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-   -   Current in loading coil, EZNEC - helix (https://www.radiobanter.com/antenna/2449-current-loading-coil-eznec-helix.html)

Roy Lewallen October 21st 04 02:56 AM

Thanks for the correction regarding proximity effect. In that case,
Reg's program should report the loss more accurately than EZNEC when the
turns are very closely spaced.

Yes, indeed, EZNEC does account for the capacitance -- it comes about
from the coupling of fields between turns, which is at the heart of the
fundamental NEC-2 electromagnetic field calculations. As I said, the
self-resonant frequency reported by EZNEC is pretty close to that
calculated by your program.

Roy Lewallen, W7EL

Reg Edwards wrote:
EZNEC doesn't model proximity effect (significant only when the
turns are pretty closely spaced) but I don't think Reg's program
includes proximity effect, either.

Roy Lewallen, W7EL



======================================

Yes it does!

But you can forget it. It doesn't matter except when calculating efficiency.
It has no affect on how the thing works which is what you are all
so-aggressively fighting about. You'll soon be using assault weapons.

Program "Loadcoil" also includes the ALL-IMPORTANT COIL CAPACITANCE (which I
suspect Eznec does not - I never use it) - the existence of which the
whole set of you block-heads, so-called electrical engineers, appear to be
entirely ignorant.

We ARE dealing with alternating currents.

Oh Boy - I enjoyed typing that! ;o)
----
Reg, G4FGQ



Tom Donaly October 21st 04 05:32 AM

Jim Kelley wrote:


Tom Donaly wrote:

Jim Kelley wrote:

Tom Donaly wrote:

Next, Cecil, you're going to be talking about a "current gradient"
and a "scalar current field." Here's a question for you, Cecil, and
Richard Harrison, and Yuri, too: how do you take the gradient of
the current at a point on a transmission line, and, if were possible
to do so, what is the physical significance of the result?
73,
Tom Donaly, KA6RUH




The standing wave current profile along, for example, a quarter wave
radiator is a cosine function. The gradient then would be the
derivative of the cosine function which is a -sine function.

73, ac6xg


Jim,
current, in a wire, is the total current density integrated across
a cross section of the wire. It's a vector, as is the current density.
Now tell me, how do you take the gradient of a vector? David K. Cheng,
in his book Field and Wave Electromagnetics, defines the gradient
operation this way: "We define the vector that represents both the
magnitude and the direction of the maximum space rate of increase
of a scalar as the gradient of that scalar." He wrote "scalar,"
not "vector," Jim. You and the rest of the boys are acting as if
current had magnitude but no direction, whereas it has both.
73,
Tom Donaly, KA6RUH



Not sure why you don't like gradients, Tom. I'm sure Mr. Cheng is
undoubtedly correct, but I'm just as sure he didn't intend that sentence
as any sort of definition of the term "gradient".


Actually, he did. It's the accepted definition of the term in
electromagnetics. You and Cecil are using the term in a more
general fashion which you've made up for the purpose. It doesn't
make much sense in an elecromagnetic setting. Similarly, Yuri,
Richard and Cecil made up a very loose term "current drop" for
a change in current at two ends of a coil. That was misleading
and wrong if they were trying to convey something about the
electromagnetics of a coil, which they were. I've seen you fellows
pick each other to death over trivia time and again. It's time
you paid attention to what you write.

That's something you
have apparently read into it. The gradient in our case (since you
proposed the question) would be expressed as the superposition of
forward and reverse currents, with magnitude and phase (or direction if
you prefer) written as a function of either position or angle *along*
the radiator. It's nothing fancy. Honest. It's simply the rate of
change of current as a function of position. The gradient across the
radiator at any given point along the radiator could then be determined
using some additional parameters - if someone were really that
interested in it (which I'm not).

73, ac6xg


How could the gradient be in your case if I proposed the
question?
73,
Tom Donaly, KA6RUH

Cecil Moore October 21st 04 05:38 AM

Tom Donaly wrote:
However, the
term "current drop" as used by Yuri was wrong. There is no place for
it in electromagnetic theory, and if you had known enough theory to
understand that, you wouldn't have answered as you did.


I've been in Las Vegas for ten days and didn't see Yuri's posting.
All I know is there is a "current drop" from the current maximum
point to the current minimum point on a transmission line with
reflections. So exactly how did Yuri use "current drop"? If it is
through a mobile loading coil, I explain exactly how that happens
on my web page through the superposition of the forward and reflected
currents. For the typical base-loaded or center-loaded shortened
mobile antenna, If+Ir at one end of the coil is NOT equal to If+Ir
at the other end of the coil even if the two currents through the
coil are of constant magnitudes. I have explained that multiple times
here with no disagreement.

For typical standing-wave antennas with loading coils:
The forward current through a loading coil is reasonably constant.
The reflected current through a loading coil is reasonably constant.

The two above facts are obeying Kirchhoff's laws.

The total current is the sum of the forward current and the reflected
current and results in a cosine function standing wave on the antenna.
The differing phases of forward current and reflected current is what
causes the variation in the total current, i.e. the current drop.

The current drop in a standing wave antenna is similar to the current
drop in a section of transmission line with reflections. The governing
equations can be found in any EM textbook and for lossless situations
are of the form:

Itot = If*e^-yz - Ir*e^+yz

Losses to radiation or I^2*R add another couple of e^-2ad (attenuation)
terms.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 21st 04 05:40 AM

Tom Donaly wrote:
Besides, you missed the point again.


