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Richard Harrison wrote:
At high altitudes, high potentials can easily produce corona and flashover. That's why the cubical quad was invented. The voltage at the voltage maximum points is in the ballpark of half that of a dipole and those points can be insulated. -- 73, Cecil, W5DXP |
Looks perfectly reasonable to me, Jim. Another perfectly reasonable thing to
ask is "what is the electric field strength near the antenna elements?" because if the field strength is too great, you can get corona. And EZNEC (NEC2, etc) will give you at least an estimate of that value. As you say, it can be interesting to know if an insulator will be adequate, and that's a question well worth asking. Cheers, Tom Jim, K7JEB, wrote: Well, I chose one particular configuration and one particular integration path because I was curious about the original question - something about how much voltage would the end insulator have to handle for 100 watts of radiated power. I chose a vertical, half-wave monopole fed against perfect ground and looked at the driving source data with EZNEC. The feed- point impedance was 2188 +j66 ohms and a driving current of .213 amps produced a radiated power of 100 watts and a feedpoint voltage of 466 volts. 1500 watts scales that up to 1805 volts. Symmetry about the ground would increase that to 3600 volts for the free-space case. That is what I would adopt as my design-to target for end insulators. I know it's crude, but I was just looking for a ballpark figure. |
Jim, K7JEB, wrote:
.... Again, this is just a special case of the general problem. But it has a configuration that is easy to implement in the EZNEC program and is quite relevant to typical ham-radio, low-band dipole installations. It's also easy to get the electric field strength near the antenna from EZNEC. I expect the field to be highest near wires, because of the shape the field must take near the wires, so that's where I'd look first to get an idea about possible breakdown of the air or insulators. Cheers, Tom |
Really???
K9CUN |
What we know as and call "voltage" is the potential difference between two
points. Give me access to the two points and an ideal voltmeter (AC or DC) and I'll measure it for you. I am assuming sinusoidal steady state AC, isn't everyone? 73 de Jack, K9CUN |
Just one caution about this. I don't think EZNEC or other NEC-based
programs will give accurate field strength any closer to a wire than a few wire diameters. So it probably wouldn't be good for predicting the likelihood of corona discharge and the like. It might be possible, though, to model a wire as a number of very much smaller parallel wires arranged in a circle, to get good field strength values closer to the real wire. I wouldn't completely trust the results, though, until at least a few test cases were run which could be compared to theoretical values. Roy Lewallen, W7EL K7ITM wrote: Jim, K7JEB, wrote: ... Again, this is just a special case of the general problem. But it has a configuration that is easy to implement in the EZNEC program and is quite relevant to typical ham-radio, low-band dipole installations. It's also easy to get the electric field strength near the antenna from EZNEC. I expect the field to be highest near wires, because of the shape the field must take near the wires, so that's where I'd look first to get an idea about possible breakdown of the air or insulators. Cheers, Tom |
Roy, W7EL wrote:
"I don`t think EZNEC or other NEC-based programs will give accurate field strength any closer to a wire than a few wire diameters." The Antenna Section in Keith Henney`s "Radio Engineering Handbook" was written by Edmund A. Laport, Chief Engineer of RCA`s International Division at the time (around 1950). On page 637 Ed writes: "Where high power is to be transmitted, or at high altitudes, antenna insulation and conductor designs require care to details. For h-f use, only radial potential gradients need to be considered. At high altitudes, pluming may occur with consequent damage to the system. Fortunately in practice, high power is generally used with directive antennas, and the power is divided among several dipole sections thus tending to minimize the problem. A thin-wire dipole gives an end potential of about 3,900 volts rms for 1000 watts input for a height of 0.25 wavelength. It will be higher for smaller heights, and falls to a minimum of about 1,700 volts as height increases to 0.75 wavelength; beyond this point it settles down to the free-space value of about 3,000 volts. Potentials vary as the square root of the power ratio and as the inverse square root of the capacitance per unit length. For a potential of 3,900 volts on a wire 0.101 in. in diameter (No, 10 B&S), the radial gradient is of the order of 31 kv per cm. As a rough approximation for a cage, the gradient for one wire is divided by the number of wires in the cage." The multiwire observation is important because, if the potential gradient at any point in air becomes greater than 30,000 volts/cm., the air becomes ionized and sparking or corona discharge will occur. On page 645, Ed writes: "With 100-kw carrier input (to an 8-dipole array), the end potential on each dipole is 7,500 volts rms. A 3000-ft. 580-ohm two-wire balanced feeder used with this antenna had an efficiency of 67 per cent. I am comfortable with Ed`s experience which can be scaled for the power and configuration of the antenna. Best regards, Richard Harrison, KB5WZI |
"So what's the voltage across the 1k resistor?"
------------------------------------------------------ It's whatever my ideal voltmeter reads when it's connected across the ends of the 1-kOhm resistor. Jack |
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