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[email protected] August 9th 12 04:00 PM

Poynting vector
 
Rob wrote:
tom wrote:
And I am Polish so I can make fun of my heritage. Our last name was
quite different when my grandfather moved to the US.


Ah, see! We DO have two Poles on the newsgroup.


Unfortunately one is in the left half of the plane and the other in the right
half of the plane so we are a bit lacking in stability.




Szczepan Bialek August 9th 12 05:46 PM

Poynting vector
 

"Rob" napisał w wiadomości
...
David wrote:
On Thu, 09 Aug 2012 07:53:35 +0000, Rob wrote:

tom wrote:
And I am Polish so I can make fun of my heritage. Our last name was
quite different when my grandfather moved to the US.

Ah, see! We DO have two Poles on the newsgroup.


dipole?


I think we have the monopole and the counterpoise.


I was starting to write the same.
S*



Ian[_5_] August 9th 12 05:52 PM

Poynting vector
 
"Szczepan Bialek" wrote in message
...
: : Ah, see! We DO have two Poles on the newsgroup.
:
: dipole?
:
: I think we have the monopole and the counterpoise.
:
: I was starting to write the same.
: S*
I believe irony can be hard to understand and appreciate.
Regards, Ian.



Szczepan Bialek August 9th 12 06:01 PM

Poynting vector
 

"Ian" napisał w wiadomości
...
"Szczepan Bialek" wrote in message
...
: :
: So we have the three teams of posters:
: 1. Faraday, Stokes, Lorenz, Marconi, Tesla and Dirac,
: 2. Heaviside and Poynting,
: 3. You, Tom, Rob and Jimp.
:
: From whom should I learn?
: : S*
Hello Szczepan. Teams 1 and 2 do not exist, do they? Faraday and the
others
aren't sitting at computers and making posts, are they?
You're making posts with text that you seem not to understand. This
confuses
you even more and amuses us.


Do you agree with Heaviside and Poynting. Father of the famous vector wrote
in 1884 (before the Hertz experiment):

""Energy is transferred through empty space outside the wires".
"The whole of the energy then enters in through the external surface of the
wire, and by the general theorem the amount entering in must just account
for the heat developed owing to the resistance,"

As you should see the energy from the transmitter enters in through the
external surface of the
wire (antenna) and next is radiated as the heat.

It amuses me. And what about you?
Do you know that antennas radiate very,very lower frequences than heat?


"'How does energy really flow in electric circuits?'. The answer is fairly
standard university-level physics but is rarely mentioned in secondary
school text books".

What textbooks you have?
S*



W5DXP August 9th 12 07:24 PM

Poynting vector
 
On Thursday, August 9, 2012 12:01:31 PM UTC-5, Szczepan Bialek wrote:
"'How does energy really flow in electric circuits?'.


The coherent RF energy flows near the surface of the conductor at the speed of light in clouds of photons. Given the magnitude of the Poynting vector, we can calculate the number of photons passing through that area in unit time. Those coherent photons that extend into the inner surface effect area have the highest probability of their energy being converted into infrared higher energy photons, i.e. heat radiation. After all, RF photons cannot exist for long deep inside a real-world conductor and they cannot exist at all inside a zero resistance conductor. Here's a question for you: How many 10 MHz photons does it take to generate one infrared photon?

Only steady-state DC doesn't involve photons. All AC, RF, and transient DC functions involve photons and that has been accepted as scientific fact for about a century. Unfortunately, the physicists being quoted by you were completely ignorant of the existence of photons.
--
73, Cecil, w5dxp.com

Ian[_5_] August 9th 12 07:34 PM

Poynting vector
 
"Szczepan Bialek" wrote in message
.. .
: Do you agree with Heaviside and Poynting. Father of the famous vector
wrote
: in 1884 (before the Hertz experiment):
: ""Energy is transferred through empty space outside the wires".
: "The whole of the energy then enters in through the external surface of
the
: wire, and by the general theorem the amount entering in must just account
: for the heat developed owing to the resistance,"
: As you should see the energy from the transmitter enters in through the
: external surface of the
: wire (antenna) and next is radiated as the heat.
: It amuses me. And what about you?
: Do you know that antennas radiate very,very lower frequences than heat?
: "'How does energy really flow in electric circuits?'. The answer is
fairly
: standard university-level physics but is rarely mentioned in secondary
: school text books".
:
: What textbooks you have?
: S*

Hello Szczepan.
I am a licensed radio amateur and I am concerned with matching my aerial to
my transceiver. I'm personally not at all concerned about any heating
effect, theoretical or actual. Sounds like a topic for one of the physics
newsgroups.
As for textbooks, I have a shelf of them. You'll remember the
recommendations I made in other posts.
Regards, Ian.



