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#61
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![]() The formula for z which you gave would give me nightmares. Are you absolutely sure that what you have written is correct? Perhaps first principles was overstated n my posting Art "Richard Clark" wrote in message ... On Fri, 11 Mar 2005 23:05:28 GMT, " wrote: A cardioid pattern has radiation in the 180 degree portion behind the feed point first described by Johann Castillon made a Fellow of the Royal Society of London in 1753: r = 2a(1 + cos(theta)) where theta = 180 such that: r = 2a(1 + cos(180)) r = 2a(1 + -1) r = 0 Hi Art, Understandably, the term you are so unfamiliar with, insofar as no rearward radiation (not the same as no radiation to 180 degrees) is Lambertian. As may be expected, the term is derived from the work of mathematician Johann Heinrich Lambert (1728-1777). It is a distribution curve derived from reflections off of a "diffuse surface" (note, not the same thing as reflections off of a specular antenna element): (x²+y²+z²)² = z At 300 years+ both are pretty old works that each easily qualify within the purview of "first principles" if one is serious about radiation. 73's Richard Clark, KB7QHC |
#62
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I wrote:
"However, there is a measured by D.C. Glockner of Ohio State University pattern of the 3-element Yagi-Uda with more than 7 dB gain and almost zero radiation from the direction of 180-degrees from the maximum. It is on page 246." No correction required but I should add that the book is the 3rd edition (2002) of "Antennas" by John D. Kraus et al. Best regards, Richard Harrison, KB5WZI |
#63
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I did rotate it and placed it on the ground, the gain dropped
by 4db and the circular lobe pointed straight up. Some time I will look at same at 1 WL Art "Cecil Moore" wrote in message ... wrote: If the phases and and magnitudes of the paired elements are exactly the same, then radiation to the rear is zero. If you rotate the elements by 90 degrees, can you make the radiation toward the ground zero? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#64
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On Sat, 12 Mar 2005 00:38:31 GMT, "
wrote: The formula for z which you gave would give me nightmares. Hi Art, That is the Cartesian form. A 2D polar form would follow: I = I0 · A · cos (phi) · cos (theta) / Pi where I is the intensity at a point with elevation theta A is the area of the surface I0 is the radiation directed normal to a diffuse surface phi is the angle of incidence (all angles being considered) A variant for conforming radiators is found in: I = I0 · cos (theta) Observation will reveal why this is called Lambert's Cosine Law. Simple draughting techniques will reveal the circular distribution curve. A simple example of the last equation is found in the common, unlensed LED. Insofar as radios go, I expect the same response would follow from placing an isotropic source above a diffuse reflector (you would then have to use the first equation). 73's Richard Clark, KB7QHC |
#65
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wrote:
A cardioid pattern has radiation in the 180 degree portion behind the feed point You want zero radiation in an entire hemisphere? Arecibo probably meets that specification. :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#66
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Yup.
They have now upgraded the mountain road so you don't have to take a spare rear axle with you now. Art "Cecil Moore" wrote in message ... wrote: A cardioid pattern has radiation in the 180 degree portion behind the feed point You want zero radiation in an entire hemisphere? Arecibo probably meets that specification. :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#67
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But that formula for z does not appear to be correct!
