Home |
Search |
Today's Posts |
#13
![]() |
|||
|
|||
![]()
On Tue, 29 Nov 2005 15:02:15 GMT, Cecil Moore wrote:
Reg Edwards wrote: You then include in the calculation the measurement or assumption of the Zo of the 50-ohm coax, and the measurement or assumption of Zo of the twin-line, and the forward and reverse powers, and the SWR on the twin line can be deduced or assumed. Actually, nowadays I use my MFJ-259B to read the resistance at the choke-balun where I have adjusted the ladder-line length to guarantee the existence of a current maximum point. It's actually easier to do than to write about it. An assumption that Z0=50 ohms is not necessary. But if you think you are measuring SWR on anything you are cheating and fooling yourself. I actually have an SWR meter calibrated for balanced 380 ohms but it's in a box somewhere in my garage. I found my indirect measurements to be entirely accurate enough. In general, if one can isolate the problem to 10% of the Smith Chart, one can solve any problem by tweaking. Speaking of indirect measurements - let's say the feedline Z0 is 380 ohms with a VF of 0.9 and a length of 90 ft. The measured resistance at the current maximum point is 30 ohms on 7.15 MHz. The SWR on the ladder-line is 380/30 = 12.7:1. The feedline is 0.727 wavelengths long. Plot the point 30/380 = 0.079 + j0 on a Smith Chart. Draw an SWR circle through that point. Backtrack from that point around the circle for 0.727 wavelengths and there's your antenna feedpoint impedance (neglecting losses). Losses can be taken into account by using SWR spirals instead of SWR circles. And of course, all of this is done by a computer program after just a few seconds of data entry. So what is the answer to your example, the load Z, with and without consideration of the losses? -- |