Roy Lewallen wrote:
W5DXP wrote: wrote: Connect a length of 50 Ohm transmission line to a 9 Volt battery and wait for the transient to die: Hint: The Z0 of a piece of coax at DC is NOT 50 ohms. It is for the time it takes for the transient to die. Did you not see where he said "wait for the transient to die"? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
W5DXP wrote:
Instantaneous power is useless if an understanding is desired. A number of texts, in presenting analyses that enhance understanding, use both instantaneous power and the instantaneous value of the Poynting vector as part of the explanation. Perhaps you mean that it adds unwelcome complexity to your simplified analysis? I agree with Hecht and all my other references. Kraus, Jasik, Balanis, Hecht, Ramo & Whinnery all agree that dealing with instantaneous power is a waste of time. Instantaneous power is essentially meaningless since the definition of power requires a length of time. There is simply no such thing as instantaneous power. Instantaneous power is defined in the first half dozen books I pulled from my bookshelf. They we Physics: Weidner & Sells Circuit analysis: Pearson & Maler Network analysis: Van Valkenburg ("Power, instantaneous" is even indexed) Electromagnetics: Johnk, Holt, Kraus You certainly have a lot to straighten us out on in your forthcoming paper! Power is always the energy passing a point during a slot of time. Zero energy passes a point in dt of time as delta-t approaches zero, by definition. By exactly the same reasoning, instantaneous current can't exist, since it has the same relationship to charge as power does to energy. By your argument, we should all through away that "useless" and "boring" analysis using time-varying currents, and deal only with average currents. The new math indeed. . . . Roy Lewallen, W7EL |
W5DXP wrote:
. . . This is obviously a diversionary tactic. Instantaneous power is essentially meaningless according to all my references and I have a bunch of them. Would you care to provide a reference that seriously deals with instantaneous power in transmission lines? It was just day before yesterday I posted just such a reference (Magid). But you seemingly rejected it out of hand as being probably wrong without making an effort to even look at it. So what's the point in providing you with references? Roy Lewallen, W7EL |
W5DXP wrote:
Roy Lewallen wrote: p(t) = v(t) * i(t). Period. No phase, no vectors, no cross products. Millions of power engineers have been taught that V*I*cos(theta) is power. Are you disagreeing with that teaching? Yes. p(t) = v(t) * i(t) is virtually worthless to a power engineer since a generator is a giant heat sink. Most of my references say that instantaneous power is virtually meaningless for RF and optics work. Can you provide a reference that extols the virtues of instantaneous power applied to RF? Can you list any benefit for considering instantaneous RF power? I've addressed the remainder of this in another posting, except for the last question. The last question has been the subject of many postings I've made over the past several months. If your memory needs refreshing, a Google search should locate them quite easily. Roy Lewallen, W7EL |
Roy Lewallen wrote:
. . . By your argument, we should all through away that "useless" . . . That's "throw", not "through", of course. I really do know better. Roy Lewallen, W7EL |
Ian'
I don't see from what what Reg said that this should have been unloaded on him in such a way. I sure hope the " establishment" or "cabal" as I call them don't follow you and pile it on . Seems to me that Reg is a giver not a taker as far as ham radio is concerned, and just as much as a asset to this group as those wish to fire off a shot at the first oportunity to give dutch courage to all those that wil follow. Now you can stick the label on me also, audacity was it? After all I did say "cabal" ? What really surprises me is that you have not noticed over the years how many people have been attacked so wickedly on this newsgroup by people that infer that "all is known" to which you whimsically referred to. The fact is that is if this were true a thread would never exceed five postings after a particular expert had posted. I can only imagine that Reg has not swallowed all you have said and thus has raised your ire such that you have lost your cool Art A real XG "Ian White, G3SEK" wrote in message ... Reg Edwards wrote: It should not be forgotten this newsgroup is primarily intended for exchange of information between radio amateurs. It is fairly clear there's a number of retired professional engineers who are also radio amateurs who frequent this newsgroup. Fine! I'm a long-retired engineer myself. There are also a sprinkling of engineers who are professionals in that they are paid for their services of some sort or another. There are some people, perhaps with some small historical justification, have the audacity to consider themselves to form an informal Establishment. Reg, this "Establishment" is something that you just invented. The audacity is yours. Yes, there are people on this newsgroup who agree on lots of technical points. And yes, they are often quite insistent about it. (At this point, I'll change to "we", because