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#11
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Bernie wrote in :
He thinks your writing style is deranged and your theories are total nonsense. He also pleased that someone is willing to take the time to expose your posts for the idiotic nonsense that they are, because leaving you to post that sort of guff unchallenged could give a casual reader the mistaken impression that you are in any way correct in your bizarre assertions. Concise. ![]() I was at leasi intelligible because you got it. ![]() it's not aimed at Gareth, it's specifically aimed at supporting the countering move. Not the same thing, because as I explained, there are several other aspects of life where this matters. |
#12
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On Sat, 01 Nov 2014 13:52:06 -0500, Lostgallifreyan wrote:
Bernie wrote in : He thinks your writing style is deranged and your theories are total nonsense. He also pleased that someone is willing to take the time to expose your posts for the idiotic nonsense that they are, because leaving you to post that sort of guff unchallenged could give a casual reader the mistaken impression that you are in any way correct in your bizarre assertions. Concise. ![]() like I was at leasi intelligible because you got it. ![]() though... it's not aimed at Gareth, it's specifically aimed at supporting the countering move. Not the same thing, because as I explained, there are several other aspects of life where this matters. I kept it short as I was worried about 'putting words in your mouth'. I didn't mention the Chopin, either - doesn't matter how many times I hear it, I never tire of Berceuse : http://www.youtube.com/watch?v=8TQ-AXJZqtg |
#13
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Bernie wrote in :
I never tire of Berceuse Nice. I bet Satie knew that, there seems to be a link in his sound. For me it's mainly the Etudes and Preludes that work best... Not sure why, and not all either, mostly the lyrical Schubert-like ones, rather than the purely virtuosic stuff, I remember watching my mum playing once, I just stood there, and my mind got strongly influenced by that, it mixed a fascination for many more things, all related, organs, synthesisers, looms, typeriters like my dad used, computers, logic arrays, the things Babbage built... It's all related, and to me all such machines are living, or a direct extension of life. It's a slow Saturday night, but I'll stop there, it's strayed a bit from antennas, though if (and only if) a good and specific reason arises, I'll say why I think antennas of all things have gathered such an acrimonius history in Usenet dicussions, but otherwise I'll keep that bit of philosphy to myself. It's not a complex thought, just a deep and entirely untechnical one... |
#14
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On 11/1/2014 11:26 AM, gareth wrote:
Ignoring, for the moment, travelling wave antenna, and restricting discussion to standing wave antennae ... A wave is launched, and radiates SOME of the power, and suffers both I2R losses and dielectric and permeability losses associated with creating and collapsing the near field. At first, there is no standing wave, until the wave reaches the point of reflection in the antenna and heads back the way it has come (because not all has been radiated*****) On the way back, it againn suffers the losses described above, as well as radiating a bit more. It then reaches the other end and suffers further reflections ad infinitum. An interesting conclusion is, therefore, that the I2R losses are repeated, each tiome with a smaller loss, as the wave decrements. ***** Without the remnants of non-radiated power, there could NOT be a standing wave! I think the subject says it all. -- Rick |
#15
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#16
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#17
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rickman wrote in :
Hmm, what? I'm sorry, I was looking out the window for a moment. Were you saying something? Nope. writing. |
#18
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On Sat, 1 Nov 2014 15:26:52 -0000, "gareth"
wrote: ***** Without the remnants of non-radiated power, there could NOT be a standing wave! That's quite true. Standing waves require a transmission line. If all the RF has been radiated, and there are no "remnants" left in the transmission line, there can be no standing waves because there is no RF. Think about the other boundary conditions. If you unplug the coax cable and antenna, and then transmit into an open circuit, there are no standing waves. All the RF power is converted to heat in the output stage. There's no transmission line upon which to produce standing waves and there's no antenna to radiate. Without a transmission line or antenna, there can be no radiation and therefore, not standing waves. The other extreme is also true. If you have an infinitely long lossless coaxial cable, with either an open, short, or black hole at the far end, there are no reflections because the wave will never quite reach the open or short to produce a reflection. Without a reflection, there can be no standing waves. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#19
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Jeff Liebermann wrote in
: Without a reflection, there can be no standing waves. That's the one bit that comes naturally to my own understanding, such as it is. How far does this parallel with an optical laser cavity? I'd find it easier to understand if someone here who knows both can point out a few essential similarotes and differences. Also, in the ringing of a resonant audio filter (or any electronic filter), there seem to be parallels there too. After all you can only have ringing, a note produced, while energy remains in the system. |
#20
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On 2014-11-01 20:44:55 +0000, Jeff Liebermann said:
On Sat, 1 Nov 2014 15:26:52 -0000, "gareth" wrote: ***** Without the remnants of non-radiated power, there could NOT be a standing wave! That's quite true. Standing waves require a transmission line. If all the RF has been radiated, and there are no "remnants" left in the transmission line, there can be no standing waves because there is no RF. Think about the other boundary conditions. If you unplug the coax cable and antenna, and then transmit into an open circuit, there are no standing waves. All the RF power is converted to heat in the output stage. There's no transmission line upon which to produce standing waves and there's no antenna to radiate. Without a transmission line or antenna, there can be no radiation and therefore, not standing waves. The other extreme is also true. If you have an infinitely long lossless coaxial cable, with either an open, short, or black hole at the far end, there are no reflections because the wave will never quite reach the open or short to produce a reflection. Without a reflection, there can be no standing waves. However, this does not change the fact that standing waves do not 'use up' any of the power fed to the aerial (in principle, increased current intensity increases resistive losses, but this loss can be made arbitrarily low by having a lower wire resistance). Standing waves do not in principle use 'power' at all and certainly do not dissipate energy that otherwise would be radiated. They require a signal to be applied to the transmission line but, whether the power is radiated at the other end or the signal merely meets a mismatch, say an open circuit, the standing wave does not affect, or need to use, any of the power that leaves the other end. Indeed they work just as well if no power whatever is used, as in the open circuit case. -- Percy Picacity |
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