[email protected] August 9th 12 11:39 PM

Poynting vector
 
Szczepan Bialek wrote:

"Ian" napisa? w wiadomo?ci
...
"Szczepan Bialek" wrote in message
...
: :
: So we have the three teams of posters:
: 1. Faraday, Stokes, Lorenz, Marconi, Tesla and Dirac,
: 2. Heaviside and Poynting,
: 3. You, Tom, Rob and Jimp.
:
: From whom should I learn?
: : S*
Hello Szczepan. Teams 1 and 2 do not exist, do they? Faraday and the
others
aren't sitting at computers and making posts, are they?
You're making posts with text that you seem not to understand. This
confuses
you even more and amuses us.


Do you agree with Heaviside and Poynting. Father of the famous vector wrote
in 1884 (before the Hertz experiment):

""Energy is transferred through empty space outside the wires".
"The whole of the energy then enters in through the external surface of the
wire, and by the general theorem the amount entering in must just account
for the heat developed owing to the resistance,"


Nope; proved incorrect or incomplete, depending on how you want to look
at it.

As you should see the energy from the transmitter enters in through the
external surface of the
wire (antenna) and next is radiated as the heat.


Nope, not a chance.

It amuses me. And what about you?


Your babbling?

Yes, it is amusing how you are always wrong.

Do you know that antennas radiate very,very lower frequences than heat?


If by "heat" you mean infrared, then yes, standard radio frequencies are
much lower than the frequency of infrared light, but you only got that
correct by accident.

"'How does energy really flow in electric circuits?'. The answer is fairly
standard university-level physics but is rarely mentioned in secondary
school text books".


Of course not; lots of detail in every field is ommited at the secondary
school level.

So what.

What textbooks you have?


Lots; all university level and all read.

Do you wear slip on shoes?



[email protected] August 9th 12 11:41 PM

Poynting vector
 
Ian wrote:
"Szczepan Bialek" wrote in message
...
: : Ah, see! We DO have two Poles on the newsgroup.
:
: dipole?
:
: I think we have the monopole and the counterpoise.
:
: I was starting to write the same.
: S*
I believe irony can be hard to understand and appreciate.
Regards, Ian.



Everything is hard for this idiot to understand.



Szczepan Bialek August 10th 12 08:05 AM

Poynting vector
 

napisał w wiadomości
...
Szczepan Bialek wrote:


Do you agree with Heaviside and Poynting. Father of the famous vector
wrote
in 1884 (before the Hertz experiment):

""Energy is transferred through empty space outside the wires".
"The whole of the energy then enters in through the external surface of
the
wire, and by the general theorem the amount entering in must just account
for the heat developed owing to the resistance,"


Nope; proved incorrect or incomplete, depending on how you want to look
at it.

As you should see the energy from the transmitter enters in through the
external surface of the
wire (antenna) and next is radiated as the heat.


Nope, not a chance.

It amuses me. And what about you?


Your babbling?

Yes, it is amusing how you are always wrong.

Do you know that antennas radiate very,very lower frequences than heat?


If by "heat" you mean infrared, then yes, standard radio frequencies are
much lower than the frequency of infrared light, but you only got that
correct by accident.

"'How does energy really flow in electric circuits?'. The answer is
fairly
standard university-level physics but is rarely mentioned in secondary
school text books".


Of course not; lots of detail in every field is ommited at the secondary
school level.


In the secondary school level are electrons.
In university level are the all theories including "proved incorrect or
incomplete".
Students should know all of them.


What textbooks you have?


Lots; all university level and all read.


So try to pick up the theorirs which are "proved incorrect or incomplete".

The first should be Heaviside's and Poynting's.
S*



Szczepan Bialek August 10th 12 08:09 AM

Poynting vector
 

"W5DXP" napisal w wiadomosci
...
On Thursday, August 9, 2012 12:01:31 PM UTC-5, Szczepan Bialek wrote:
"'How does energy really flow in electric circuits?'.


The coherent RF energy flows near the surface of the conductor at the speed
of light in clouds of photons. Given the magnitude of the Poynting vector,
we can calculate the number of photons passing through that area in unit
time. Those coherent photons that extend into the inner surface effect area
have the highest probability of their energy being converted into infrared
higher energy photons, i.e. heat radiation. After all, RF photons cannot
exist for long deep inside a real-world conductor and they cannot exist at
all inside a zero resistance conductor. Here's a question for you: How many
10 MHz photons does it take to generate one infrared photon?


Only steady-state DC doesn't involve photons. All AC, RF, and transient DC
functions involve photons and that has been accepted as scientific fact for
about a century. Unfortunately, the physicists being quoted by you were
completely ignorant of the existence of photons.


Could you please to quote the physicists which are completely sure of the
existence of photons?
S*




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