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Balun Use/Need
There is a general belief that a balun should be used where coax connects to
the feedpoint of a 1/2-wave dipole (for example), to avoid RF current on the outer surface of the coax outer conductor -- which can affect antenna input match, radiation pattern etc. But does even a perfect balun fully remove these effects? The outside of the outer conductor of the coax feedline still will be coupled into the received and/or radiated fields, even when there is no current flowing into the coax outer conductor via a metallic connection directly with the dipole itself. As an illustration of this, consider the effect of a 1/2-wave dipole suspended near, and parallel to another 1/2-wave dipole. Only one dipole is driven. For simplicity of concept, let's say the active RF device (either a tx or rx) is a physically small unit built in to the center insulator of the driven dipole, e.g., no feedline. Standard equations, and NEC-2 analysis show that considerable interaction exists between the two dipoles. The input match of the driven dipole changes, and the radiation pattern of the simple dipole is strongly affected. Yet the only coupling between these two dipoles is by radiation. So how important is the balun in the total RF system? RF |
So how important is the balun in the total RF system? For simple dipoles it makes lots of money and helps out with the unemployment. |
Richard Fry wrote:
There is a general belief that a balun should be used where coax connects to the feedpoint of a 1/2-wave dipole (for example), to avoid RF current on the outer surface of the coax outer conductor -- which can affect antenna input match, radiation pattern etc. But does even a perfect balun fully remove these effects? There are two sources for common-mode current. One is conduction. The other is induction. Since common-mode currents are somewhat unpredictable, the best way to ascertain if there is a problem is to measure the current. A toroidal pickup slipped over the coax will give one a relative reading and is super simple to implement. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
On Fri, 21 Jan 2005 12:06:42 -0600, "Richard Fry"
wrote: The outside of the outer conductor of the coax feedline still will be coupled into the received and/or radiated fields, Hi OM, What you fail to bring into this is the "degree" of coupling. The transmission line being orthogonal is in the plane of the dipole's null - hence zero conduction. It only supports conduction through either direct connection (which the BalUn/Choke breaks) or loss of symmetry (not falling in the plane of the dipole's null or the environment distorting that electrical plane - an unbalanced dipole). As an illustration of this, consider the effect of a 1/2-wave dipole suspended near, and parallel to another 1/2-wave dipole. Only one dipole is driven. This, again, reveals the nature of "degree" of coupling. That is, in your scenario the second dipole MUST be parallel AND broadside. If it were parallel and online, the coupling would be considerably (10 - 15 dB) less. So how important is the balun in the total RF system? What is the "degree" of coupling? 73's Richard Clark, KB7QHC |
Cecil Moore wrote:
Richard Fry wrote: There is a general belief that a balun should be used where coax connects to the feedpoint of a 1/2-wave dipole (for example), to avoid RF current on the outer surface of the coax outer conductor -- which can affect antenna input match, radiation pattern etc. But does even a perfect balun fully remove these effects? No, it doesn't, for the reasons that Richard gave, and Cecil summarizes below. The reasons why these currents can appear is because the antenna, the feedline layout and/or the environment is asymmetrical - and often it's all three. How much unwanted feedline current you have will depend on the physical layout, how long the feedline is in wavelengths, and where and how it may be grounded at the shack end. That's what makes it unpredictable, as Cecil says below; so whether or not you need a balun will depend entirely on your particular situation. There are two sources for common-mode current. One is conduction. The other is induction. The 'conduction' component of the current is launched onto the feedline where it connects to the antenna, and a good choke balun at the feedpoint can effectively knock it out. The balun at the feedpoint doesn't have to be perfect; only good enough to make sure that the conduction current doesn't dominate any more. That leaves the 'induction' component of the current, which is due to asymmetrical electromagnetic coupling between the antenna and the feedline. Unless the feedline is much closer to one side of the antenna than the other, this induction component will generally be much smaller than the conduction component was (before you mostly removed it with a balun at the feedpoint). If the remaining induction current is a problem, you may need to use additional chokes at various places along the feedline. Depending on the feedline length and the grounding arrangements, there will be current maxima and minima at various places along the feedline. The most effective place to put a choke is obviously at a