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Rich Grise March 3rd 05 11:07 PM

On Thu, 03 Mar 2005 13:44:06 -0800, Richard Clark wrote:

On Thu, 3 Mar 2005 20:53:48 +0000, John Woodgate
wrote:

Doesn't everyone know that an audio amplifier that id designed to feed
an 8 ohm load MUST have an output source impedance of 0.0000001 ohms or
less.


Hi John,

I hope that was a joke.


Please! You know Mr. Woodgate _hates_ explaining his jokes:

"Doesn't everyone know that an audio amplifier that [is] designed to feed
an 8 ohm load MUST have an output source impedance of 0.0000001 ohms or
less[?] An output source impedance of 8 ohms would dramatically decrease
the electromagnetic damping on the loudspeaker voice-coil - by the huge
factor of .... two! (;-)
[^^^^]

Please notice the last sentence in that paragraph. ;-)

73's


Best regardses? ;-)

Cheers!
Rich


Richard Clark March 3rd 05 11:15 PM

On Thu, 03 Mar 2005 22:47:00 GMT, gwhite wrote:
I see one line here with no content.


Hi Forrest,

Great! Now try with the other eye. :-)

73's
Richard Clark, KB7QHC

gwhite March 3rd 05 11:15 PM

Rich Grise wrote:

On Thu, 03 Mar 2005 13:44:06 -0800, Richard Clark wrote:

On Thu, 3 Mar 2005 20:53:48 +0000, John Woodgate
wrote:

Doesn't everyone know that an audio amplifier that id designed to feed
an 8 ohm load MUST have an output source impedance of 0.0000001 ohms or
less.


Hi John,

I hope that was a joke.


Please! You know Mr. Woodgate _hates_ explaining his jokes:


Mr. Clark _hates_ reading and comprehending. I forsee a clash royal.

Richard Clark March 3rd 05 11:16 PM

On Thu, 03 Mar 2005 23:07:14 GMT, Rich Grise
wrote:

Please! You know Mr. Woodgate _hates_ explaining his jokes:


Hi Rich,

Some love explaining their jokes. I've gotten quite a bit of
correspondence to that matter already.

73's
Richard Clark, KB7QHC

gwhite March 3rd 05 11:22 PM

Richard Clark wrote:

On Thu, 03 Mar 2005 22:47:00 GMT, gwhite wrote:
I see one line here with no content.


Hi Forrest,

Great! Now try with the other eye. :-)


At least your not even pretending to have an argument anymore. Ah, sweet
progress.

Richard Clark March 3rd 05 11:29 PM

On Thu, 03 Mar 2005 23:22:07 GMT, gwhite wrote:

At least your not even pretending to have an argument anymore. Ah, sweet
progress.



Hi OM,

I suppose this means you failed the eye exam with the other eye.

73's
Richard Clark, KB7QHC

Thomas Magma March 4th 05 01:13 AM

Wow this is a long thread. Don't really know where I should put my two bits
in, but here it goes.

I have designed several RF PA sections in the past. 500MHz at about 50W.
Pretty easy stuff if you have the right tools and know how to use them. The
tools I like using for matching the power output FET is two triple stub
tuners. One on the input of the FET and one on the output. So it
goes...pre-amp (50 ohm output) - stub tuner - FET - stub tuner - 50 ohm
dummy pad - spectrum analyzer. Then just tune the stubs for the performance
you desire, these include: efficiency (thermal issues), harmonic content,
spurious emissions, load VSWR considerations, cold start, ect. Then remove
the FET and look into the triple stub tuners with the network analyzer.
Model and duplicate the network out of discrete components that can handle
the voltage/power, send the design off to the enviro test lab, and head home
early for the day.

Cheers,
Thomas

"gwhite" wrote in message
...
Richard Clark wrote:


As I've noted in the past, you can fill a library with negative
assertions...


The troublesome assertion is not the negative one. It is that RF PA's are
conjugate matched. Neither you nor Ken has provided a single example of

such a
design that also extracts the maximum amount of "linear" power from a

device and
essentially its power supply (after all, that is what it is: a _power_

amp).
Your example said nothing about output-Z, which suggests you have no clue,

since
you didn't even remotely address the issue.

For Ken's part, he recently obfuscated by dismissing an example that was
primarily intended to be illustrative, but yet holding the salient points.

He
completely ignored (or didn't understand) the clipping issue. Further
obfuscation was provided by talking about "protection circuitry," which

may or
may not exist in a circuit, but adds zero to a discussion regarding how

the PA
is to be loaded. "Protection" is a non-stater because the PA is either

off or
impaired.

