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antenna theory for idiots?
Can anyone point me at a good book or website that can teach me about
antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . |
antenna theory for idiots?
hi lisa,
check you local library, the arrl antenna books are very good, also http://www.cebik.com jake Lisa Simpson wrote: Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . |
antenna theory for idiots?
The ARRL Antenna Book is very good, and it's a good deal more accurate
than many other beginners' books. There's very likely to be a copy at your local library. Roy Lewallen, W7EL Lisa Simpson wrote: Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . |
antenna theory for idiots?
Thanx all - I'll check this book out!
"Roy Lewallen" wrote in message ... The ARRL Antenna Book is very good, and it's a good deal more accurate than many other beginners' books. There's very likely to be a copy at your local library. Roy Lewallen, W7EL Lisa Simpson wrote: Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . |
antenna theory for idiots?
The ARRL Radio Amateur's Handbook (ANY year) is a little less
intimidating than the Antenna Handbook. The Antenna Handbook is enough for most of us for many years. On Sun, 19 Mar 2006 02:23:07 GMT, "Lisa Simpson" wrote: Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . John Ferrell W8CCW |
antenna theory for idiots?
Lisa:
Check out the SWL oriented antenna links at URL: http://ac6v.com/swl.htm#ANT -- CL -- I doubt, therefore I might be ! "Lisa Simpson" wrote in message . .. Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . |
antenna theory for idiots?
ORIGINAL MESSAGE:
Lisa Simpson wrote: Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . *********** REPLY SEPARATOR *********** The ARRL Antenna Handbook starts at the very beginning and goes as far as you would like for ham radio designs. If you become so enthralled with antennas that you want to go into it professionally, there are other books but for us hams. that one will do. Bill, W6WRT |
antenna theory for idiots?
On Sun, 19 Mar 2006 02:23:07 GMT, "Lisa Simpson"
wrote: Can anyone point me at a good book or website that can teach me about antenna theory from a beginner's standpoint? I'm getting into SWL & feel I really need to understand this subject well . . . Better Shortwave Reception, by William Orr, out of print, but a used copy is at: http://www.alibris.com/search/search...MDVKJzo0z0Tvng Mr. Orr was one of the more understandable writers on things electronic... bob k5qwg |
antenna theory for idiots?
Bob Miller wrote:
"Can anyone point me at a dood book or website that can teach me about antenna theory from a beginner`s viewpoint?" The ARRL 2006 Handbook devotes Chapter 22 to that task and provides a good bibliography at the end of the chapter for further study. Best regards, Richard Harrison, KB5WZI |
antenna theory for idiots?
Bob Miller was quoting the originaql questioner.
Bob recommended "Better Shortwave Reception" by William Orr. Good advice, and the "Radio Handbook" recently published by Howard Sams and edited by William Orr is a good source of elementary theory too. Best regards, Richard Harrison, KB5WZI |
antenna theory for idiots?
Thanx all!
"Richard Harrison" wrote in message ... Bob Miller was quoting the originaql questioner. Bob recommended "Better Shortwave Reception" by William Orr. Orderd from alibris.com for ~$6.00! Also orderd the ARRL handbook for ~$30 used! Good advice, and the "Radio Handbook" recently published by Howard Sams and edited by William Orr is a good source of elementary theory too. Best regards, Richard Harrison, KB5WZI |
antenna theory for idiots?
Is this an explanation of the term 'capture area' I hear a lot of hams
use. regards, Jer As a 'rule of thumb' the captured signal power in small loops is proportional to the area enclosed by the loop. Twice the area = twice the power (3 dB). The typical dimensions given for these loops allow them to be used on either 160M or 80M -- and as you have surmised, the loop can be larger for 160M only. 73, Gary K9AY _________ Subject: [Antennaware] Shielded loop receive antennas. In the ARRL antenna handbook (and repeated elsewhere) is a design for a 160m shielded rx loop antenna with 5ft square sides. Can anyone advise me how the strength of the recovered signal would change if the loop was made bigger. By using low-capacity coax I think I could still resonate a loop that has 7ft square sides. This would very nearly double the **AREA** of the loop, I would like to understand how this would affect the received signal. Any thoughts would be appreciated. 73, |
Capture Area (was antenna theory for idiots?)
Here is a site for examples of capture areas of antennas
http://www.sommerantennas.com/gain.html -- CL -- I doubt, therefore I might be ! "k" wrote in message ... Is this an explanation of the term 'capture area' I hear a lot of hams use. regards, Jer As a 'rule of thumb' the captured signal power in small loops is proportional to the area enclosed by the loop. Twice the area = twice the power (3 dB). The typical dimensions given for these loops allow them to be used on either 160M or 80M -- and as you have surmised, the loop can be larger for 160M only. 73, Gary K9AY _________ Subject: [Antennaware] Shielded loop receive antennas. In the ARRL antenna handbook (and repeated elsewhere) is a design for a 160m shielded rx loop antenna with 5ft square sides. Can anyone advise me how the strength of the recovered signal would change if the loop was made bigger. By using low-capacity coax I think I could still resonate a loop that has 7ft square sides. This would very nearly double the **AREA** of the loop, I would like to understand how this would affect the received signal. Any thoughts would be appreciated. 73, |
Capture Area (was antenna theory for idiots?)