Sorry, I've been out of town for 10 days and haven't read
all the postings. So please bring me up to date. Exactly
what is "the point"?
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 21st 04 05:44 AM

Tom Donaly wrote:
you've hit the nail squarely on the head. The validity of
the whole argument boils down to whether or not you can safely neglect
the effects of the physical dimensions of the inductor on the behavior
of the antenna. It looks to me as if you can, but some of the other
fellows on this newsgroup seem to be as much interested in
characterizing Tom Rauch as a rat as they are in verifying some
antenna effects due to the properties of real loading coils.


You guys have completely missed the point. The argument is not about
the behavior of the antenna. The original argument is/was about the
current in a real-world antenna loading coil. The behavior of the
antenna is irrelevant to that original argument.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 21st 04 05:50 AM

Tom Donaly wrote:
I
don't agree with the term "current drop" because, even in a transmission
line, current, or more properly, current density, doesn't act like a
potential of any sort to which you could ascribe a "drop."


Webster defines "drop" as "to become less". Seems to me, the current
"becomes less" as one moves the measurement point from a current loop
to a current node on a standing-wave antenna.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 21st 04 06:13 AM

Tom Donaly wrote:
current, in a wire, is the total current density integrated across
a cross section of the wire. It's a vector, ...


From "Fields and Waves in Communications Electronics", by Ramo, Whinnery,
& Van Duzer, page 239: "It must be recognized that the symbols in the
equations of this article have a *different* meaning from the same symbols
used in Art. 4.06. There they represented the instantaneous values of the
indicated *vector* and scalar quantities. Here they represent the complex
multipliers of e^jwt, giving the in-phase and out-of-phase parts with
respect to the chosen reference. The complex scalar quantities are commonly
referred to as *phasors*, ..."

From the IEEE Dictionary: "The phase angle of a phasor should not be
confused with the space angle of a vector."

You are obviously confusing vectors and phasors.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 21st 04 06:18 AM

Richard Clark wrote:
There is no such Kirchoff law of two separate points of current, that
is Kirchoff's voltage law. A point (singular, the only component of
Kirchhoff's current law) has no dimension, any departure from this
necessarily excludes itself from strict Kirchhoffian analysis.


Yes, you are starting to get it. Point inductances don't exist
in reality.
--
73, Cecil http://www.qsl.net/w5dxp


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Richard Clark October 21st 04 07:31 AM

On Thu, 21 Oct 2004 00:18:59 -0500, Cecil Moore
wrote:
starting to get it

took you a long time too.

Richard Clark October 21st 04 07:35 AM

On Wed, 20 Oct 2004 23:44:01 -0500, Cecil Moore
wrote:
behavior of the antenna is irrelevant

sour grapes :-)

Tom Donaly October 21st 04 03:18 PM

Cecil Moore wrote:
Tom Donaly wrote:

current, in a wire, is the total current density integrated across
a cross section of the wire. It's a vector, ...



From "Fields and Waves in Communications Electronics", by Ramo, Whinnery,
& Van Duzer, page 239: "It must be recognized that the symbols in the
equations of this article have a *different* meaning from the same symbols
used in Art. 4.06. There they represented the instantaneous values of the
indicated *vector* and scalar quantities. Here they represent the complex
multipliers of e^jwt, giving the in-phase and out-of-phase parts with
respect to the chosen reference. The complex scalar quantities are commonly
referred to as *phasors*, ..."

From the IEEE Dictionary: "The phase angle of a phasor should not be
confused with the space angle of a vector."

You are obviously confusing vectors and phasors.
--
73, Cecil http://www.qsl.net/w5dxp


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You're just digging the hole deeper, Cecil. I know you think you can use
the simplifications of transmission line theory to explain everything
in electromagnetics. Reg seems to think that's a valid way of doing
things, too. If it were true, it would certainly make life easier for
those poor souls who have to study Maxwell's equations in colleges
throughout the world. Just think, no more vector calculus for engineers!
From what I've read on this group the past few days, many engineers
don't learn it anyway, so why not just dumb things down to
your level? Maybe you should write a letter to Texas A&M telling them
they don't have to teach it any more. (If they still do, that is. Some
colleges have dumbed themselves down considerably in the past 20 years.)
73,
Tom Donaly, KA6RUH

Cecil Moore October 21st 04 04:02 PM

Richard Clark wrote:
Cecil Moore wrote:
behavior of the antenna is irrelevant


sour grapes :-)


Yes, from you guys. "OK, I admit I was wrong, but that original
argument didn't matter anyway." :-)


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Cecil Moore October 21st 04 04:23 PM

Tom Donaly wrote:
You're just digging the hole deeper, Cecil. I know you think you can use
the simplifications of transmission line theory to explain everything
in electromagnetics.


The transmission line model is more complicated than the circuit
model and works for transmission lines, including antennas, which
are single-wire transmission lines. Your overly simplified circuit
model doesn't work for transmission lines or for antennas. That's
what got you (and others) into trouble. All you guys can do now
to try to save face is sandbag and divert the issue.
--
73, Cecil http://www.qsl.net/w5dxp


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Richard Harrison October 21st 04 05:29 PM

Tom Donaly wrote:
"I know you think you can use the simplification of transmission line
theory to explain everything in electromagnetics. Reg seems to think
that`s a valid way of doing things, too."

