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Cecil Moore wrote:
Ian White, G3SEK wrote: Cecil Moore wrote: OK, let's agree on that and take another look at the example I just presented on another thread involving half a dipole. wire coil wire ---------------////--------------- 22.5 deg ? deg 22.5 deg Assuming a lumped inductance, presumably the current into the coil will have the same phase as the current out of the coil. Zero phase shift through the coil means this antenna has the same current phasing as a 40m dipole used on 75m, i.e. the feedpoint current is at a current minimum point. Sorry, I don't understand that last statement... A 40m 1/4WL vertical used on 40m is 90 degrees long. A 40m 1/4WL vertical used on 80m is 45 degrees long and we know its characteristics. If the coil above has zero phase shift, the antenna above is also 45 degrees long and will exhibit the feedpoint characteristics of a 40m 1/4WL vertical used on 80m but we know it doesn't exhibit those characteristics. ERGO, the phase shift through the coil is not zero. OK, I see what you're getting at, but by changing the frequency you are losing sight of some important points. Let's stay on the *same* frequency, halve the physical height of the antenna and insert a lumped loading coil at the midpoint. Instead of being 90deg tall, our vertical monopole is now only 45deg tall (physically). Drawn on its side, and fed against ground at one end, it now looks like: wire coil wire ---------------////--------------- 22.5 deg ? deg 22.5 deg (just as you drew it) Where you're going astray (I suspect) is in believing that the coil literally "replaces" the 45deg of antenna that was lost when we halved the height. It doesn't - the loading coil drastically changes the current distribution. Fed with 1.0A at the base, the original quarter-wave has a roughly cosine-shaped current distribution, so the current at a point 22.5deg from the top is 1A * cos(90-22.5) = 0.38A. Now feed the loaded antenna with 1.0A at the base. The current distribution is now radically different: in the bottom 22.5deg of the antenna, the current hardly changes - let's say it's 0.9A at the bottom of the loading coil. Since we have assumed a lumped loading coil, the current at the top of the coil is the same 0.9A. But now the current distribution in the top 22.5deg is very different from the full-size case: it tapers much more sharply, from 0.9A down to zero at the very top. This is all standard stuff. My reason for walking through it is to emphasize that shortening the antenna and loading it changes many things about the current distribution, both above and below the loading coil. And here are two other important differences: the feed impedance of the loaded antenna is much lower than that of the full-size; and the much sharper reduction in current is associated with a much higher E-field over the same length of top section. To sum up, shortening and loading the antenna creates so many important differences that you're misleading *yourself* if you say that the loading coil simply "replaces" the missing length of antenna. Two footnotes: 1. The diagram for current distribution with center loading in 'Low Band DXing' is based on the same incorrect assumption that loading coil somehow fully "replaces" the missing 45deg of antenna. (Fortunately the method later in the same chapter for calculating the inductance of loading coils is still OK, because it doesn't depend on any assumptions about current distribution.) 2. I haven't thought about an answer to Cecil's problems of what happens to the "missing" 45deg, and what happens to the forward and reflected waves of voltage and current. Since it's Cecil who chooses to think about antennas in such ways, he'll have to solve his own problems! My only point is that a correct solution can *not* involve a difference in the currents at the two ends of an idealized lumped inductor. Such a difference simply cannot be... so the true solution will be that bit harder for Cecil to find. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
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