Caveat Lector wrote: Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html -- CL -- I doubt, therefore I might be ! As a 'rule of thumb' the captured signal power in small loops is proportional to the area enclosed by the loop. Twice the area = twice the power (3 dB). That's all nonsense, including the Sommer site!! Capture area, more correctly called effective aperture, and gain has nothing directly to do with physical area of an antenna. It is strictly a function of the operating wavelength and gain of the antenna. If I double the size of an antenna the capture area (effective aperture) might increase, decrease, or stay the same. If I have a small loop and it has zero loss, the capure area is effectively very large. If I have a full size dipole and add enough loss resistance, capture area is very small. Capture area is generally an excuse people make to justify using a larger antenna, even if the antenna does not work as nearly as well. "My quad works great for receiving because it has large capture area." Nonsense. If it has the same gain as a Yagi on the same band, it has exactly the same capture area. If it has less gain than a Yagi (which many quads do, hence the reason you don't see them in contest stations) it has less capture area. I'd be ashamed if I was selling antennas and did not understand what capture area was. 73 Tom |
Capture Area (was antenna theory for idiots?)
You can also find many postings explaining capture area by doing a
groups.google.com search of this newsgroup for the phrase "capture area". I've explained it here several times. Roy Lewallen, W7EL Caveat Lector wrote: Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html |
Capture Area (was antenna theory for idiots?)
Caveat Lector wrote:
Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html Have you got a link to a similar site that covers ferrite rod antennas? |
Capture Area (was antenna theory for idiots?)
On Fri, 24 Mar 2006 06:57:21 -0800, "Caveat Lector"
wrote: Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html Are you recommending it? Is the following statement from the page correct? "Note: Antenna B has only half the capture area of antenna A and is therefore able to "catch" only 50 percent of the electromagnetic field; e.g., 50mV, compared to 100 mV/50 Ohms. This means 6dB less gain for antenna B in comparison to antenna A." -- |
Capture Area (was antenna theory for idiots?)
Caveat Lector wrote:
Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html John Popelish wrote: Have you got a link to a similar site that covers ferrite rod antennas? I hope this question isn't taken the wrong way, but why would you want a similar site? That one is terrible for accuracy. The poor fellow who wrote that page doesn't even know what capture area is. Wouldn't it be better to find a totally different type of site, one that at least has some technical accuracy? 73 Tom |
Capture Area (was antenna theory for idiots?)
What information are you looking for, capture area or effective height?
Capture area determines how many watts you'll get into a conjugately matched load connected to the antenna. Effective height determines how many volts you'll get from an open circuited antenna. The two aren't directly related. For more information about the two topics, do a groups.google.com search for postings I've made on those topics in this newsgroup. As I've posted here quite a number of times before, the capture area of a lossless infinitesimally short dipole is very nearly as great as that of a half wave dipole, in their most favored directions. (The difference is about 10%, and it's due to the slight pattern shape difference caused by different current distributions). So except for loss the capture area of a ferrite rod antenna is within 10% of that of a dipole. But loss in a ferrite rod antenna will reduce the capture area considerably. If you're interested in knowing how much power you can get from a ferrite rod, then, what you need to know is its efficiency, which is a function of wire length, number of turns, and the antenna feedpoint impedance. I don't have the time right now to work it out for you. The effective height of a ferrite rod antenna is approximately: (2 * pi * mueff * N * A) / lambda where mueff = effective relative permeability of the rod (mainly a function of rod length) N = number of turns A = rod cross sectional area lambda = wavelength Roy Lewallen, W7EL John Popelish wrote: wrote: Caveat Lector wrote: Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html John Popelish wrote: Have you got a link to a similar site that covers ferrite rod antennas? I hope this question isn't taken the wrong way, but why would you want a similar site? That one is terrible for accuracy. The poor fellow who wrote that page doesn't even know what capture area is. I meant a site that addressed (correctly, one would hope) that concept of capture area for rod antennas. Wouldn't it be better to find a totally different type of site, one that at least has some technical accuracy? Okay, I'll take one of those. :-) |
Capture Area (was antenna theory for idiots?)