I had a graduate course in Maxwell`s equations, but had a long rewarding
career without using Maxwell directly.

Reg is an advocate of Oliver Heaviside`s work based on Maxwell. Nothing
wrong with that.

In his 1950 work "Antennas", Kraus has this to say about Maxwell`s
equations:

"Maxwell`s equations are summarized in the tables. The first table gives
Maxwell`s equations in differential form and the second table in
intergral form. The equations are stated for the general case,
free-space case, harmonic-variation case, steady case (static fields but
with conduction currents), and static case (static fields with no
currents). In the table giving the integral form, the equivalence is
also indicated between the various equations and the electrical
potential or emf, the magnetic potential or mmf, the electric current,
the electric flux, and then magnetic flux.

Many texts do very well with no mention of Maxwell despite his
contributions to electromagnetics. That`s too bad, but that`s the way it
is.

Best regards, Richard Harrison, KB5WZI


Jim Kelley October 21st 04 05:39 PM



Tom Donaly wrote:
Jim Kelley wrote:
Not sure why you don't like gradients, Tom. I'm sure Mr. Cheng is
undoubtedly correct, but I'm just as sure he didn't intend that
sentence as any sort of definition of the term "gradient".



Actually, he did. It's the accepted definition of the term in
electromagnetics. You and Cecil are using the term in a more
general fashion which you've made up for the purpose. It doesn't
make much sense in an elecromagnetic setting. Similarly, Yuri,
Richard and Cecil made up a very loose term "current drop" for
a change in current at two ends of a coil. That was misleading
and wrong if they were trying to convey something about the
electromagnetics of a coil, which they were. I've seen you fellows
pick each other to death over trivia time and again. It's time
you paid attention to what you write.

That's something you

have apparently read into it. The gradient in our case (since you
proposed the question) would be expressed as the superposition of
forward and reverse currents, with magnitude and phase (or direction
if you prefer) written as a function of either position or angle
*along* the radiator. It's nothing fancy. Honest. It's simply the
rate of change of current as a function of position. The gradient
across the radiator at any given point along the radiator could then
be determined using some additional parameters - if someone were
really that interested in it (which I'm not).

73, ac6xg


How could the gradient be in your case if I proposed the
question?
73,
Tom Donaly, KA6RUH


Are you trying to make some point? If so, I'd sure like to know what it
is. It appears you're trying to pretend that the gradient (a
mathematical term) in the standing wave current along the length of a
radiator doesn't exist. Why? It's a very simple and straightforward
notion.

73, Jim AC6XG


Tom Donaly October 21st 04 07:52 PM

Jim Kelley wrote:


Tom Donaly wrote:

Jim Kelley wrote:

Not sure why you don't like gradients, Tom. I'm sure Mr. Cheng is
undoubtedly correct, but I'm just as sure he didn't intend that
sentence as any sort of definition of the term "gradient".




Actually, he did. It's the accepted definition of the term in
electromagnetics. You and Cecil are using the term in a more
general fashion which you've made up for the purpose. It doesn't
make much sense in an elecromagnetic setting. Similarly, Yuri,
Richard and Cecil made up a very loose term "current drop" for
a change in current at two ends of a coil. That was misleading
and wrong if they were trying to convey something about the
electromagnetics of a coil, which they were. I've seen you fellows
pick each other to death over trivia time and again. It's time
you paid attention to what you write.

That's something you

have apparently read into it. The gradient in our case (since you
proposed the question) would be expressed as the superposition of
forward and reverse currents, with magnitude and phase (or direction
if you prefer) written as a function of either position or angle
*along* the radiator. It's nothing fancy. Honest. It's simply the
rate of change of current as a function of position. The gradient
across the radiator at any given point along the radiator could then
be determined using some additional parameters - if someone were
really that interested in it (which I'm not).

73, ac6xg


How could the gradient be in your case if I proposed the
question?
73,
Tom Donaly, KA6RUH



Are you trying to make some point? If so, I'd sure like to know what it
is. It appears you're trying to pretend that the gradient (a
mathematical term) in the standing wave current along the length of a
radiator doesn't exist. Why? It's a very simple and straightforward
notion.

73, Jim AC6XG


Keep trying, Jim.
73,
Tom Donaly, KA6RUH

Tom Donaly October 21st 04 07:53 PM

Cecil Moore wrote:

Tom Donaly wrote:

You're just digging the hole deeper, Cecil. I know you think you can use
the simplifications of transmission line theory to explain everything
in electromagnetics.



The transmission line model is more complicated than the circuit
model and works for transmission lines, including antennas, which
are single-wire transmission lines. Your overly simplified circuit
model doesn't work for transmission lines or for antennas. That's
what got you (and others) into trouble. All you guys can do now
to try to save face is sandbag and divert the issue.
--
73, Cecil http://www.qsl.net/w5dxp


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Who said anything about a circuit model?
73,
Tom Donaly, KA6RUH

Jim Kelley October 21st 04 09:19 PM



Tom Donaly wrote:

Jim Kelley wrote:


Keep trying, Jim.
73,
Tom Donaly, KA6RUH


To what end? It's not a controversial issue.