maximum, where the current is trying to be large; the least effective place is at a minimum, where it's low anyhow. The last traces of feedline current are very hard to kill completely. It's rather like trying to squeeze the air out of a long balloon - choke the current in one place, and a new maximum will try to pop up somewhere else. Even so, a few chokes in the right places - and always put the first one at the feedpoint - will almost definitely put you in control of the situation. But how do you know how much current you've got, and where the current maxima are? Since common-mode currents are somewhat unpredictable, the best way to ascertain if there is a problem is to measure the current. A toroidal pickup slipped over the coax will give one a relative reading and is super simple to implement. Here is a whole page about clip-on current meters, which have the advantage that you don't have to disconnect the cable to feed it through a toroid: http://www.ifwtech.co.uk/g3sek/clip-on/clip-on.htm The clip-on gadget is a bit more trouble to build, but you'll be very glad you did! With one of these, you can actually *see* how much RF current you've got, and where it is. Without it, you might as well be investigating RFI problems with your eyes shut. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
"Richard Fry" wrote in message ... There is a general belief that a balun should be used where coax connects to the feedpoint of a 1/2-wave dipole (for example), to avoid RF current on the outer surface of the coax outer conductor -- which can affect antenna input match, radiation pattern etc. But does even a perfect balun fully remove these effects? The outside of the outer conductor of the coax feedline still will be coupled into the received and/or radiated fields, even when there is no current flowing into the coax outer conductor via a metallic connection directly with the dipole itself. As an illustration of this, consider the effect of a 1/2-wave dipole suspended near, and parallel to another 1/2-wave dipole. Only one dipole is driven. For simplicity of concept, let's say the active RF device (either a tx or rx) is a physically small unit built in to the center insulator of the driven dipole, e.g., no feedline. Standard equations, and NEC-2 analysis show that considerable interaction exists between the two dipoles. The input match of the driven dipole changes, and the radiation pattern of the simple dipole is strongly affected. Yet the only coupling between these two dipoles is by radiation. So how important is the balun in the total RF system? RF Richard I'd sure like to see radiation pattern from testing or modeling you do on this "dipole pattern". I have been wondering about how the feed line can be disassociated from effecting the dipole's radiation pattern. I finally decided to make my feed for a 137MHz dipole by using two 50 ohm coax cables to form a 100 ohm balanced line. That alowed me to locate the balun at a place where its effectiveness is not important. Jerry |
"Richard Clark" wrote
The transmission line being orthogonal is in the plane of the dipole's null - hence zero conduction. ___________ But the nulls of a dipole are off its ends. The t-line connects to the dipole center, where relative field normal to the longitudinal axis of the dipole is at a maximum. RF |
"Jerry Martes" wrote
Richard I'd sure like to see radiation pattern from testing or modeling you do on this "dipole pattern". _________ Sure - I'll send it to your email adr as a GIF file. |
On Fri, 21 Jan 2005 14:50:05 -0600, "Richard Fry"
wrote: "Richard Clark" wrote The transmission line being orthogonal is in the plane of the dipole's null - hence zero conduction. ___________ But the nulls of a dipole are off its ends. The t-line connects to the dipole center, where relative field normal to the longitudinal axis of the dipole is at a maximum. Hi OM, It takes only a moment to visualize a dipole, frozen in time, where each arm supports the opposite charge. The continuum of forces between the two, in three-space, shows a distinct plane of response where a net-zero force is exhibited. This reference plane, a virtual ground, falls between the poles and is orthogonal. A common artifice of erecting vertically polarized antennas above dipoles bears this out. The two are invisible to each other. It also allows for the use of towers to support beams, but also explains why guy wires which violate balance (do not fall within the plane) must be broken up as conductors. The towers have a smaller degree of coupling than do the guy wires that support them. Even folded dipoles in commercial installations make use of this reference plane by providing a mounting point (180 degrees from the feed) to the support structure. No regard needs to be made for "shorting" out the loop at this point. The null you speak of is exhibited in the far field - the utility of BalUn/Chokes are in the near field. The transmission line may lie within the reference plane, but its metallic connection to one of the poles necessarily violates the electrical balance. The BalUn/Choke isolates this connection. 73's Richard Clark, KB7QHC |
If the coax bites - put a balun on it.
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