I am one of the people we're talking about. And despite his chosen role as maverick, provocateur and general gadly, so too is Reg ;-) Nobody knows everything, but each of us has been around for long enough to have covered most of the same territory, and to have made all the common mistakes. But we've also been around long enough - and been persistent enough - to have come out the other end with some correct answers. (Here comes Philosophy of Science in two paragraphs. Please don't give me a hard time over the things I'm going to leave out.) What's a correct answer? One that accurately describes external, physical, observable, measurable reality, as nearly as we can measure it or need to know. People who take that view are not too comfortable with approximations and half-truths, because sooner or later we're going to be caught out by a new situation where the "nearly correct" answers don't work any more. In the long run, it's simply easier to work out a correct answer that can be trusted. Each of the people Reg is talking about (in fact, especially Reg himself) worked out many of those answers for ourselves, way before we met on the Internet. But when we did meet, it wasn't at all surprising to find ourselves agreeing on so much. That's because all correct answers are describing the same physical reality, so they *have* to agree. The only allowable difference is to choose different viewpoints upon the same reality; but if they are correct, all those alternative viewpoints still *must* be consistent with one another - they must *not* contradict in even the smallest detail (unless it's acknowledged to involve an approximation). Those rules are rigid, but nobody made them - reality did. The only available choice is whether to accept them and stick by them, or to sometimes let them slide. I choose to accept them, as much as I possibly can, because it's actually easier in the long run. If someone else's better logic forces me to re-evaluate, that's really not a problem because I'm better-off than before. Yes, people like that can be rather insistent! But it's not because we want our personal faiths or beliefs to prevail - it's not about us at all. It's because we want external, physical, observable, measurable reality to prevail. Cue for somebody to pipe up about quantum physics, Heisenberg, uncertainty and all that. There are certain areas of science and engineering where these apply and even dominate, and mean that certain things are fundamentally un-knowable. Antennas, transmission lines and electronic engineering are *not* one of those areas. It's an excellent approximation to say that everything in these areas of physics and engineering is fixed and "real", and - if we work hard enough at it - knowable. The exceptions, such as noise and the internal physics of semiconductors, can all be treated by engineers as macro-scale observables. A good example is the tunnel diode, which relies on a probabilistic quantum phenomenon that just can't happen according to classical science... but at the engineering level you can still rely on the device data. You don't see "Probably" stamped on each page. Cue now for someone else to pipe up "But we don't know everything yet." No, we don't... but for every genuine new discovery, there are billions of mistakes, experimental and logical errors. When straightened out, these simply confirm that what we already knew is correct. You'd better learn to trust that body of existing knowledge much more that you trust yourself! I certainly do, and again life is easier as a result. The good thing about the Internet is that we can all learn much faster than before. I certainly have. The bad thing is that we no longer make our mistakes in private. Stuff that used to end up as crumpled balls of paper, to be thought about more clearly tomorrow, is now being published every night to be read by thousands of people and archived forevermore. It's becoming harder and harder to identify the good information among all the rest. To anyone who has already made those same mistakes, it seems such a waste to see people wandering off and doing it all over again. It's very hard to stand by and let it happen... |
"J. McLaughlin" wrote
The issue of the max. value of the magnitude of the reflection coefficient came up in our student mess. It was shown in lab that it must approach the square root of 5, which is close to 2.41. ================================ You don't need a lab. All you need is a pencil and the back of a cigarette packet. Theoretical Max possible value = 1+Sqrt(2) exactly = 2.4142136 . . . . . Can't imagine where you get 5 from. It occurs when line Zo = Ro - jXo has an angle of -45 degrees, ie., when Xo = -Ro, and when the line is terminated in an inductive reactance of +jXo. ---- Reg. |
On Tue, 19 Aug 2003 03:06:15 -0700, Roy Lewallen
