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#1
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Hello,
may I ask the gurus a question please. What does a SWR meter actually display? effective power reactive power apparent power What does it display in the 1 : 1 case with optimal impedance matching between transmitter, cable and antenna, I guess it's effective power, but what does it display when matching is off, say, 1 : 5 or even worse, when the mismatch SWR is 1 : 10 or greater? There are two pointers in the instrument, forward and reverse, how do they add up? Why do forward power and reverse power both increase in their values when the antenna is strongly mismatched, but the displayed SWR remains the same? Please elaborate a little on the answers for a beginner like me. Thank you, w. |
#2
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Hello,
may I ask the gurus a question please. What does a SWR meter actually display? effective power reactive power apparent power What does it display in the 1 : 1 case with optimal impedance matching between transmitter, cable and antenna, I guess it's effective power, but what does it display when matching is off, say, 1 : 5 or even worse, when the mismatch SWR is 1 : 10 or greater? There are two pointers in the instrument, forward and reverse, how do they add up? Why do forward power and reverse power both increase in their values when the antenna is strongly mismatched, but the displayed SWR remains the same? http://en.wikipedia.org/wiki/SWR_meter gives a decent starting view of how a typical SWR meter works. To a first approximation: an SWR meter is measuring the magnitude of the forward wave (transmitter - antenna) and reverse wave (antenna - transmitter) RF. The latter (the reverse wave) is usually a portion of the forward wave which has been reflected back towards the transmitter when it encountered an impedance change. Again, to a first approximation, the "effective" power being transmitted is equal to the power in the forward wave *minus* the power in the reverse wave. So, you don't want to "add up" the two powers you see displayed... you want to subtract one from the other, to see what's actually being radiated. This is only an approximation due to the presence of losses in the transmission line, between the SWR meter and the antenna. If there's enough loss in the transmission line, the reflected wave will be mostly dissipated in the line as heat... little of it will reach the SWR meter. In this case, even if there's a horrible mismatch at the antenna (e.g. the antenna is open or shorted) the SWR meter won't see a significant reflected wave, and will indicate a good match (close to 1:1). |
#3
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Helmut Wabnig [email protected] --- -.dotat wrote:
Hello, may I ask the gurus a question please. What does a SWR meter actually display? effective power reactive power apparent power What does it display in the 1 : 1 case with optimal impedance matching between transmitter, cable and antenna, I guess it's effective power, but what does it display when matching is off, say, 1 : 5 or even worse, when the mismatch SWR is 1 : 10 or greater? There are two pointers in the instrument, forward and reverse, how do they add up? Why do forward power and reverse power both increase in their values when the antenna is strongly mismatched, but the displayed SWR remains the same? Please elaborate a little on the answers for a beginner like me. Thank you, w. SWR (Standing Wave Ratio) is a ratio so it is independant of absolute levels. http://en.wikipedia.org/wiki/Standing_wave_ratio As for what is diplayed, it depends on how the maker calibrated the meter as most meters are acutally measuring a voltage across a given resistance. Usually it is in average power. One meter I have can be switched between average and peak. You have to look at the meter specs to know for any given meter. -- Jim Pennino |
#4
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El 12-11-14 21:51, Helmut Wabnig escribió:
Hello, may I ask the gurus a question please. What does a SWR meter actually display? effective power reactive power apparent power What does it display in the 1 : 1 case with optimal impedance matching between transmitter, cable and antenna, I guess it's effective power, but what does it display when matching is off, say, 1 : 5 or even worse, when the mismatch SWR is 1 : 10 or greater? There are two pointers in the instrument, forward and reverse, how do they add up? Why do forward power and reverse power both increase in their values when the antenna is strongly mismatched, but the displayed SWR remains the same? Please elaborate a little on the answers for a beginner like me. Thank you, w. Most VSWR measuring instruments actually measure the modulus of reflection coefficient ( |RC| ). Voltage reflection coefficient (RC) = ratio between reflected voltage wave and forward voltage wave. As sinewaves have an amplitude and phase, RC has an amplitude and a phase also. To find the power you need: Forward power = (forward voltage)^2/Zref reflected power = (reverse voltage)^2/Zref Net power = Pfwd - Pref Where Zref is mostly the transmission line impedance (for example 50 Ohms) You can calculate RC from the reference impedance (for example 50 Ohms) and the load impedance (use complex calculus). RC = (Zload - Zref)/(Zload + Zref). The scale of the instrument does the VSWR calculation based on. VSWR = (1+|RC|)/(1-|RC|). |RC| = modulus or amplitude of reflection coefficient. Most amateur VSWR indicators need a calibration where you need to set the forward reading at the end of the scale. Changing the switch from FWD to REF shows the VSWR. Why VSWR? one can measure VSWR directly by probing the voltage along a slotted transmission line (or slotted wave guide), and that was used in the past. I still use it during courses on transmission lines or lectures. VSWR = (max amplitude along line) / (min amplitude along line). An instrument displaying VSWR only, says nothing about the absolute forward and reflected power, you only know the ratio. An example: VSWR = 2. Using the formulas this translates to |RC| = 0.3333, so the reflected wave amplitude is 33.3% of the forward wave amplitude. This means that the ratio between reverse and forward power is Prev/Pfwd = 0.333^2/1^2 = 0.11 (11%) Therefore many instuments also show power loss, for example VSWR = 2 shows 11% also. in case of VSWR = 1, |RC| = 0, so there is no reverse traveling wave, hence no reverse power. The net power equals the forward power. The amplitude along the line is constant (assuming zero attenuation). Based on VSWR alone (not knowing the position of max voltage along the line), you can't calculate the impedance at the position of the instrument. For example both 25 and 100 Ohms show VSWR=2 on an instrument with 50 Ohms reference impedance. there are infinite impedances that have VSWR=2. You can see reflection as a form om reactive power. In a well terminated cable (Zref = Zload, VSWR=1), voltage and current are in phase at al positions along the cable. In case of reflection, voltage and current are no long in phase along the line (except for certain positions). If you want to transmit 50W via a 50 Ohms line, the line will carry 50V and 1A everywere along the line (both in time phase). If that same line carries 50W net power, but the VSWR of the load is 10, then you may find positions where the voltage is 158V and positions where the current is 3.16A. The positions of maximum current are in between positions of maximum voltage. At many places, current and voltage are not in phase. Pfwd = 151W, Pref = 101W You can imagine that in the VSWR=10 situation the transmission line loss is more (because of the higher voltage and current). Change of forward power because of a change in VSWR is because of the source and has therefore nothing to do with the instrument. A source that has a real resistive output impedance equal to the reference impedance should display constant forward power independent of load impedance Hopefully avoiding a long thread: An RF power amplifier should deliver the stated power to a specified load, it does not say that the output impedance equals that specified load. In other words, an RF power amplifier generally doesn't have an internal impedance of 50 Ohms. In that case some part of the reflected power bounces at the amplifier-cable interface and goes towards the VSWR instrument and interferes with the amplifier's original forward power. -- Wim PA3DJS Please remove abc first in case of PM |
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