Bob, W9MDK wrote:
"The above paragraph, however, was a rather difficult to ubderstand
reading,---."

I responded that the load would not accept volts and amps in a ratio
which does not fit its load impedance. Perhaps we should reason together
some more. The transmission line delivers power to the load at its Zo.
When the load impedance is different, there is a surplus of either volts
or amps. The surplus nust be reflected because the load can`t take it.
That`s all.

Best regards, Richard Harrison, KB5WZI

On Sun, 26 Jun 2005 19:31:17 -0500, (Richard
Harrison) wrote:

Bob, W9MDK wrote:
"The above paragraph, however, was a rather difficult to ubderstand
reading,---."

I responded that the load would not accept volts and amps in a ratio
which does not fit its load impedance. Perhaps we should reason together
some more. The transmission line delivers power to the load at its Zo.
When the load impedance is different, there is a surplus of either volts
or amps. The surplus nust be reflected because the load can`t take it.
That`s all.

Best regards, Richard Harrison, KB5WZI


Dear Richard,

Actually, your previous response was much more than I really expected.
I just wanted to see different wording on the original paragraph.
You've done a good job, and I hope everyone took good notes - Hi!

Bob, W9DMK, Dahlgren, VA
Replace "nobody" with my callsign for e-mail
http://www.qsl.net/w9dmk
http://zaffora/f2o.org/W9DMK/W9dmk.html

Bob, W9MDK wrote:
"Actually, your previous response was much more than I expected."

Bob Lay is a well known designer and author. I appreciate his criticisms
and comments as I appreciate those of Cecil, Ian, Richard C., Walter,
and others. I make mistakes and typos, but can`t blame the shakes. My
problems are fuzzy sight and forgetfulness. I`ve never taught, or
written for magazines or books. I`m just a perpetual student. I`ve
learned a lot here.

Thank you to all of you who have taught me much. I always read what Reg,
Roy, and Wes have to say. They are rich information sources. There are
many more great contributors, but I could not begin to name them all.

Some of the conflicts are roll on the floor funny. I thoroughly enjoy
them as an observer. Thanks for the memories.

Best regards, Richard Harrison, KB5WZI

Richard Harrison wrote:
Bob, W9MDK wrote:
"The above paragraph, however, was a rather difficult to ubderstand
reading,---."

I responded that the load would not accept volts and amps in a ratio
which does not fit its load impedance. Perhaps we should reason together
some more. The transmission line delivers power to the load at its Zo.
When the load impedance is different, there is a surplus of either volts
or amps. The surplus nust be reflected because the load can`t take it.
That`s all.

Another way of saying the same thing:

The mismatched load rejects voltage in the form of Vref and rejects
current in the form of Iref. Thus Vload is the phasor sum of Vfor
and Vref. Iload is the phasor sum of Ifor and Iref. The
result is that (Vfor+Vref)/(Ifor+Iref) = Zload.

If Z0 and Zload are purely resistive and Zload Z0 then:

Zload = (Vfor+Vref)/(Ifor-Iref)

Vfor and Vref are in phase, Ifor and Iref are 180 deg out of phase,
because we need a higher voltage and a lower current for RL Z0.

If Z0 and Zload are purely resistive and Zload Z0 then:

Zload = (Vfor-Vref)/(Ifor+Iref)

Vfor and Vref are 180 deg out of phase, Ifor and Iref are in phase,
because we need a lower voltage and a higher current for RL Z0.
--
73, Cecil http://www.qsl.net/w5dxp

----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==----
http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups
----= East and West-Coast Server Farms - Total Privacy via Encryption =----