as fast as they are radiated, then the positive charge should reside in the transmitter. If you then claim that the local electric utility is supplying electrons to the transmitter, then the utility generating station must have a huge positive charge. Keep trying. Eventually, you'll get something correct. S* You're not trying hard enough. Open book, insert face, absorb everything, and verify what you've learned using real world examples and numerical calculations. If your theory of the moment can't be reduced to real (i.e. non-quantum) physics, with real calculations, and real experimental verification, it's probably wrong. [1] Maybe this will help. It's not a perfect analogy, but it's close enough. Find a billiard table and line up about 10 balls in a line and as close together as possible. Use another ball to hit one end of the line, and time how long it takes between the first impact, and when the ball at the end starts to move. Now, cover the same distance with just the cue ball, and without the line of billiard balls. Note how it take MUCH longer for just the cue ball to travel the same distance. The line of billiard balls represents the atoms in a conductor. You'll get electron transport at almost the speed of light in such a situation. The cue ball alone represents the electron drift in the same conductor. If the cue ball could be made to travel at the same speed as it did through the line of billard balls, the felt on the billiard table would probably show a deep burn mark. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#8
![]() |
|||
|
|||
![]()
Jeff Liebermann wrote:
Also, if your electrons are leaving the antenna, and flying off into the ether, there should be a rather large positive charge left on the antenna. If you then claim that the transmitter is replacing the electrons as fast as they are radiated, then the positive charge should reside in the transmitter. If you then claim that the local electric utility is supplying electrons to the transmitter, then the utility generating station must have a huge positive charge. Well, he thinks that this is what is happening and therefore he believes that any transmitter should always be grounded so that the earth can supply the missing electrons and prevent the transmitter from being charged more and more. However, we all know this doesn't happen. He himself has no way to verify it because he does not have a transmitter (or he is not bright enough to realize that maybe he has one in his pocket). So he keeps insisting that the transmitter must be grounded or problems would occur because of the electron emission. When everyone agrees that these problems do not occur, he does not realize that maybe the electron emission is not there at the voltages involved, and he was wrong after all. |
#9
![]() |
|||
|
|||
![]() "Jeff Liebermann" napisal w wiadomosci ... On Sat, 21 Apr 2012 17:51:31 +0200, "Szczepan Bialek" wrote: "Jeff Liebermann" napisal w wiadomosci . .. On Sat, 21 Apr 2012 09:24:03 +0200, "Szczepan Bialek" wrote: Electrons escape from each charged body. Your antennas emit electrons and for this reason they need the sink of electrons (the earth/chassis/ counterpoise). Great theory. If antennas emitted electrons, and electrons have mass, we could then build a rotating antenna powered by the electron belching reaction mass. Put the antenna on a hub, and watch the electron emissions turn the antenna as they fly off the antenna at ummm... the speed of light. A few hundred watts of power should be more than enough to move the antenna around. Yeah, great physics you have there. Hint: How fast do electrons travel in a wire? No, it's not the speed of light. It's called electron drift velocity. http://en.wikipedia.org/wiki/Drift_velocity http://www.jensign.com/JavaScience/www/cuwire/cuwire.html For the above example, it takes about 12 hours for an electron to travel 1 meter in a copper wire. Not exactly at RF speeds. The air molecules travel with the speed of the wind. But they oscillate if there is the sound source. The speed of sound and the speed the wind are the different things. Please let me know how far you can communicate using air molecules. There is a momentum transfer when moving air, but it dissipates rather quickly. Comparing electron dynamics with pneumatics just doesn't work.[1] All is O.K. Oscillating molecules produce the electron waves and in this way lost its energy rather quickly. But no smaller species than the electrons. Tunnig fork transfer its energy to air molecules, air molecules to electrons and no next step. The same is with the electron waves speed and the electron beam (drift) speed. Same as what? There is no such thing as an electron wave. There no such thing as the EM waves. There are electron beams, and radio waves, with very little overlap. Like wind and sound. If think that electrons fly off the ends of an antenna, there should be a way to directly detect those electrons. For example, a CRT has a phosphor screen that lights up when hit by electrons from the electron gun. If your mythical electrons are really there, you should also be able to place a phosphor screen near a transmitting antenna, and have it light up. Cathode rays were idenified in 1895. Also, if your electrons are leaving the antenna, and flying off into the ether, there should be a rather large positive charge left on the antenna. You call it "static". If you then claim that the transmitter is replacing the electrons as fast as they are radiated, then the positive charge should reside in the transmitter. If you then claim that the local electric utility is supplying electrons to the transmitter, then the utility generating station must have a huge positive charge. For this reason the all electronic equipment have the earth/chassis/counterpoise as e remedy. Keep trying. Eventually, you'll get something correct. S* You're not trying hard enough. Open book, insert face, absorb everything, and verify what you've learned using real world examples and numerical calculations. If your theory of the moment can't be reduced to real (i.e. non-quantum) physics, with real calculations, and real experimental verification, it's probably wrong. It could not be wrong because such Giants as Ampere, Faraday, Stokes, Lorenz, Tesla and Dirac were "using real world examples and numerical calculations." [1] Maybe this will help. It's not a perfect analogy, but it's close enough. Find a billiard table and line up about 10 balls in a line and as close together as possible. Use another ball to hit one end of the line, and time how long it takes between the first impact, and when the ball at the end starts to move. Now, cover the same distance with just the cue ball, and without the line of billiard balls. Note how it take MUCH longer for just the cue ball to travel the same distance. The line of billiard balls represents the atoms in a conductor. You'll get electron transport at almost the speed of light in such a situation. The cue ball alone represents the electron drift in the same conductor. If the cue ball could be made to travel at the same speed as it did through the line of billard balls, the felt on the billiard table would probably show a deep burn mark. Ampere, Faraday, Stokes, Lorenz, Tesla and Dirac analyzed and explained everythig. "Maybe this will help": 1825 - Ampere publishes his collected results on magnetism. His expression for the magnetic field produced by a small segment of current is different from that which follows naturally from the Biot-Savart law by an additive term which integrates to zero around closed circuit. It is unfortunate that electrodynamics and relativity decide in favor of Biot and Savart rather than for the much more sophisticated Ampere, whose memoir contains both mathematical analysis and experimentation, artfully blended together. In this memoir are given some special instances of the result we now call Stokes theorem or as we usually write it. Maxwell describes this work as ``one of the most brilliant achievements in science. The whole, theory and experiment, seems as if it had leaped, full-grown and full-armed, from the brain of the `Newton of electricity'. It is perfect in form and unassailable in accuracy; and it is summed up in a formula from which all the phenomena may be deduced, and which must always remain the cardinal formula of electrodynamics.'' From: http://www.electricityforum.com/a-ti...ectricity.html "a small segment of current" = electron. "the Biot-Savart law" = hydraulic analogy. Teaching and science are the two different things. In teaching is the hydraulic analogy in science are electrons. "It is unfortunate that electrodynamics and relativity decide in favor of Biot and Savart rather than for the much more sophisticated Ampere". S* |
#10
![]() |
|||
|
|||
![]()
Szczepan Bialek wrote:
If you then claim that the transmitter is replacing the electrons as fast as they are radiated, then the positive charge should reside in the transmitter. If you then claim that the local electric utility is supplying electrons to the transmitter, then the utility generating station must have a huge positive charge. For this reason the all electronic equipment have the earth/chassis/counterpoise as e remedy. Maybe in 1900, but not today. This is because it was found that an antenna does not emit electrons. |
Reply |
|
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Carbon Emission Regulations to be Used as Censorship Tool | Shortwave |