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![]() Say a beam has 5db forward gain and a front to back difference of 20db. Where does the extra 15db go? I mean, if you loose 20db off the back on transmit, I assume you also loose that much on receive. What happened to the 20db? Did it burn up as heat? What am I missing here? -- Steve The analogy to a balloon is pretty apt. Squeeze and pinch the back so only about 1/50 th of the air that used to be there is left. The rest gets distributed towards the front, and makes the front side more than a factor of two bigger. But the ratio of the amount of air in the front to that of the back is very big--say, 100. That's a 20dB F/B. Hope that helps. 73, Chip N1IR |
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