73, Jim AC6XG



Cecil Moore October 21st 04 11:48 PM

Tom Donaly wrote:
Who said anything about a circuit model?


I'm going to present an example, step by step. Please contribute
something technical in response.

It's a simple lossless quarter-wave matching section example.

------50 ohm feedline---+---1/4WL 600 ohm feedline---7200 ohm load
Pfor1=100w-- Pfor2=352w-- 100w
--Pref1=0w --Pref2=252w
Vfor1=70.7v-- Vfor2=460v-- Vload=849v
--Vref1=0v --Vref2=389v
Ifor1=1.414A-- Ifor2=0.766A-- Iload=0.118A
--Iref1=0A --Iref2=0.648A

Vref2 is 180 degrees out of phase with Vfor2 and thus they subtract.

Iref2 is in phase with Ifor2 and thus they add.

The impedance at '+' is (Vfor2-Vref2)/(Ifor2+Ifor1)

The impedance at '+' is (460v-389v)/(0.766A+0.648A) = 70.7V/1.414A = 50 ohms

Note that the impedance seen at the match point is:

Vfor1/Ifor1 = (Vfor2-Vref2)/(Ifor2+Iref2)

So Tom, do you find anything wrong with this network analysis? If so,
please be technically specific. (Sorry, your feelings don't matter.)
--
73, Cecil http://www.qsl.net/w5dxp


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Tom Donaly October 22nd 04 08:59 PM

Cecil Moore wrote:
Tom Donaly wrote:

Who said anything about a circuit model?



I'm going to present an example, step by step. Please contribute
something technical in response.

It's a simple lossless quarter-wave matching section example.

------50 ohm feedline---+---1/4WL 600 ohm feedline---7200 ohm load
Pfor1=100w-- Pfor2=352w-- 100w
--Pref1=0w --Pref2=252w
Vfor1=70.7v-- Vfor2=460v-- Vload=849v
--Vref1=0v --Vref2=389v
Ifor1=1.414A-- Ifor2=0.766A-- Iload=0.118A
--Iref1=0A --Iref2=0.648A

Vref2 is 180 degrees out of phase with Vfor2 and thus they subtract.

Iref2 is in phase with Ifor2 and thus they add.

The impedance at '+' is (Vfor2-Vref2)/(Ifor2+Ifor1)

The impedance at '+' is (460v-389v)/(0.766A+0.648A) = 70.7V/1.414A = 50
ohms

Note that the impedance seen at the match point is:

Vfor1/Ifor1 = (Vfor2-Vref2)/(Ifor2+Iref2)

So Tom, do you find anything wrong with this network analysis? If so,
please be technically specific. (Sorry, your feelings don't matter.)
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil, if I had a dollar for every time you challenged someone to solve
a quarter wavelength transmission line transformer problem I could eat a
meal in the best restaurant in San Francisco and still have change left
over to pay a 20% tip. The question is not whether or not the theory
you made up in your head is right or not, but whether the length, shape,
volume, whatever of a loading coil on a short antenna makes any
substantial difference in the efficiency of the antenna. The problem of
increasing the total current on a short antenna was solved so many years
ago the fellows who solved it are old enough to be Richard Harrison's
grandparents. If Yuri would spend more time researching his subject and
less time with his fish thermometers and his diatribes against Tom Rauch
he would learn that.
73,
Tom Donaly, KA6RUH

H. Adam Stevens, NQ5H October 22nd 04 09:41 PM


"Tom Donaly" wrote in message
m...
Cecil Moore wrote:
Tom Donaly wrote:

Who said anything about a circuit model?



I'm going to present an example, step by step. Please contribute
something technical in response.

It's a simple lossless quarter-wave matching section example.

------50 ohm feedline---+---1/4WL 600 ohm feedline---7200 ohm load
Pfor1=100w-- Pfor2=352w-- 100w
--Pref1=0w --Pref2=252w
Vfor1=70.7v-- Vfor2=460v-- Vload=849v
--Vref1=0v --Vref2=389v
Ifor1=1.414A-- Ifor2=0.766A-- Iload=0.118A
--Iref1=0A --Iref2=0.648A

Vref2 is 180 degrees out of phase with Vfor2 and thus they subtract.

Iref2 is in phase with Ifor2 and thus they add.

The impedance at '+' is (Vfor2-Vref2)/(Ifor2+Ifor1)

The impedance at '+' is (460v-389v)/(0.766A+0.648A) = 70.7V/1.414A = 50
ohms

Note that the impedance seen at the match point is:

Vfor1/Ifor1 = (Vfor2-Vref2)/(Ifor2+Iref2)

So Tom, do you find anything wrong with this network analysis? If so,
please be technically specific. (Sorry, your feelings don't matter.)
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil, if I had a dollar for every time you challenged someone to solve
a quarter wavelength transmission line transformer problem I could eat a
meal in the best restaurant in San Francisco and still have change left
over to pay a 20% tip. The question is not whether or not the theory
you made up in your head is right or not, but whether the length, shape,
volume, whatever of a loading coil on a short antenna makes any
substantial difference in the efficiency of the antenna. The problem of
increasing the total current on a short antenna was solved so many years
ago the fellows who solved it are old enough to be Richard Harrison's
grandparents. If Yuri would spend more time researching his subject and
less time with his fish thermometers and his diatribes against Tom Rauch
he would learn that.
73,
Tom Donaly, KA6RUH


Tom
You would have enough money to own the restaurant.

sigh
Here goes---
Any difference in current between the ends of a compact loading coil in the
center of a short whip is due to radiation from the coil.
The same people have been making the same arguments here for years.
sheesh!
OTOH is has been entertaining.
73
H.