Art "Richard Clark" wrote in message ... On Sat, 12 Mar 2005 00:38:31 GMT, " wrote: The formula for z which you gave would give me nightmares. Hi Art, That is the Cartesian form. A 2D polar form would follow: I = I0 · A · cos (phi) · cos (theta) / Pi where I is the intensity at a point with elevation theta A is the area of the surface I0 is the radiation directed normal to a diffuse surface phi is the angle of incidence (all angles being considered) A variant for conforming radiators is found in: I = I0 · cos (theta) Observation will reveal why this is called Lambert's Cosine Law. Simple draughting techniques will reveal the circular distribution curve. A simple example of the last equation is found in the common, unlensed LED. Insofar as radios go, I expect the same response would follow from placing an isotropic source above a diffuse reflector (you would then have to use the first equation). 73's Richard Clark, KB7QHC |
#68
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On Sat, 12 Mar 2005 03:15:42 GMT, "
wrote: But that formula for z does not appear to be correct! Hi Art, As I said, you are not working in Cartesians in the first place with "polygons." It is a formula for computer generation of the surface. If you absolutely need to understand the formula, read through the code that is used to construct the distribution curve: #define sz 2000000 #define bc 19 static double fr() {return rand()/(double)~(131);} static double sq(double x){return x*x;} int hi[bc]; int out=0; int main(){ {int j=bc; while(j--) hi[j]=0;} {int j=sz; while(j--) { double x = fr()*1.4-.7, y=fr()*1.4-.7, z=fr(); if(sq(x*x+y*y+z*z) z) { ++hi[(int)(z/sqrt(x*x+y*y+z*z)*bc)];} else ++out;}} {int j; for(j=0; jbc; ++j) printf("%d %d %8.2f\n", j, hi[j], (sz-out)*(j+.5)/(bc*bc/2));} printf ("%d out of box.\n", out); } If you still don't understand, the polar coordinate formulas are just as useful, simpler, and take very little work to construct a "polygon" that obtains complete closure. It is, after all, a construction much like any of a number of classic curves. You need only conform to the requirements of a Lambertian surface or emitter to obtain the curve you describe. 73's Richard Clark, KB7QHC |
#69
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Put the antenna half way up and a small part broke!
Have put the antenna to one side and I will pick it up again during the summer Regards Art " wrote in message news:dySVd.30807$r55.174@attbi_s52... I have just come to realise that if one drew a polygon of element phases in a array and all elements were 180 degrees to its companion element and excluding the driven element, the max gain and max front to back will occur at the SAME frequency! Until now I was of the understanding that these two max figures could not occur at the same frequency. Is there anything written about this possibility? Regards Art |
#70
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Gene Fuller wrote:
Art, Why not? The cardioid pattern from a two-element array was reported back as least as far as 1937, by the famous George H. Brown. In the ideal case (free space, no losses, etc.) the radiation directly to the rear is precisely zero. If you add various real world effects then the back lobe is not precisely zero, and this is shown in the ARRL Antenna Book referenced by Cecil. . . . Actually, this isn't quite true. If you manage to get perfectly phased and equal magnitude currents in two identical elements where the phase angle equals 180 degrees minus the element spacing (such as the classic 90-degree fed, 90-degree spaced cardioid), you don't get an infinite front-back ratio. In the case of the cardioid with typical diameter quarter wavelength elements, you end up with around a 35 dB front/back ratio. With longer elements, close to a half wavelength, the front/back ratio can deteriorate to less than 10 dB when base currents are identical in magnitude and correctly phased. The reason is that the mutual coupling between elements alters the current distribution on the elements. The mutual coupling from element 1 to element 2 isn't the same as the coupling from element 2 to element 1 (the mutual Z is the same, but the coupled voltage and coupled impedance aren't). The net result is that the two elements have different current distributions, so despite having identical magnitude base currents the two elements don't generate equal magnitude fields. The overall fields from the two elements end up being imperfectly phased, also. This occurs for theoretically perfect and perfectly fed elements, and isn't due to "real world" effects. I published some comments about this effect in "Technical Correspondence" in July 1990 QST ("The Impact of Current Distribution on Array Patterns"). I'm certainly not the first to have observed it -- some papers published as early as the '40s are referenced in my article. But I had never seen its effect on front/back ratio of cardioids mentioned before. Modern versions of the ARRL Antenna Book clearly show the small reverse lobe of a typical antenna with quarter wavelength elements. I stumbled across it when doing some modeling with ELNEC, the predecessor of EZNEC, and originally thought it was an error in the program. You'll see it in a plot from the Cardioid.EZ EZNEC example file (which is also included with the demo program), and a brief explanation in the corresponding Antenna Notes file. A theoretically infinite front/back ratio can be achieved by modification of the base currents. The amount of modification required depends on the length and diameter of the elements. Only a small modification is needed if elements are a quarter wavelength high and small diameter, but in that case, real world effects will probably have at least as much and likely more of an effect on the front/back than the current distribution phenomenon. Rather drastic modification is required of the base currents of elements approaching a half wavelength high, however, as elaborated in the "Technical Correspondence" piece. Roy Lewallen, W7EL |
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