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Reg, G4FGQ wrote:
"The active device generally behaves as a current source." As Reg also wrote: "I can`t imagine why this conversation has continued for so many years by more or less the same group of experts." Agreed! Reg seems to have answered his own question.The same people recite the same arguments in hopes their view of reality will be accepted. Fat chance! Time has inured them. Reg has faithfully proposed constant-current behaviour from all vacuum valves and transistors as I recall. I agree that most of these devices have extremely high plate ond collector resistances as linear amplifiers. Current through them is almost constant regardless of anode voltage. As most transmitter power amplifiers exceed 50% efficiency by a good margin, these devices are not operating as Class-A linear amplifiers. They instead operate as HF switches. These are turned-off most of every cycle and are only on for short pulses. Harmonics and other noise is cleaned up by output filters. It`s the only thing which makes the output linear. During the output device`s conduction, its saturation volts are very low and its current is very high, giving the device a very low impedance while switched-on. You may not infer a low impedance from the d-c volts and amps feeding the final amplifier. These are the averages, almost, of the device amps. The device saturation volts sre what counts toward its dissipation and loss. The transmitter usually has no built-in indicator of saturation voltage. It wouldn`t read much anyway.Device impedance depends mostly on its ratio of off to on times. This is a form of lossless resistance. Dissipation is zero in a sewitched-off device. The d-c volts and amps are related to the output device(s) internal impedances used as a switch when the transmitter output is considered. A high voltage and a low current accompany a high internal impedance but they won`t be nearly so high as the spec sheet plate or collector resistances. We have d-c power input to the amplifier. We can measure HF power output. The difference is dissipation, but loss resistance does not represent the total source resistance because we have non-dissipative resistance in the device off-times. There have been measurements of transmitter internal output impedances which indicated that they did indeed match their loads. I have not done it myself but have no reason to doubt the reports. Best regards, Richard Harrison, KB5WZI |
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