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#1
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Cecil Moore wrote:
And if you will remember, the original question didn't involve the SWR meter at all. The question was: Are my 2-foot sections of RG-400 connected to my SWR meter long enough to ensure that the SWR meter reading is valid for the coax? Remember that argument? The threads for the past few days have all diverged from that original question which was: How long must the 50 ohm coax connected to the SWR meter be for the SWR meter to report a valid SWR *on that coax*? The answer obviously cannot be zero length. Cecil, What has become quite clear from this lengthy thread and the experiments reported is that what you seek is impossible. The design and physical configuration of the Bird 43, and probably most or all simple SWR meters, is such that the measurement is completely unaware of the external "environment". The Bird 43 correctly reports system mismatch, such as that from a load that differs from 50 ohms, but it ignores any artificial mismatch from the adjacent coax. A report of the valid SWR *on that coax* will happen only by coincidence. The meter does not care about the length. Zero is just as good an answer as any other length. And who would really care to know such a thing? The unknown of interest is generally a load or matching device, not the improper coax. If you really need to know the "valid SWR" on the mismatched coax you are going to need a different technique and instrument. 73, Gene W4SZ |
#2
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Gene, W4SZ wrote:
"The unknown of interest is generally a load or matching device, not the improper coax." Bird says: "The Model 43 THRULINE Directional Wattmeter is a portable insertion-type instrument which accurately measures forward or reflected power in coaxial transmission lines under any load condition." I accept the above description as I`ve seen confirmation under many conditions. Bird also says: "Line section: The line section is a high precision 50 ohm coaxial air line designed for transmission line insertion between the transmitter and the antenna or load. A socket is provided in each line section for the plug-in element with the desired power rating and frequency range." The width of the instrument including connectors is given as 4.25 inches. This makes the preciaion coax section longer than its width or spacing. I conclude from this that it is capable of enforcing its 50 ohms. Bird mentions cable lengths in regard to VHF measurements. They suggest that insertion and removal of the 43 with random length cables attached may affect the load match unless it is made exactly a total of 1/2-wavelength. In the 1/2-wave case, insertion and removal have no effect on the load match. I`ve done this countless times and attest to its effectiveness. If there were other possible problems with Bird cable lengths, they would have appeared during the past 50 years and been reported. Best regards, Richard Harrison, KB5WZI |
#3
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Gene Fuller wrote:
What has become quite clear from this lengthy thread and the experiments reported is that what you seek is impossible. Not true. The question has been answered and it surprised me. Only a half inch or so of ordinary 50 ohm coax is required to ensure the SWR on that half inch of coax is the same as the SWR reported by the SWR meter. I didn't ask the original question in a very understandable manner because I don't know of anyone who understood my original question. And who would really care to know such a thing? History: Reg and I were arguing about a year ago whether two feet of RG-400 was long enough to ensure that the SWR reported by the SWR meter was the same as the SWR on the RG-400. I said it was but had no references that covered the subject so had no proof. There was no answer to my question forthcoming from this newsgroup at the time, so I asked the question over on sci.physics.electromag. I received an answer on that newsgroup but, unfortunately, didn't question the math. The answer was one foot of RG-213 but the answer was off by a magnitude due to an accidental shift in a decimal point. The correct answer was about an inch to reduce the undesired mode by a factor of 1/e^5, i.e. 1/0.2=5 where 0.2 is the conductor spacing, e.g. estimated for RG-213. The error was caused by using 2" instead of 0.2" as the conductor spacing. I mistakenly ran with the one foot answer but, wrong as it was, proved that my two feet of RG-400 was long enough. Now Dave has set the record straight and caused the decimal point error to be exposed by Owen and me at about the same time. The correct answer is surprising to me. 1/2 inch of ordinary 50 ohm coax is enough to ensure a 50 ohm environment in that 1/2 inch piece of coax, i.e. to ensure Vfor/Ifor=Vref/Iref=50. Nobody else may care, but I learned a lot and thank everyone who contributed. -- 73, Cecil http://www.qsl.net/w5dxp |
#4
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On Mon, 17 Oct 2005 16:27:33 GMT, Cecil Moore wrote:
I didn't ask the original question in a very understandable manner makes sense so far, and consistent too. because I don't know of anyone who understood my original question. well -um- it's still consistent |
#5
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"Cecil Moore" wrote
I mistakenly ran with the one foot answer but, wrong as it was, proved that my two feet of RG-400 was long enough. ======================================= Cecil, bearing in mind Lord Kelvin, can you say what the error in the measured value of the SWR, or the reflection coefficient, would be if the (sufficient) two feet of RG-400 was reduced to 1" inch. ---- Reg. |
#6
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Reg Edwards wrote:
"Cecil Moore" wrote I mistakenly ran with the one foot answer but, wrong as it was, proved that my two feet of RG-400 was long enough. Cecil, bearing in mind Lord Kelvin, can you say what the error in the measured value of the SWR, or the reflection coefficient, would be if the (sufficient) two feet of RG-400 was reduced to 1" inch. According to Dave's calculations, 1" of 50 ohm coax will result in a negligible error in the SWR on that 1" of coax. -- 73, Cecil http://www.qsl.net/w5dxp |
#7
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On Mon, 17 Oct 2005 18:49:49 GMT, Cecil Moore wrote:
According to Dave's calculations, 1" of 50 ohm coax will result in a negligible error in the SWR on that 1" of coax. Negligible for you, is brighter than the sun for everyone else. No numbers, hmm? |
#8
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Richard Clark wrote:
Cecil Moore wrote: According to Dave's calculations, 1" of 50 ohm coax will result in a negligible error in the SWR on that 1" of coax. Negligible for you, is brighter than the sun for everyone else. When reflections are completely canceled, appear to have disappeared from everyone else's sight, and you say they are brighter than the sun (for you), who am I to argue? You have created your own unreality and everyone who understands the physics of 1/4WL thin-films in this universe laughs at you every time you post that "brighter than the sun" nonsense. In your calculations, you superposed powers which is not a valid thing to do and you apparently haven't even comprehended the error of superposing powers. No numbers, hmm? Dave provided the numbers. Check his posting. Simply stated: The unwanted mode is attenuated by 1/e with each increment of length equal to the spacing between the two conductors. If the conductor spacing is 0.1", the unwanted mode is down to 0.00000001% in one inch. That's a big surprise to me but I don't see any reason not to believe it. -- 73, Cecil http://www.qsl.net/w5dxp |
#9
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On Mon, 17 Oct 2005 19:13:38 GMT, Cecil Moore wrote:
everyone who understands the physics of 1/4WL thin-films in this universe laughs at you every time you post that "brighter than the sun" nonsense. Just how big IS your universe? |
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