Ken's argument is circular. He say's that if a design is done for

conjugate
match,
then it will behave as if it is conjugately matched. Well of course (or

at
least sort of under specific test conditions and circuits)! It is
self-fullfilling prophecy but it unfortunately makes no statement

regarding
obtaining the maximum power out of the circuit in the sense of turning DC

power
into RF power (yes, *extracting* power from the DC supply and transformed

to
RF). This is paramount to PA design. To use the device to maximum

efficacy, as
Cripps puts it, a load-line match is needed. Ken's "conjugate match"

design
won't do that, and that's why PA's aren't designed that way.

The bottom line is that if I design an amp via load line techniques using

the
same device and power supply as Ken (him using conj-match), my amp will

deliver
higher unclipped PEP than his. That is the factual result you resist.

Now if
you want to pay for extra power and big devices, that's your business--go

ahead
and attempt to conj-match your amp--but engineers who design PA's don't do

that.

Another idealized and hypothetical example to elucidate the load-line

principle
is offered.

Let's say we have a 10 W FET we'll build into a class A circuit. An RF

choke is
used to supply drain current. We DC bias it to Vd = 10 V and Id = 1 A.

Just
for argument sake, let's say it has a constant internal resistance of 110

ohms
and the device will break down at 25 V. According to the most idealized

and
standard load-line theory, we should load it to rL = Vd/Id = 10 Ohms.

This
idealization includes the definition of positive and negative clipping --
whichever comes "first" -- of being the operational limit for output

voltage
swing. Clipping is associated with severe distortion.

Since we need rL to be 10 ohms, and Ri = 110 ohms, we need to make the

actual
load resistor equal to: RL = 11 Ohms. Let's check that result and see if

it
meets the clipping constraint for maximum available power.

positive swing = Id*rL = 1*10 = 10 V
negative swing = Vd = 10 V
Power delivered to RL: Pload = 10^2/(2*11) = 4.55 W
The efficiency is a little under 50% because of the internal resistance.

Note
the Load resistance is decidely not the conjugate of the internal

resistance.

Let's spot check the load to see if it at least appears to be the peak

available
power, by testing two loads "immediately" on either side of our optimum 11

ohms.

Let RL = 10 ohms
positive swing = Id*rL = 1*9.17 = 9.17 V
negative swing = Vd = 10 V
Since we positive clip at 9.17 V, we are limited by our design clipping
constraint to only driving the PA such that 2*9.17 V is the maximum

available
voltage swing.
Power delivered to RL: Pload = 9.17^2/(2*10) = 4.20 W

Let RL = 12 ohms
positive swing = Id*rL = 1*10.82 = 10.82 V
negative swing = Vd = 10 V
Since we negative clip at 10 V, we are limited by our design clipping

constraint
to driving the PA such that 2*10 V is the maximum available voltage swing.
Power delivered to RL: Pload = 10^2/(2*12) = 4.17 W

Sure enough, the power peaked at a load of 11 ohms, just like load-line

theory
says it will. Now let's see what the available power hit of conjugate

matching
is.

By definition, conj-match insists RL = Ri = 110 ohms. Again we are

limited in
our clipping constraint by static drain current, and supply voltage,
specifically 10 V.

Our negative swing limit is, as ever, 10 V (the drain voltage).

positive swing = Id*rL = 1*55 = 55 V

This would breakdown the device, but the lower negative swing will force

us to
back down the drive to meet the design defined clipping constraint.

Pload = 10^2/(2*110) = 0.455 W

Conjugate matching resulted in a 10*log(0.455/4.55) = 10 dB available

power
hit. Power amplifiers are not designed with conjugate matching in mind.

You
don't need to re-invent the wheel. Just follow well established

principles when
doing cookie cutter PA design.

The list could go on,...


LOL. Given your pattern, I am sure it will.

You sighed with content at being offered a "relevent
question/statement" Your re-iterative response contains the same (how
could it be otherwise?) slack of precision that started this. Want to
try again?


Not really. The problem isn't precision, it is you can't, or refuse, to
comprehend what is being said, which I presume is why you instead write

with the
most bizarre terms and phrasology that has nothing of import to the topic

at
hand.

You could have as easily expressed what sense they ARE matched,


For what seems like the billionth time now: they are load-line matched.

...but instead this time offer what Basis
of Matching you are attempting to
describe.


I've given a didactic example (actually a couple), you just don't--or more
likely won't--get it. If you don't like my example, you can refer to

Cripps,
who is considered one of the preeminant RF PA experts in the world.