Roy Lewallen wrote:
What information are you looking for, capture area or effective height? Since I wasn't even aware that effective height applied to rod antennas (or exactly what effective height means) I guess I was thinking of capture area. Capture area determines how many watts you'll get into a conjugately matched load connected to the antenna. That's it. Effective height determines how many volts you'll get from an open circuited antenna. Does that include an antenna that has been brought to resonance with an appropriate capacitive load? The two aren't directly related. For more information about the two topics, do a groups.google.com search for postings I've made on those topics in this newsgroup. Thanks. As I've posted here quite a number of times before, the capture area of a lossless infinitesimally short dipole is very nearly as great as that of a half wave dipole, in their most favored directions. (The difference is about 10%, and it's due to the slight pattern shape difference caused by different current distributions). So except for loss the capture area of a ferrite rod antenna is within 10% of that of a dipole. But loss in a ferrite rod antenna will reduce the capture area considerably. So if a very small rod antenna had a lossless core that could handle any flux level, and was wound with superconductor, it could couple into the same volume of space as a 1/2 wave dipole? Amazing. If you're interested in knowing how much power you can get from a ferrite rod, then, what you need to know is its efficiency, which is a function of wire length, number of turns, and the antenna feedpoint impedance. I don't have the time right now to work it out for you. The effective height of a ferrite rod antenna is approximately: (2 * pi * mueff * N * A) / lambda where mueff = effective relative permeability of the rod (mainly a function of rod length) N = number of turns A = rod cross sectional area lambda = wavelength I can apply this formula directory to what I am experimenting with, except that I have to approximate mueff. I am making the rod by stacking ferrite beads, with various gaps between them. Can I approximate mueff by taking the ratio of coil inductance with and without the rod? And, what if the rod area is not constant all along the rod? Since my rods are assembled from pieces, I have a lot of freedom in this direction. |
Capture Area (was antenna theory for idiots?)
"John Popelish" wrote in message ... Caveat Lector wrote: Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html Have you got a link to a similar site that covers ferrite rod antennas? Try URL: http://www.st-andrews.ac.uk/~jcgl/Sc...rt7/page5.html Some others using Google -- CL -- I doubt, therefore I might be ! |
Capture Area (was antenna theory for idiots?)
John Popelish wrote:
Roy Lewallen wrote: . . . Effective height determines how many volts you'll get from an open circuited antenna. Does that include an antenna that has been brought to resonance with an appropriate capacitive load? No. "Open circuited" means that there's nothing connected across the feedpoint. . . . So if a very small rod antenna had a lossless core that could handle any flux level, and was wound with superconductor, it could couple into the same volume of space as a 1/2 wave dipole? Amazing. Yes, exactly the same volume of space, although capture area isn't a measure of this. Capture area is an area, not a volume, and it's different in all directions, just like gain. In fact, there's a 1:1 correspondence between capture area and gain, they're just different ways of expressing the same thing. In the absence of loss, all the power applied to *any* antenna will radiate, so the integral of the power density over all directions is the same for all lossless antennas -- the integral of the power density will equal the applied power, since there's no dissipation (and in the far field the power density is simply E^2 / Z0 = H^2 * Z0 where Z0 is the impedance of free space and E and H are the electric and magnetic field strengths respectively). The reciprocal of this principle is that the integral of capture areas in all directions (what you're calling the "volume" the antenna is "coupling" to) is the same for all lossless antennas. But more directly to the point, your tiny theoretical rod antenna would have a gain of about 0.45 dB less than a half wave dipole, and its capture area would be correspondingly smaller -- about 10%. This is assuming you're looking in the best direction for each antenna. Because the total radiated power or integral of the capture areas must be the same for the two antennas, this means that the tiny antenna has to have more gain or capture area than the dipole in some other directions. And indeed it does -- the tiny antenna has slightly fatter lobes than the half wave dipole. This is a good experiment to run with EZNEC or NEC-2. The EZNEC demo is adequate. Use free space, set wire loss to zero, and compare the gains and patterns of a half wave dipole to a very short one. The Average Gain tells you the ratio of total radiated power to input power, and it should equal one if the program is doing its calculations correctly. If you're interested in knowing how much power you can get from a ferrite rod, then, what you need to know is its efficiency, which is a function of wire length, number of turns, and the antenna feedpoint impedance. I don't have the time right now to work it out for you. The effective height of a ferrite rod antenna is approximately: (2 * pi * mueff * N * A) / lambda where mueff = effective relative permeability of the rod (mainly a function of rod length) N = number of turns A = rod cross sectional area lambda = wavelength I can apply this formula directory to what I am experimenting with, except that I have to approximate mueff. I am making the rod by stacking ferrite beads, with various gaps between them. Can I approximate mueff by taking the ratio of coil inductance with and without the rod? Yes. That's exactly what it is. And, what if the rod area is not constant all along the rod? Since my rods are assembled from pieces, I have a lot of freedom in this direction. That one I don't know the answer to. Roy Lewallen, W7EL |
Capture Area (was antenna theory for idiots?)
