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Surely as a former broadcast engineer you're acquainted with a circuit
called a "DC restorer". This is a circuit which is always present in a TV receiver. In its simplest form, it's just a diode clamping circuit, although I've made very good ones with an FET switch and hold capacitor. What it does is to set the sync pulse tip to a fixed DC value, which then causes the rest of the TV waveform to be at a fixed DC value. This is how the DC information is "transmitted". The actual TV waveform is AC coupled, as it must be, and its DC values are established in the receiver by the DC restorer. No DC value is transmitted. You should be able to find an explanation of this in any basic text on the principles of television transmission and reception. Roy Lewallen, W7EL Richard Fry wrote: ______________ You mis-read. There is a DC component _required_ to convey the steady voltage values preceding and following the step pulse transition. He's not saying that the step pulse transition itself is comprised of "DC." RF |
Richard Fry wrote:
Before calling this reality absurd, consider that a television station transmits a video signal in/on an RF channel. The demodulated video waveform in the TV receiver will be identical to the baseband video signal applied to the TV tx -- including its DC components (subject to any distortions along the transmission path). If it wasn't ~ identical, a TV set could never "fade to black" when the original image did, and low-luminance colors such as blue, red, brown etc would be impossible to reproduce with their original chromaticity. RF (ex-RCA Field Engineer, and installer of hundreds of TV color studio and film cameras) You perhaps never installed a receiver. Without its DC restorer circuit, the problems you mention do indeed exist. In a black-and-white set, a large white area will cause everything else to go black, to maintain a zero average. But the DC information is transmitted as a level difference between the sync tip and the "porches". At the receiver (as I mentioned in another post), this voltage *difference* is turned into a DC value. No DC is transmitted. Surely a little bit of thought will establish why direct transmission of DC isn't possible beyond the range of a static field. Roy Lewallen, W7EL |
"Roy Lewallen" wrote
Surely as a former broadcast engineer you're acquainted with a circuit called a "DC restorer". This is a circuit which is always present in a TV receiver. In its simplest form, it's just a diode clamping circuit, although I've made very good ones with an FET switch and hold capacitor. What it does is to set the sync pulse tip to a fixed DC value, which then causes the rest of the TV waveform to be at a fixed DC value. This is how the DC information is "transmitted". The actual TV waveform is AC coupled, as it must be, and its DC values are established in the receiver by the DC restorer.... _________________________ I must respectfully disagree with that, Sir. The baseband video signal is * DC coupled * through analog TV transmitters . The peak power of a transmitted TV RF waveform is a fixed value, at the power corresponding to the licensed ERP of the station, occurring at the peak of sync pulses, and independent of program video. Transmitted _average_ power is a function of the video envelope. Video is transmitted with negative polarity; 75% modulation when video is black, and 12-1/2% modulation when it is white. The video waveform AS TRANSMITTED can contain a steady state (DC) value throughout the video field for any amplitude at or between those values (actually the color subcarrier can exceed these for some conditions). The circuits in a TV receiver cannot pass the DC component, thus the need for a DC restorer following the video demodulator. But the point remains that the transmitted TV waveform can, and often does contain a DC component, and that this DC component is required for accurate reproduction of the original video on the TV display. RF PS: I still AM a broadcast engineer. |
"Roy Lewallen" wrote
But the DC information is transmitted as a level difference between the sync tip and the "porches". At the receiver (as I mentioned in another post), this voltage *difference* is turned into a DC value. No DC is transmitted. _________________ As I wrote in my slightly earlier post to you on this, the actual video waveform is DC coupled through an analog TV transmitter. Please refer to that post for more on this topic. RF |
"Roy Lewallen" wrote about broadcast television waveforms:
... No DC value is transmitted.... and ...The actual TV waveform is AC coupled, as it must be, and its DC values are established in the receiver by the DC restorer... ___________________________ Please think about this. Standard TV color bars are produced by mixing the outputs of three video pulse generators. The pulses are square waves, with amplitude limits of 0 and 0.7VDC (~0.25µs transitions). These three video waveforms are shown in Figure 7-1 in the paper hyperlinked at the bottom of this post. The DC present during the "on" time of these video pulses is indistinguishable from the DC supplied by a continuous 0.7VDC source, over the same, steady-state time interval. The DC and near-DC values of this video must be available to the TV display device in order to accurately show the color bar signal (and any other video waveform). Low frequency content is lost when video is AC-coupled through a TV transmitter (or any other circuit). A TV set DC restorer sets and maintains the DC axis on which the pulse rides, but that does not correct the distortion of the pulse waveform resulting from loss of its low frequency content near zero hertz (DC). Also recall that even the shortest pulse* that can pass undistorted through the ~4MHz video bandwidth of the US broadcast TV standard contains most of its energy at, and near zero hertz, e.g., DC. *a sin² pulse with 0.25µs transitions So DC _is_ , and must be conveyed by analog broadcast (and other) television systems, because television wouldn't work well otherwise. It isn't DC as you may think of it coming out of a battery, but it is DC, nevertheless, and identical to battery DC of the same amplitude, when compared over equal, steady-state intervals. http://www.tek.com/Measurement/cgi-b...Set=television RF |
Richard Clark wrote:
"Dave" wrote: you will of course note that i quoted the term 'static' to denote that it was indeed not static in the infinite sense of mathematics, but in the real sense of it being a constant value over some measured time period. This is fine as an elaboration that grows beyond the horizon of the question. But it really serves no purpose but to embroider a glaring lack of facts. Perhaps the measured DC value is not the result of EM waves but the result of mechanical depositing of charge on the antenna. I assume that wind/snow static is DC - enough DC to cause arcing across a coax connector. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
Richard,
Sorry about the triple. I was so caught up in the excitement (constant throughout all time) of your message I just couldn't stop. Quote: "After having done a quite rigorous contract with HP deeply involved in both the strict math and the mechanics of Fourier, I am well versed to know how not all Fourier Transforms offer equal outcomes - especially with, or without D.C. as a product. Pure Fourier mandates a waveform constant throughout all time (from its inception to its end)" I can ignore the name-dropping, but I cannot ignore the incorrect statement about "Pure Fourier". There is no mandate of constancy even for the purest Fourier transform. The function needs only to be moderately well-behaved, including single valued and integrable. Perhaps you are confusing Fourier series analysis with Fourier transform analysis? (By the way, for any of the lurkers out there, I did not say a word about "DC". That is a trivial matter subject only to one's choice of wording. There is no apparent disagreement on the reality, only the description.) 73, Gene W4SZ Richard Clark wrote: On Sun, 06 Feb 2005 21:58:05 GMT, Gene Fuller wrote: Utter nonsense. Hi Gene, You had to post that three times? Oh well, seems the season for deeply insightful criticism that appears to be following the value of the dollar in the world market. Was that your 1½¢ worth? Barring any discussion of conflicting experience, I would say it was worth every penny. You can put it into a privatized SS account and recoup massive earnings - if the dollar would just tread water. Don't invest in cotton or rice futures though.... [Feb. 5 - President Bush will seek deep cuts in farm and commodity programs in his new budget] 73's Richard Clark, KB7QHC |
On Mon, 07 Feb 2005 14:34:38 GMT, Gene Fuller
wrote: I can ignore the name-dropping, but I cannot ignore the incorrect statement about "Pure Fourier". There is no mandate of constancy even for the purest Fourier transform. The function needs only to be moderately well-behaved, including single valued and integrable. Hi Gene, In this case you are seriously wrong. There are no IFs ANDs or BUTs. The loop hole of well-behaved is not enough with it being far too inspecific. The ONLY case where the Fourier Series resolves a correct transformation is if you limit your data set (or for an Integration, you define your limits) over an interval of n · 2 · PI for a periodic function where n is an integer from 1..m. Further, you are resolution limited if you fail to observe Nyquist's laws and under sample, or fail to frequency limit your real data. This also segues into Shannon's laws where you can observe the S+N/N in the transform (discussed below). These concerns are EXTERNAL to the simple act of transforming data, but are necessary correlatives that MUST be taken into account. If you fail even in this simple regard for periodicity (say looking at only 359 degrees of the periodic function), the result is quite dramatically different in the Fourier output. Even the casual observer can immediately see the difference between the correct and incorrect results, there is nothing ambiguous about it at all. Perhaps you are confusing Fourier series analysis with Fourier transform analysis? No, I have done both, and I will drop the name again, at HP with their work on Fourier Analysis equipment where I tested their FFT algorithms (call them what you may, the basic underlying requirements do not change). I was working with 24 Mathematicians AND Engineers - there was nothing sloppy about the quality of up-front preparation. This was a project 5 years in the making. They even wrote their own Pascal compiler for 1000000 lines of code. I have also done IIRs and FIRs, Wavelets, and a host of other frequency/time series decimation analysis. ALL Fourier techniques have requirements that go beyond the Fourier math. These requirements (if you have any interest in accuracy) cannot be ignored. If you have no interest in accuracy, you still have to perform some of them, which is to say there are trade offs as I mentioned previously. Ignoring them all simply reduces real data into transformed garbage. I have written FFT software that has resolved pure sine waves into a transformation to a single bin with a statistical noise floor and ALL spurious response down 200dB. To give an example of what 1° of decimation error will do, it will inject 120dB of noise into the product and spurs that are barely 10 to 20 dB down from the principle bin (which also exhibits about 3dB error). Much of what is available through college texts and on the web are seriously under powered in their scope. College is not very interested in scope, simply introduction. That is, unless you find yourself in a undergrad (more probably grad school with the additional considerations taken into account) engineering course dedicated to modern implementations (practical Fourier) now largely focused on DSP (which had its genesis in the IIR and FIR earlier implementations). 73's Richard Clark, KB7QHC |
Cecil Moore wrote: Tam/WB2TT wrote: "Galilea" wrote When analysing wideband impulse signals from a wideband antenna I have realised that the average signal magnitude is not zero. I have thought this is because the reactance of the antenna at different frequencies varies and since it is a wideband antenna there can be energy measured since it is only for an extremely small period of time of 2-4 us. However, I am not sure and would greatly appreciate the views of this newsgroup. Are you saying the DC value is not 0 ? He seems to be saying the DC value is not 0 for a sampling time period of 2-4 uS which would of course be true for a sine wave if, e.g., an odd number of positive cycles were sampled along with an even number of negative cycles. Or if the frequency was lower than 250 kHz. Plus all the signals and noise are superposed. Chances are fair that something is doing some rectifying somewhere. ac6xg |
Jim Kelley wrote:
Chances are fair that something is doing some rectifying somewhere. It later occurred to me that wind/snow noise is carried by static DC charged particles. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
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