RadioBanter

RadioBanter (https://www.radiobanter.com/)
-   Antenna (https://www.radiobanter.com/antenna/)
-   -   Radiation Resistance (https://www.radiobanter.com/antenna/90399-radiation-resistance.html)

Reg Edwards March 13th 06 03:04 PM

Radiation Resistance
 

"Roy Lewallen" wrote

C = 160 * pi^2 ~ 1579.


====================================

Thank you Roy.
----
Reg



Richard Harrison March 13th 06 03:07 PM

Radiation Resistance
 
Owen Duffy wrote:
"Is that correct---?"

No, I don`t think so.

Kraus` formula is:
Radiation resistance = 80 pi squared L squared

L is the fraction of a WL made by a tiny dipole.

For the same wavelength, a monopole is only 0.5 the length of a dipole
and it has 0.5 the radiation resistance.

If we use its length in the formula abbove, the radiation resistance
would calculate as only 1/4 that of a dipole because the constant is the
same and L squared is 0.5 squared.

I speculrte from the resistance ratio of a normal dipole to a normal
monopole that the answer should be 0.5. So I erred by halving the
constant. I should have doubled it to offset the quartered answer an
unchanged constant would produces when L = 0.5.

My new and improved answer to what the value of C is:

1580

Best regards, Richard Harrison, KB5WZI


Cecil Moore March 13th 06 03:18 PM

Radiation Resistance
 
wrote:
This newsgroup, like any public forum, allows anyone to say almost
anything without censorship. Because of that two things none of us like
to see will happen:

1.) Incorrect information is posted


By gurus as well as everyone else. I asked some technical
question in another posting, Tom. In the past, you simply
ignored my technical questions by trimming them from my
posting and then you objected to my style which is all
that was left.

Let's see if you are still unwilling to answer my technical
questions one of which is:

Why isn't a century old method of determining the phase
shift (delay) through a coil by measuring the self-
resonant frequency good enough for you? How do you
explain an 81% difference between this old accepted
method and your recently measured results?
--
73, Cecil
http://www.qsl.net/w5dxp


All times are GMT +1. The time now is 01:13 AM.

Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
RadioBanter.com