wrote: Thanks for the analogy. One can mathematically and conceptually conceive two opposite-traveling waves that add up to the observed standing wave, and that's fine. The problem comes with assigning power or energy to the waves. Then you run into the problem of how one wave got the energy over the barrier into the pocket and the other wave took the same amount back out, without transfering any air molecules across the barrier in the process. The average power analysis looks to me something like this. Suppose you have two batteries each with exactly 2 volts potential and zero internal resistance, with a 2 ohm resistor connected between their positive terminals. The negative terminals are connected together. You replace the battery on the left with a short (turning it off), and observe that the current through the resistor is one amp to the left. Then you hook the left hand battery back up and turn the right hand battery "off" by replacing it with a short. You observe that there's one amp now flowing through the resistor to the right. Finally, turn both batteries "on" by putting them both in place. You can use superposition to conclude, correctly, that there's zero current flowing in the resistor. But it's silly to insist that there's a forward two watt "power wave" flowing to the right, and another two watt wave flowing to the left. You subtract one from the other and, sure enough, get zero. But are the "power waves" real? Studying and analyzing these imaginary waves is surely a lot more interesting than simply looking at the circuit and noting that the "boring" (as Cecil calls it) net power is zero. But aren't you studying ghosts? Interesting question, isn't it? It seems to me that this is a class of problem that is succeptable to solution by several approaches, classical network theory, or transmission line theory and perhaps others. Identifying the solution that best matches physically observable phenominia isn't always obvious. Applying Ockham's Razor (spell it any of the alternative ways you wish) one might prefer the simpilist theory that produces correct results. But, to some extent the artifical conditions necessary in such a statement are responsible for some of difficulty. I = E/R but as as you make R zero, you have introduced a singularity into Ohm's law, so in some sense I isn't determinable. There is also a finite propagation time for current flow across the resistor, (and through the battery, for that matter) and that might argue for a transmission line solution. It also reminds me a bit of the question posed in electromagnetic theory class. You've probably seen it before as well. You have two wires going through the room you are in. With a clamp-on ammeter, you measure 1 amp in each wire, in opposite directions. With a volt meter, you measure 1,000 volts between the two wires. When asked to calculate the power flow, you answer 1,000 watts, being 1KV * 1A. However, the actual circuit is 4 wires, and you only see two in the room. Two loops of 1 volt batteries with a 1 ohm series resistance, with the two loops bridged via a 1KV source. No current flow from the 1 KV battery and the total power is 2 watts, being 1 watt in each loop. As I recall, the only way to get the correct answer is to properly determine the Poynting vector, but it's damn near 40 years since I looked at it. 1 ohm A B 1 ohm +---WWW--------+ +---WWW--------+ | | | | | | | | + + + = 1 volt battery | = | + | | | | +--------------+--+||---+--------------+ A B 1KV battery You can only see the wires at A-A and B-B. Jack K8ZOA Even more risky is adding the things. This time hook two one volt batteries in series with the 2 ohm resistor and energize one at a time. With the upper one on and the lower one "off" (replaced with a short) you get 1/2 amp. You've got a "power wave" of I^2 * R = 1/2 watt. Turn the lower one on and the upper one "off", and you get another "power wave" of 1/2 watt, in the same direction. Turn them both on, and you have a power flow of, um, 2 watts. Welcome to the new math. Roy Lewallen, W7EL Sounds like a variation on the old two identical caps with equal charge are shorted together. Where does the excess energy go? Jack Smith wrote: Roy: Interesting point and I don't recall reading or hearing it elsewhere. The following is dashed off without fully thinking it through, so no warranty on its accuracy. If you think of a sound wave (longitudinal transmission, of course) in a lossless acoustic transmission line terminated with a short, the individual air molecules within each 1/4 wave section are likewise trapped since at the 1/4 wave points there is zero sound pressure. This may be a useful analogy for the electromagnetic transverse propagating T-line. Jack K8ZOA |
W5DXP wrote:
wrote: I see your confusion and apologize for not being completely clear. When I say P = V * I, P, V and I are instantaneous values, the only ones worth exploring if an understanding is desired. Instantaneous power is useless if an understanding is desired. I agree with Hecht and all my other references. Kraus, Jasik, Balanis, Hecht, Ramo & Whinnery all agree that dealing with instantaneous power is a waste of time. Instantaneous power is essentially meaningless since the definition of power requires a length of time. There is simply no such thing as instantaneous power. May I recommend differentiation: In the limit, as t approaches 0.... Very useful results can be obtained with this technique. Power is always the energy passing a point during a slot of time. Zero energy passes a point in dt of time as delta-t approaches zero, by definition. Well, if you do a bit of fudging you can always make it work. But I do not observe these