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Yuri Blanarovich wrote:
In a nutshell, I (and W9UCW, etc.) found that current diminishes accross the coil. W8JI using Kirchoff and Ohm says it can't. If you put a loading coil 1/3 of the way up on an end-fed 1/2WL vertical, the net current will increase across the coil. The net current can decrease, or increase, or be the same magnitude for special cases. Think Ifwd+Iref with the coil causing major phase shifts. Open-ended antennas like dipoles are standing wave antennas. The forward current is relatively constant through the coil and the reflected current is relatively constant through the coil. But the phasor sum of those two currents can vary wildly from end to end in the coil because of phase shifts. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#2
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Open-ended antennas like dipoles are standing wave antennas. The forward current is relatively constant through the coil and the reflected current is relatively constant through the coil. But the phasor sum of those two currents can vary wildly from end to end in the coil because of phase shifts. -- 73, Cecil http://www.qsl.net/w5dxp Don't we have a case of coil being RF choke to certain extent? Also I think that behaviour of radiator before and after the coil defines the magnitude of the current, no? Yuri, K3BU |
#3
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Yuri Blanarovich wrote:
Open-ended antennas like dipoles are standing wave antennas. The forward current is relatively constant through the coil and the reflected current is relatively constant through the coil. But the phasor sum of those two currents can vary wildly from end to end in the coil because of phase shifts. Don't we have a case of coil being RF choke to certain extent? RF chokes are usually high enough impedance to drop virtually all the RF voltage across the choke. Also I think that behaviour of radiator before and after the coil defines the magnitude of the current, no? It can be thought of as a very lossy transmission line where the loss is radiation. Please see my other posting comparing a 1/2WL dipole to a loaded dipole. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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