Cecil Moore October 23rd 04 02:53 AM

Tom Donaly wrote:
The question is not whether or not the theory
you made up in your head is right or not, but whether the length, shape,
volume, whatever of a loading coil on a short antenna makes any
substantial difference in the efficiency of the antenna.


No, that's not the question at all. You have diverted the issue from
current through the coil to efficiency. The question is whether the
current at each end of a real-world loading coil is the same or not
the same. Efficiency is irrelevant.

Diverting the issue is an obvious tactic employed by someone who is
losing the argument.

If one doesn't understand standing waves on a transmission line, one
cannot understand standing-wave antennas. The ignorance of how standing-
wave antennas work is the basic problem. I am attempting to alleviate
that ignorance.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 23rd 04 03:37 AM

H. Adam Stevens, NQ5H wrote:
Any difference in current between the ends of a compact loading coil in the
center of a short whip is due to radiation from the coil.


That's an old wives' tale. But don't feel bad. Kurt N. Sterba made essentially
that same mistake in his Nov. 2004 article in "Worldradio". Anyone who believes
that the current is zero at the tip end of a standing-wave antenna because it
has been radiated needs a refresher course in standing waves.

************************************************** *******************
* Any difference in forward current between the ends of a loading
* coil is due to radiation from the coil.
*
* Any difference in reflected current between the ends of a loading
* coil is due to radiation from the coil.
************************************************** *******************

Please read those two statements until they soak in because they
agree with you about component currents but disagree with you about
superposed currents.

The main difference between the net superposed current at each end of the
coil is caused by the phase shift through the coil acting on each of those
current components in opposite phase-rotation since they are traveling in
opposite directions.

Is any difference in current between the ends of a section of transmission
line due to radiation from the transmission line? Yes, but most of the
difference is due to phase shifts between the forward and reflected waves.
Exactly the same concepts apply both to a transmission line with standing
waves and a standing-wave antenna. In fact, a horizontal wire antenna is
nothing more than a "lossy" transmission line losing energy to radiation.

A mobile antenna is a standing-wave antenna possessing a Z0, just like a
transmission line. There's a forward current and a reflected current. The
superposition of those two component currents causes the main difference
in the magnitude of the net current at each end of the coil.

When Roy, W7EL, measured the phase of the current at each end of the coil,
he measured the phase of the NET superposed current, not the phase of the
forward current or reflected current. The phase shift of the NET superposed
current is only a couple of degrees max from feedpoint to end as asserted by
Kraus in "Antennas for all Applications", page 464.

In the ARRL Antenna Book is an equation for the characteristic impedance of
a single wire over ground. It is 138*log(4h/d) where 'h' is the height of
the antenna and 'd' is the diameter of the wire. The Z0 for a piece of #16
wire positioned 24 feet above ground is about 600 ohms. A quarter wavelength
of that wire used as an antenna responds essentially the same as a quarter
wavelength of lossy transmission line. There is a large reflected current
component at the tip of a mobile (standing-wave) antenna.

In fact, my earlier quarter-wavelength matching section plus its 100w load
acts similar to a quarter-wavelength antenna radiating 100w.
--
73, Cecil http://www.qsl.net/w5dxp


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Tom Donaly October 23rd 04 05:06 AM

Cecil Moore wrote:
Tom Donaly wrote:

The question is not whether or not the theory
you made up in your head is right or not, but whether the length, shape,
volume, whatever of a loading coil on a short antenna makes any
substantial difference in the efficiency of the antenna.



No, that's not the question at all. You have diverted the issue from
current through the coil to efficiency. The question is whether the
current at each end of a real-world loading coil is the same or not
the same. Efficiency is irrelevant.

Diverting the issue is an obvious tactic employed by someone who is
losing the argument.

If one doesn't understand standing waves on a transmission line, one
cannot understand standing-wave antennas. The ignorance of how standing-
wave antennas work is the basic problem. I am attempting to alleviate
that ignorance.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil, I'll believe you know something about loading coils when you
go back to school and learn something about basic classical
electromagnetic theory. As it stands, all you can do is make one
unsupported statement after another and hope someone is gullible
enough to believe you.
73,
Tom Donaly, KA6RUH

(P.S. How do you know what the subject was? You didn't read all
the posts.)

Cecil Moore October 23rd 04 05:48 AM

Tom Donaly wrote:
Cecil, I'll believe you know something about loading coils when you
go back to school and learn something about basic classical
electromagnetic theory.


Been there - done that - even got the T-shirt with Maxwell's
equations on it. I suspect that your university never taught
the real thing.

As it stands, all you can do is make one
unsupported statement after another and hope someone is gullible
enough to believe you.


I supported my statements with examples. Strangely enough, you
haven't posted any technical disagreement with my examples. All
you do is take potshots based on nothing except your feelings.

It's impossible to argue with you on a technical basis because you
have not posted anything technical. Do you disagree that the Z0
of a single #16 wire located 24 ft. above ground is ~600 ohms? Do
you disagree that such a wire can support standing waves whether
used as a transmission line or as an antenna?