fudge terms in the expressions related to forward and reverse power in transmission lines. Then you haven't read Dr. Best's QEX article. The interference is there and takes the form of 2*Sqrt(P1)*Sqrt(P2) for 100% constructive interference. Of circuit theory I have a reasonable grasp, optics I leave to others. Too bad. The field of optics has already solved the problems with which you are wrestling. Take a look at this web page to figure out how Z0- matching works. http://www.mellesgriot.com/products/optics/oc_2_1.htm As mentioned previously: stored in the line and moving back and forth between quarter wave boundaries. Mentioned, but not explained. How does the energy's momentum change direction in a constant Z0 environment? What causes the back and forth movement? Back in basic circuit theory, some years ago, it was permitted to short points of equal voltage and open conductors with no current. Has this changed in the intervening years? Ahhhh, I see your confusion. Circuit theory and transmission line theory are not the same thing. Many have tried to mix the two models and fallen on their faces. Transmission line theory is simply more complicated than basic circuit theory. Well, slightly more. The capacitances and inductances are spatially distributed. Should make the math a bit more complicated but hasn't introduced anything new. If you don't believe it, replace a transmission line with ghosting with an equivalent circuit - the ghosting disappears. Are they really equivalent? Well if the ghosting disappears, it was not the 'equivalent circuit'. No surprises there. Because the observed voltages and currents are the same. The circuit has been replaced by one which is indistinguishable from the first. BS! I can certainly distinguish between a short and a non-shorted transmission line. Please try again. Just to recap, the experiment was: a matched source connected to an open transmission line. After the source is turned on (and a brief wait for settling), measure any voltage or current you desire at any point on the line. I short the points of zero voltage and cut the points with zero current. You can now remeasure any current or voltage at any points you choose to tell me whether the shorts or cuts are in or out. Since you can not tell the difference, the circuit with cuts and opens is identical to the one without. You have gone from 100% transmission of waves to 100% reflection of waves. An intriguing assertion, but one which can not be demonstrated through any observations made on the circuit. Of course it can by observing ghosting in a TV signal. With the line shorted, there is no ghosting. With the line not shorted, there is ghosting. Why is that so difficult to understand? We were, I thought, discussing an open transmission line, not one carrying a TV signal. You have changed the experiment. I am not sure why you are looking so hard for reflections. I am not attempting to claim that there are any. I simply claim that no energy can cross the boundaries because the current or voltage is always 0. In the real world, if no RF energy crosses a boundary, then that energy is reflected since it cannot stand still. Of course, the supernatural world is an entirely different matter. Basic electriciy. This says nothing about the presence or absence of reflections or whether there is a mechanism to prevent the energy crossing the boundary or it just happens through the dynamics of the distributed capacitance and inductance. Unfortunately, this is beyond the ability of basic electricity to handle. It takes the wave reflection model (or quantum physics) Oh, I don't think we need quantum physics to understand energy distributions in ideal transmission lines. Let's not scare off the neophytes. to handle it. Einstein said a model should be as simple as possible, but not too simple. Once again, you seem to be trying to force reality to obey your model instead of vice versa. Oh, I fully understand what a 'directional watt' meter will indicate. Then why are you so confused? :-) May I suggest that you perform the same experiment with a real instantaneous watt meter: This is obviously a diversionary tactic. Not at all. A much better understanding will be had if both the indications of real wattmeters and 'directional watt' meters are understood. Limiting yourself to only one instrument limits the opportunity for full understanding. Instantaneous power is essentially meaningless according to all my references and I have a bunch of them. Would you care to provide a reference that seriously deals with instantaneous power in transmission lines? It's not so hard that you need a text book. V, I, cos(theta) and a little thinking will suffice. Draw a sine wave for the voltage and one for the current shifted by 90 degrees. Compute the power (which will be a new sine wave at double the frequency). Observe that the power goes positive and negative representing forward and reverse energy flow. At any instance (at a single point) the power is either positive or negative. Energy is either flowing in one direction or the other at any given instance. And remember that at any point where the voltage or current is always 0, no energy is ever flowing. ....Keith |
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