After reading this thread it seems there is significant confusion between E and
H fields created locally from electric current and the E and H aspects of a
passing RF photon stream. It is easy to see how this can occur. That said the
tools for working with them are entirely different.

E and H fields from capacitors, inductors, and transformers are predominantly
local effects. Photons are not involved, they are created by electric current
and are explained by Maxwell equations. They can be created separately, that is
a capacitor is pretty much a pure E field and an inductor an H field, albeit
none of these are perfect. Photons are not involved in the operation of a

On the other hand EM waves and photons which are RF waves and visible light and
beyond are entirely different. Although they are referred to as
electro-magnetic, they are in fact massless particles with a well defined energy
that is a function of frequency. These particles, traveling at the speed of
light, create what is referred to as RF including RF fields. The E and M
components cannot be separated. Antennas are devices which convert RF currents
into photons for transmission and to convert photons into RF currents on
reception, all this at the frequencies we are mostly interested in.

These are two very different physical constructs. Now at RF frequencies -
Faraday shields are local electrical devices, they have nothing to do with
photons and antennas. (Although they may be effective at blocking their
passage.) Electric currents in equipment create both E and H fields. These
fields are not associated with photons and can be separated. Faraday shields are
a way to block the E portions of those local fields while allowing the passage
of the H.

Dan

Roy Lewallen wrote:
*Sigh*

Richard Harrison wrote:

Roy Lewallen, W7EL wrote: "A short while ago, I explained why your
Faraday cage doesn`t separate the E and H fields as you claim." n I
am misunderstood. I never used the tem Faraday cage. I understand the
Faraday cage to be a completely shielded enclosure which could be a
metal automobiole body, a steel rebar reinforced concrete structure
or a screened room. These all tend to completely block both the
E-field and the H-field components of an electromagnetic wave.


Sorry, I meant "Faraday screen", which is the term you used, and I used
in my posting explaining its operation.

If you block either the E or H field, you also block the other. You
can't independently block one or the other.

. . .


Why would one pay a lot of extra money for a transformer which
eliminated capacitive coupling if it didn`t work, especially in
Havana, Cuba?


Because in order to "work" it doesn't need to "eliminate capacitive
coupling". All it needs to do is locally reduce the E/H field ratio,
which is what it does.

Roy Lewallen, W7EL