Even more simplistic is Malvino's discussion on pp177-185 of the first

edition
((c) 1968) of "Transistor Circuit Approximations." It is basically a

technician
level description, so perhaps it is well-suited to you. In academics,

load-line
theory is presented down to tech level courses and up across to

engineering.
That some engineers and techs aren't clear on the load-line concept for

PA's (or
*any* circuit needing a wide symmetrical swing) is notwithstanding.

This is the more rigorous approach that eliminates vague
descriptions and uses standard terms. If you have to query about what
"Basis" means (used by professionals - namely metrologists who can
quantify Output Z of all sources) - then we can skip it as a topic out
of the reach of amateur discussion.


I see you still don't know what impedance is. In any case, it doesn't

mean that
looking into a properly designed PA output with a network analyzer

confirms the
conj-match precept, it doesn't.

Impedance is a *linear* conception, a portion of linear theory, and again

by
definition:

Z = V/I

V and I are sinusoids (phasors). But with power amps, substantial

non-linearity
exists (destroying the linearity assumption of impedance), thus applying a
linearly defined concept to a non-linear milieu is a misapplication. You

are
attempting, as is Ken, to stuff a square peg down a round hole. Why?

The concept is even questionable for the most linear of the power amps:

class
A. In any case, given real devices with real supplies, the conj-match

ideal is
next to worthless. While I could agree that the borderline may be fuzzy
regarding where and when to drop the impedance notion, it still stands

that the
concept is not useful in determining how to optimally load an RF PA.

At this point you own the conj-match assertion as much as Ken. Prove it!

You
can't because it is fundamentally incorrect.

Note:
Again, RF PA's should be load-line matched.

Does not qualify as a Basis.


Load-line matching is such a basic electronic concept it is unbelievable

how
oblivious you are to the concept. Read a basic book. Don't rely on me:

look it
up and do your own design!

It is suggestive of one, but because you indiscriminately
mix several Basis within your discussions, it is your
responsibility to be precise.


You just like to hear yourself talk. I've been explicit and precise. You

just
don't know anything about the elementary electronics principle of load

line
matching. I presume this is why your comments have zero substantive
responsiveness.

If you can accomplish this, then we can
proceed to review how little it all matters.


If you keep ignoring what I've written, and that which is written in

elementary
electronics texts, you can remain happily ignorant of understanding the
simple-basic-fundamental concept presented. Your choice.

Barring resolving any of these issues of precise language,...]


The guy ignorant of the definition of impedance and that s-domain theory

*is*
linear circuit theory (and more goodies) is talking about "precise

language."
Amusing.

I notice
that you rather enjoy...


No, I don't enjoy it at all. Your lack of electronic understanding is

dismal,
especially given your tone. It would have been a lot easier for me if Ken
hadn't made the erroneous
statement in the first place and made a correct one instead. That would

have
been my preferance.

..fruitless jousting with them than challenging my
support of Ken's (supposed) statement that you say is your focus:
However, responding to the bald statement, I find nothing
objectionable about it.

That's because you don't understand the difference between impedance

matching
and ac load line matching.

We will leave that as another dead-end.


I suspect you will. I already understand it -- you're the one who

doesn't.


"One of the principal differences between linear RF amplifier design and

PA
design is that, for optimum power, the output of the device is not

presented
with the impedance required for a linear conjugate match. That causes much
consternation and has been the subject of extensive controversy about the
meaning and nature of conjugate matching. It is necessary, therefore, to

swallow
that apparently unpalatable result as early as possible (Section 1.5),

before
going on to give it more extended interpretation and analysis (Chapter

2)." --
Cripps, p1


The quote is on Page 1. Swallow it now. Learn something for a change.




gwhite March 4th 05 01:57 AM

Richard Clark wrote:


I suppose this means you failed the eye exam with the other eye.


There's no need for supposition. You don't know anything about PA design. You
demonstrated that clearly enough for a blind person to see.

Tom Ring March 4th 05 02:56 AM

Richard Clark wrote:

On Thu, 3 Mar 2005 20:53:48 +0000, John Woodgate
wrote:


Doesn't everyone know that an audio amplifier that id designed to feed
an 8 ohm load MUST have an output source impedance of 0.0000001 ohms or
less.



Hi John,

I hope that was a joke.

73's
Richard Clark, KB7QHC


I think he just meant that damping factor is important in an audio amp.

At least I hope that's what he meant.

He forgot to mention that for that output impedance to be relevant, you
need superconducting wire to the speakers as well as superconducting
voice coils.

tom
K0TAR

Richard Clark March 4th 05 06:09 AM

On Fri, 04 Mar 2005 01:57:06 GMT, gwhite wrote:
I suppose this means you failed the eye exam with the other eye.

There's no need for supposition.


Hi OM,

I thought not.

73's
Richard Clark, KB7QHC


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