Please post what you find technically wrong with my examples (all
based on valid distributed network reflection models) which I
learned in the 50's from "Field and Waves in Modern Radio" by Ramo
and Whinnery and a later edition of the same book in graduate school.
--
73, Cecil http://www.qsl.net/w5dxp


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Jimmie October 23rd 04 06:42 PM


"Cecil Moore" wrote in message
...
Jimmie wrote:
What, Coililng the wire has nothing to do with how well it does or does

not
radiate, only with how the radiation is summed into the total field. The
current distribution in a loading coil should be very similar to the

current
distribution in the secton of antenna it is replacing.


Actually, coiling the wire tends to reduce the far-field radiation
because much of the near-field(s) cancel each other. The currents
on each side of the coil are traveling the opposite direction in
much the same way they do in a transmission line. However, that
doesn't mean the currents at the bottom and top of the coil are
identical. The magnitude of the total current at the bottom and
top of the coil depends in large amount on the phase shift through
the coil.
--
73, Cecil http://www.qsl.net/w5dxp


Just because it is canceld in the far field does not mean the coil did not
radiate. I would not even say it is canceled in the far field although this
is a convenent way of looking at radiation. All you can really say for sure
is that the out of phase voltages in the receiving antenna combine
destructively.

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Jimmie October 23rd 04 06:49 PM


"Richard Harrison" wrote in message
...
Jimmie wrote:
"Coiling the wire has nothing to do with how it does or does not
radiate,---."

Good. Just leave your antenna rolled up.

Best regards, Richard Harrison, KB5WZI

And it will radiate, assuming no other changes but the geometry of the
antenna.. When the out of phase componts of the radiation reach a receiving
antenna they will destructivly combine.



Tom Donaly October 23rd 04 07:00 PM

Cecil Moore wrote:
Tom Donaly wrote:

Cecil, I'll believe you know something about loading coils when you
go back to school and learn something about basic classical
electromagnetic theory.



Been there - done that - even got the T-shirt with Maxwell's
equations on it. I suspect that your university never taught
the real thing.

As it stands, all you can do is make one
unsupported statement after another and hope someone is gullible
enough to believe you.



I supported my statements with examples. Strangely enough, you
haven't posted any technical disagreement with my examples. All
you do is take potshots based on nothing except your feelings.

It's impossible to argue with you on a technical basis because you
have not posted anything technical. Do you disagree that the Z0
of a single #16 wire located 24 ft. above ground is ~600 ohms? Do
you disagree that such a wire can support standing waves whether
used as a transmission line or as an antenna?

Please post what you find technically wrong with my examples (all
based on valid distributed network reflection models) which I
learned in the 50's from "Field and Waves in Modern Radio" by Ramo
and Whinnery and a later edition of the same book in graduate school.
--
73, Cecil http://www.qsl.net/w5dxp


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I'm not going to waste my time arguing with you , Cecil; as you say,
been there, done that. I know there are people in the past who have
attempted to characterize antennas as transmission lines. It's an
old, hoary method. You have a copy of Balanis. He has references you
can look up to see how close your ideas are to the truth.
Nope, I don't need to argue. I have a wife who is always willing
and ready to provide arguing services whenever I need them. I don't
need you.
73,
Tom Donaly, KA6RUH

Cecil Moore October 23rd 04 08:30 PM

Jimmie wrote:
Just because it is canceld in the far field does not mean the coil did not
radiate.


It is generally accepted that if RF energy doesn't escape to the far-
field, that energy is not "radiated". Energy can appear in the near-
field around a wire without being "radiated".

I would not even say it is canceled in the far field although this
is a convenent way of looking at radiation. All you can really say for sure
is that the out of phase voltages in the receiving antenna combine
destructively.


If the fields combine destructively in the near-field, that field energy
is returned to the system and never reaches the receiving antenna in the
far field. That's how transmission lines are supposed to work and why
the spacing between the two conductors needs to be negligible compared
to a wavelength.

The near-balanced currents on each side of a coil, traveling in
opposite directions, cause destructive interference in the near field,
thus limiting the amount of energy radiated by the coil. An electrical 1/4WL
helical antenna radiates slightly less RF than does a 1/4WL straight wire.
That implies the amount of radiation from an air-core coil is slightly less
than from a wire the same overall length as the coil.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 23rd 04 08:42 PM

Jimmie wrote:
And it will radiate, assuming no other changes but the geometry of the
antenna.. When the out of phase componts of the radiation reach a receiving
antenna they will destructivly combine.


If it actually radiates and if that radiation destructively combines
at one receiving antenna, then radiation must constructively combine
at another (potential) receiving antenna, or else the conservation of
energy principle would be violated. Any far-field destructive interference
event must be exactly balanced by an equal magnitude constructive
interference event at some other location in the far-field. If there is
a receiving antenna there, it will experience gain over the first location.

And a coiled up antenna is likely to experience a lot of I^2*R losses.
--
73, Cecil http://www.qsl.net/w5dxp


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Cecil Moore October 23rd 04 09:06 PM

Tom Donaly wrote:
I'm not going to waste my time arguing with you , Cecil; as you say,
been there, done that.


