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Hello Roy,
Good question and one I had considered addressing in my already over long post. In general "the grid" is viewed as an idealized source or sink of both real and reactive power. So we can theoretically supply it as much power as we wish, and supply or take in as much reactive power as we wish. No reactive load banks needed. So when I said generation (of both watts and VARs) is matched to demand, that's not necessarily *exactly* the case when it comes to VARs, as you guessed. Generators can both supply and absorb them to meet the need, and the net VAR output doesn't necessarily have to equal whatever the customers are offering as the load at any given time. BTW, in the power biz, we have the convention of "supplying", "outgoing", or positive VARs to describe reactive power out from the generator to a lagging (inductive) load and incoming, or negative VARs to leading (capacitive) loads. Incidentally, real power must flow *out* only. We have reverse power (anti-motoring) relays to trip the unit off line if this rule is broken. The tendency of generators to exchange VARs when in parallel leads to a stability problem in excitation control. A slight mismatch in excitation systems can lead to a huge exchange of VARs and resulting overcurrent. So excitations system incorporate what is known as a "droop" feature which essentially provides a negative feedback based on reactive current. Increased VARs out tends to reduce excitation, stabilizing the system. Droop is typically switched "off" in isochronous (one generator isolated) mode. There's an analogous "droop" feature on the governor for speed control when in parallel. Not sure if your question included this, but it's interesting to consider just how a generator produces out of phase current when connected to what we're essentially considering to be equivalent to an ideal voltage source, since by definition the generator's terminal voltage must equal that of the source (grid). As I see it, the key is that the generated voltage, Eg, is n ot the same as the generator's terminal voltage, Et. There's a drop across the armature reactance, so Et equals Eq minus that drop. Interesting that out of phase currents produce drops in phase with Eg ... Well, I thought so anyway. Current is Et minus Eg divided by Za (armature impedance). Changing excitation changes the magnitude of Eg (Et is fixed by the grid and so is an anchor point). By fooling with the phasors, I think you can see how changing excitation changes the phase angle and therefore controls VARs. How *power* is controlled is beyond the scope of this discussion (and maybe of my understanding). But it actually is related to the angle of the rotor's physical position relative to the rotating field of the armature. That angle is dependent upon the torque supplied by the driver. 73--Nick, WA5BDU in Arkansas "Roy Lewallen" wrote in message ... Thanks very much for the interesting and informative tutorial from someone in the industry. I have one question: Nick wrote: . . . Another possibly relevant story. We connect our emergency diesel generator to the grid for testing and load it to about 3000 kW and typically from 0 to 100 kVAR. But to fully test the excitation system, the kVAR is at some point raised to 1400. . . If your customers' loads were, for the sake of argument, purely resistive as seen at your power plant output, then the voltage and current would be in phase at that point. But in order to make your generator produce "reactive power", the voltage and current have to be forced out of phase at the generator. How is this resolved? Is that reactive power "delivered" to (actually swapped back and forth between) other generators in the system -- that is, do the other generators in the system shift their own phase angles so that the V and I can be at some angle other than zero at your generator output (and, necessarily, also at the outputs at other generators in the system) yet in phase at your customers' loads? Or do you have some local bank of reactance that you can switch in to feed the "reactive power" back and forth to when you run this test? Roy Lewallen, W7EL |
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