Cecil Moore wrote:
Richard Harrison wrote:

I`ll use Cecil, W5DXP`s argument. Energy must be conserved. Energy in
equals energy out. If some goes to a load it does not stay within the
amplifier to make heat.


From "Electronic Fundamentals and Applications" by
John D. Ryder, regarding Class-A amplifiers:
"As the a-c output increases, the plate loss
decreases and the tube runs cooler."


This is why the load must be matched to the amp. Anyone who has fried a
final will tell you so.
Been there, Done that, Got the bottles to prove it.

Dave WD9BDZ