Don't want to argue, Tom. I just want you to make a posting that
contains some iota of technical content. My ten-year-old grand-neice
could easily have thought up your last dozen (mostly ad-hominem) postings.

I know there are people in the past who have
attempted to characterize antennas as transmission lines. It's an
old, hoary method. You have a copy of Balanis. He has references you
can look up to see how close your ideas are to the truth.


Since you brought up Balanis, here are some quotes from Chapter 10 of
his book that should impress you:

"The sinusoidal current distribution of long open-ended linear antennas
is a standing wave constructed by two waves of equal amplitude and 180
deg phase difference at the open-end TRAVELING IN OPPOSITE DIRECTIONS
along its length" page 488 (emphasis mine)

"THE CURRENT AND VOLTAGE DISTRIBUTIONS ON OPEN-ENDED WIRE ANTENNAS ARE
SIMILAR TO THE STANDING WAVE PATTERNS ON OPEN-ENDED TRANSMISSION LINES."
Page 488 (emphasis mine)

"Standing wave antennas, such as the dipole, can be analyzed as traveling
wave antennas with waves propagating in opposite directions (forward and
backward) and represented by traveling wave currents If and Ib." page 489

Uhhhhh Tom, following Balanis' direction is EXACTLY what I have been doing.
Since you disagree with Balanis, it appears that you have never cracked
open his book. I, OTOH, have attended Balanis' antenna classes at ASU
and worked hand in hand with him on a joint Intel-ASU project.
--
73, Cecil http://www.qsl.net/w5dxp


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Yuri Blanarovich October 24th 04 12:45 AM

Nope, I don't need to argue. I have a wife who is always willing
and ready to provide arguing services whenever I need them. I don't
need you.
73,
Tom Donaly, KA6RUH



Cecil, fuggetaboutit, don't waste your time, looks like this is one of those
smart alec trollers. Who cares what they "know".

Thanks for your contribution to the subject. Looks like I should put the
article together, looks like misguided "experts" are confusing the issue.
I hope to find some time now, WX is getting about right, time to get out the
gadgets and some real life measurements and modeling helixes in EZNEC.

73 Yuri, K3BU

Cecil Moore October 24th 04 01:49 AM

Yuri Blanarovich wrote:
Cecil, fuggetaboutit, don't waste your time, looks like this is one of those
smart alec trollers. Who cares what they "know".


Looks like Tom would rather argue with his wife than with Balanis or me.
(I don't blame him for that.) I had relatively long discussions with Balanis
and he personally agreed with everything I have posted although he didn't
go to such lengths in his book.

Thanks for your contribution to the subject. Looks like I should put the
article together, looks like misguided "experts" are confusing the issue.
I hope to find some time now, WX is getting about right, time to get out the
gadgets and some real life measurements and modeling helixes in EZNEC.


Who's going to publish it? I spent a lot of time preparing an article on
what happens at a match point and QEX refused to consider publishing
anything that disagreed in the slightest with Dr. Best who denied there
is such a thing as interference at a match point. (Hint: Without interference,
a match is impossible in a system with reflections.) There's a good-old-boys
network in amateur radio. If you are politically incorrect within the ARRL
political power structure, you are black-balled from publishing. It doesn't
matter if you are technically correct. The current through a loading coil
is constant by definition in that good-old-boys network. Forget reality.
--
73, Cecil http://www.qsl.net/w5dxp


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Yuri Blanarovich October 24th 04 02:42 AM

Who's going to publish it? I spent a lot of time preparing an article on
what happens at a match point and QEX refused to consider publishing
anything that disagreed in the slightest with Dr. Best who denied there
is such a thing as interference at a match point. (Hint: Without
interference,
a match is impossible in a system with reflections.) There's a good-old-boys
network in amateur radio. If you are politically incorrect within the ARRL
political power structure, you are black-balled from publishing. It doesn't
matter if you are technically correct. The current through a loading coil
is constant by definition in that good-old-boys network. Forget reality.
--
73, Cecil http://www.qsl.net/w5dxp


100% QSL
we can give it a try, there is always internet and e-Books.
It is amusing to see two versions of current in loading coil in ARRL published
books, one version in Antenna Book, Compendia and Handbook vs. other in ON4UN
Low Band DXing.

73 Yuri, K3BU.us

Cecil Moore October 24th 04 04:42 AM

Yuri Blanarovich wrote:
It is amusing to see two versions of current in loading coil in ARRL published
books, one version in Antenna Book, ...


Correction: Two versions in the ARRL Antenna Book. The first illustration,
Fig 7 on 16-4 in my 15th edition shows the current taper across the coil.
Fig 10 on 16-6 shows no current taper across the coil. :-)
--
73, Cecil http://www.qsl.net/w5dxp


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Tom Donaly October 24th 04 05:23 AM

Cecil Moore wrote:
Yuri Blanarovich wrote:

Cecil, fuggetaboutit, don't waste your time, looks like this is one of
those
smart alec trollers. Who cares what they "know".



Looks like Tom would rather argue with his wife than with Balanis or me.
(I don't blame him for that.) I had relatively long discussions with
Balanis
and he personally agreed with everything I have posted although he didn't
go to such lengths in his book.



Suuuurrrre he did.





Thanks for your contribution to the subject. Looks like I should put the
article together, looks like misguided "experts" are confusing the issue.
I hope to find some time now, WX is getting about right, time to get
out the
gadgets and some real life measurements and modeling helixes in EZNEC.



