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Ralph Mowery wrote: "rickman" wrote in message ... Why do you ignore it when it says Zo is the impedance of the transmission line and not the source? I don't; The transmission line in this case IS the source. No, the source is the source. Even if you wish to consider transmission line as the source in some example, the page clearly says Zo is the impedance of the transmission line, without any context where you can say it is a source or a load. https://en.wikipedia.org/wiki/Charac...nsmission_line _model The SWR in a system, any kind of system, is measured at a point in a system. You mean a system that includes a source, a transmission line and a load? One side of that point is the source and the other side of that point is the load. It also does not matter which side you declare the source and which side you declare the load. In that case the antenna is Zo? I don't think so. A 50 Ohm source and a 100 Ohm load has the same SWR as a 100 Ohm source and a 50 Ohm load. By convention the load side is normally taken as the side which, when the system is powered, the power is desired to be dissipated. I don't know why you dig your heels in on every little point. Sometimes you are just wrong and need to acknowledge that so the discussion can move on. Zo (or Z0) is used to represent the characteristic impedance of a transmission line. Zs (or Zsource) is used for the source. ZL (or Zload) is used for the load. Read the wiki quote above and the many other *clear* examples. -- Rick I think that is his problem. The source does not mater . It is just there to provide power to the load. The swr is stated TOWARD the SOURCE. It does not have anything to do with the actual source impedance. As someone said eairler you measure the swr, then put any value resistor in parallel with the transmitter (source) and measuer the swr. It will still be the same if nothing else changes. Jimp just can not seem to get it in his head the impedance of the transmitter (source) does not matter. It seems to me he thinks the coax is the source. I just don't see the coax generating any power outside of a very minute random power depending on the temperature that would be in the micro watts or less that is way out of the scope of the swr discussion. Nope. SWR is a measure of the impedance match at a point in a system. No it is not. You don't get standing waves on 10mm of wire. (At HF anyway). It is a property of a driven transmission line and depends on the network at the far end. It is directional and does *not* depend on the impedance of the source. (If you put a signal source at the far end, in parallel with the existing load or replacing it, then you would get a potentially quite different SWR due to the impedance of what was the source. Because you would not have matched the source impedance to the tansmission line impedance. In the general case, a network which matches the impedance looking into the tansmission line to the impedance desired by the source for a satisfactory working point willl *not* match the source impadance to the transmission line characteristic impedance. In the general case it will be impossible to match impedances in both directions, and in pracitce we don't even try. It does not matter what the physical ends are. One end could be an unbalanced to balanced transformation network and the other end a length of parallel transmission line. If the impedance of the tranmitter does not matter, than connect YOUR transmitter to a length of 95 Ohm coax which is terminated in a square loop with an impedance of 110 Ohms. What is the SWR at the point between the coax and loop? What is the source and what is the load? What is the SWR at the point beteen the transmitter and the coax? What is the source and what is the load? -- Roger Hayter |
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