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#1
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On Mon, 22 Nov 2004 22:08:29 +0000 (UTC), "Reg Edwards"
wrote: Not having much else to do at present I thought I would make a comment on Zo and Ro of transmission lines. For entertainment and educational value, of course, if you like that sort of thing. The condition for which Zo of a transmission line is always purely resistive (Zo = Ro) is extremely simple. It is - G = C * R / L where G is shunt conductance, C is shunt capacitance, R is series resistance, L is series inductance, all per unit length of line. Which applies to any line length, at any frequency from DC to UHF. It is a shortcoming of the Smith Chart, with Zo always equal to Ro, that it does not make you aware of this and can lead you up the garden path if you are not careful. As has recently occurred on this newsgroup. Don't get me wrong. I'm not against Smith Charts. They are graphically educational within their limitations. ---- Reg, G4FGQ Dear Reg, You say that it is a shortcoming of the Smith Chart that Zo equals Ro. However, I think that is either a misunderstanding or just misleading. The Smith Chart only constrains the normalizing quantity to be purely resistive - not the characteristic impedance of a particular transmission line being shown on that chart. My program, SmartSmith, for example, allows the user to specify both an Ro and an Xo term for all transmission line sections. When it's all said and done, the Smith Chart only implements the transmission line equation (as shown on pages 24-10 and 27-29 in the 17th Edition of The ARRL Antenna Book). With my respects and best wishes, Bob, W9DMK, Dahlgren, VA http://www.qsl.net/w9dmk |
#2
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#3
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#4
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Wes Stewart wrote in message . ..
On 23 Nov 2004 07:36:11 -0800, (Dr. Slick) wrote: [snip] | Since i trust Les Besser more than |other people, Heh heh. Reminds me... I took his video taped course, "RF/Microwave Transistor Amplifier Design". I was watching one tape at home while the XYL was making dinner. She could hear the audio and finally asked me to turn it off since it was making *her* fall asleep. [g]. Really smart guy, but not a very dynamic speaker. Hehe! Yeah, also not exactly the sexiest guy on the planet, is he! I have his full RF Fund. course One and Two on tape, like 12 tapes in all. We should have a Les Besser Get together sometime. Wooohaaa! Fun! Slick |
#5
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Dr. Slick wrote:
Well, that is pretty entertaining and interesting, i will admit. However, the result isn't very practical... On the contrary, the result is extremely practical and isn't very ideal, just like real-world physics. :-) -- 73, Cecil http://www.qsl.net/w5dxp |
#6
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Cecil Moore wrote in message ...
Dr. Slick wrote: Well, that is pretty entertaining and interesting, i will admit. However, the result isn't very practical... On the contrary, the result is extremely practical and isn't very ideal, just like real-world physics. :-) When was the last time you used "G = C * R / L" for anything? Slick |
#7
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Dr. Slick wrote:
When was the last time you used "G = C * R / L" for anything? Yesterday. |
#8
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Cecil Moore wrote:
Dr. Slick wrote: When was the last time you used "G = C * R / L" for anything? Yesterday. Just curious, Cecil. What were you using a distortionless line for? Tom Donaly, KA6RUH |
#9
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Tom Donaly wrote:
Cecil Moore wrote: Dr. Slick wrote: When was the last time you used "G = C * R / L" for anything? Yesterday. Just curious, Cecil. What were you using a distortionless line for? Methinks you jumped to conclusions. Slick didn't ask when was the last time I used a distortionless line. He asked when was the last time I used the equation "G=C*R/L" for anything. I'm using it right now. I used it yesterday to refresh my memory about distortionless lines which I did use quite often before I retired from Intel in 1998. If I presently held a job in the cable modem group, I suppose I would still be using them. -- 73, Cecil http://www.qsl.net/w5dxp |
#10
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Cecil Moore wrote in message ...
Dr. Slick wrote: When was the last time you used "G = C * R / L" for anything? Yesterday. Oh really? Please explain in detail? S. |