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Old March 2nd 05, 01:42 PM
Cecil Moore
 
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Asimov wrote:
In fact the power difference is
always zero, so there is no reason for the device to cool.


Here's the reason the device cools under load.

Plate loss = Eb*Ib - Ip^2*RL

With no signal, the plate loss is Eb*Ib. When
the signal is increased from zero, any power
delivered to the load is subtracted from Eb*Ib,
thus causing the device to cool.
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73, Cecil http://www.qsl.net/w5dxp


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