Who's going to publish it? I spent a lot of time preparing an article on
what happens at a match point and QEX refused to consider publishing
anything that disagreed in the slightest with Dr. Best who denied there
is such a thing as interference at a match point. (Hint: Without
interference,
a match is impossible in a system with reflections.) There's a
good-old-boys
network in amateur radio. If you are politically incorrect within the ARRL
political power structure, you are black-balled from publishing. It doesn't
matter if you are technically correct. The current through a loading coil
is constant by definition in that good-old-boys network. Forget reality.


And now there's a cabal of old boys conspiring against you and Yuri.
This just keeps getting better and better. For those who really want to
know the truth, go to Tom Rauch's web site and read about loading coils.
(He doesn't use the term "current drop" once."
73,
Tom Donaly, KA6RUH


Yuri Blanarovich October 24th 04 02:19 PM


Correction: Two versions in the ARRL Antenna Book. The first illustration,
Fig 7 on 16-4 in my 15th edition shows the current taper across the coil.
Fig 10 on 16-6 shows no current taper across the coil. :-)
--
73, Cecil http://www.qsl.net/w5dxp



You are right, also my "lucky" thirteenth edition (1974) has picture 15-6
showing current drop across the coil. Back in those days they were some smart
and knowledgeable editors at ARRL.

Cecil, you are merciles protector of the truth :-)

Yuri, K3BU.us

Cecil Moore October 24th 04 03:36 PM

Tom Donaly wrote:
For those who really want to
know the truth, go to Tom Rauch's web site and read about loading coils.
(He doesn't use the term "current drop" once."


I'm glad you used "truth" instead of "facts". Tom's truth doesn't
agree with scientific fact. You guys have turned your "truth"
into a religion.

Is there a current drop in a transmission line from the current
maximum (loop) to the current minimum (node) when standing waves
are present?

Is there a current drop from the feedpoint of a helical 1/4WL
antenna to the tip of the antenna?

If a coil occupies 90 degrees of a standing-wave antenna or an
unterminated transmission line with reflections, the current
can be maximum at one end of the coil and zero at the other.
The electrical 3/4WL antenna below consists of 1/4WL of wire,
loading coil, and 1/4WL of wire. The net current at one end
of the coil could be one amp while the net current at the
other end of the coil is zero. If you don't understand that
fact, I feel sorry for you.

coil
Feedpoint---1/4WL wire---x-///////-y---1/4WL wire---

When the above antenna is made resonant, the net current at
'x' is zero while the net current at 'y' is maximum. How do
you explain a coil with zero current at the bottom and one
amp at the top? It happens all the time in distributed
networks.

If a coil occupies 180 degrees of a standing wave antenna or an
unterminated transmission line with reflections, the current
can be zero at both ends and maximum in the middle. Such a
configuration is illustrated in "Antennas for all Applications",
by Kraus and Marhefka on page 824.
--
73, Cecil http://www.qsl.net/w5dxp

"The current and voltage distributions on open-ended wire antennas are
similar to the standing wave patterns on open-ended transmission lines ...
Standing wave antennas, such as the dipole, can be analyzed as traveling
wave antennas with waves propagating in opposite directions (forward and
backward) and represented by traveling wave currents If and Ib ..."
_Antenna_Theory_, Balanis, Second Edition, Chapter 10, page 488 & 489


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Tom Donaly October 24th 04 04:22 PM

Cecil Moore wrote:
Tom Donaly wrote:

For those who really want to
know the truth, go to Tom Rauch's web site and read about loading coils.
(He doesn't use the term "current drop" once."



I'm glad you used "truth" instead of "facts". Tom's truth doesn't
agree with scientific fact. You guys have turned your "truth"
into a religion.

Is there a current drop in a transmission line from the current
maximum (loop) to the current minimum (node) when standing waves
are present?

Is there a current drop from the feedpoint of a helical 1/4WL
antenna to the tip of the antenna?

If a coil occupies 90 degrees of a standing-wave antenna or an
unterminated transmission line with reflections, the current
can be maximum at one end of the coil and zero at the other.
The electrical 3/4WL antenna below consists of 1/4WL of wire,
loading coil, and 1/4WL of wire. The net current at one end
of the coil could be one amp while the net current at the
other end of the coil is zero. If you don't understand that
fact, I feel sorry for you.

coil
Feedpoint---1/4WL wire---x-///////-y---1/4WL wire---

When the above antenna is made resonant, the net current at
'x' is zero while the net current at 'y' is maximum. How do
you explain a coil with zero current at the bottom and one
amp at the top? It happens all the time in distributed
networks.

If a coil occupies 180 degrees of a standing wave antenna or an
unterminated transmission line with reflections, the current
can be zero at both ends and maximum in the middle. Such a
configuration is illustrated in "Antennas for all Applications",
by Kraus and Marhefka on page 824.


Did you have fun writing that, Cecil? What makes you think the
variation in current in two seperate places of a coil carrying
A.C. is a "current drop?"
73,
Tom Donaly, KA6RUH

Cecil Moore October 24th 04 06:32 PM

Yuri Blanarovich wrote:
Cecil, you are merciless protector of the truth :-)


Guess that's why I receive no mercy. :-)
--
73, Cecil http://www.qsl.net/w5dxp


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