On Sat, 25 Mar 2006 01:09:06 GMT, Owen Duffy wrote:
On Fri, 24 Mar 2006 06:57:21 -0800, "Caveat Lector" wrote: Here is a site for examples of capture areas of antennas http://www.sommerantennas.com/gain.html Are you recommending it? Unanswered... Is the following statement from the page correct? "Note: Antenna B has only half the capture area of antenna A and is therefore able to "catch" only 50 percent of the electromagnetic field; e.g., 50mV, compared to 100 mV/50 Ohms. This means 6dB less gain for antenna B in comparison to antenna A." Of course it is not. The article seems based on some typical misconceptions about Capture Area and the suggestion that you can run a ruler over a dipole (loaded or otherwise) to measure up and calculate the capture area is nonsense. I wonder if that is how Somner derive the gain figures that they publish for their antennas. (Gain is related to Capture Area, and if they don't understand Capture Area, do they understand Gain?) Owen -- |
Capture Area (was antenna theory for idiots?)
Roy Lewallen wrote:
John Popelish wrote: Roy Lewallen wrote: . . . Effective height determines how many volts you'll get from an open circuited antenna. Does that include an antenna that has been brought to resonance with an appropriate capacitive load? No. "Open circuited" means that there's nothing connected across the feedpoint. But I can design the coil to be self resonant or not, just by adjusting the surface area of the wire, or the spacing. It is non intuitive that if I peak the coil this way, and obtain more voltage, it is a different case than if I peak the coil with cable capacitance, or an additional capacitor. I guess I really don't comprehend the point of this value. (Snip excellent review of basic lossless radiator. Thank you.) But more directly to the point, your tiny theoretical rod antenna would have a gain of about 0.45 dB less than a half wave dipole, and its capture area would be correspondingly smaller -- about 10%. This is assuming you're looking in the best direction for each antenna. Because the total radiated power or integral of the capture areas must be the same for the two antennas, this means that the tiny antenna has to have more gain or capture area than the dipole in some other directions. And indeed it does -- the tiny antenna has slightly fatter lobes than the half wave dipole. I understand what you are saying. (snip) The effective height of a ferrite rod antenna is approximately: (2 * pi * mueff * N * A) / lambda where mueff = effective relative permeability of the rod (mainly a function of rod length) N = number of turns A = rod cross sectional area lambda = wavelength I can apply this formula directory to what I am experimenting with, except that I have to approximate mueff. I am making the rod by stacking ferrite beads, with various gaps between them. Can I approximate mueff by taking the ratio of coil inductance with and without the rod? Yes. That's exactly what it is. Well, now I can calculate the effective height of my antennas, even though I am not sure what it has to do with height. And, what if the rod area is not constant all along the rod? Since my rods are assembled from pieces, I have a lot of freedom in this direction. That one I don't know the answer to. I am also experimenting with designs that do not necessarily have a small, coil, close to the rod. (My interest in the discussion of extended coils is showing.) One of the possibilities that shows a significant increase in tuned Q is an hour glass shaped coil (small diameter in the center, but sweeping to a larger diameter at the ends). I have been asked to try putting a rod through the center of a flat spiral coil. It seems to me that, at some extreme, the above formula will fail, because it assumes that essentially all the signal energy exiting the coil was collected by the rod, and that the signal the coil would collect by itself would be insignificant. But if my coils get large enough, they become loop antennas in their own right, and the rod, though it may have a significant length and area, is only a part of what is happening. In other words, the mueff can get pretty small, even though the rod has significant dimensions. I guess, what I am asking are what assumptions about coil dimensions (that are not explicitly referenced in the formula) are being made in the above formula? |
Capture Area (was antenna theory for idiots?)
John Popelish wrote:
Roy Lewallen wrote: John Popelish wrote: Roy Lewallen wrote: . . . Effective height determines how many volts you'll get from an open circuited antenna. Does that include an antenna that has been brought to resonance with an appropriate capacitive load? No. "Open circuited" means that there's nothing connected across the feedpoint. But I can design the coil to be self resonant or not, just by adjusting the surface area of the wire, or the spacing. It is non intuitive that if I peak the coil this way, and obtain more voltage, it is a different case than if I peak the coil with cable capacitance, or an additional capacitor. I guess I really don't comprehend the point of this value. Sorry, I don't understand what you're "peaking" and how. I believe that the formula I gave assumes that the coil is well below self resonance where the shunt capacitance is negligible. It won't be valid near self resonance, if that's what you mean. . . . Well, now I can calculate the effective height of my antennas, even though I am not sure what it has to do with height. Do a groups.google.com search of this newsgroup for my postings containing "effective height" or "effective length" -- I posted quite a bit about it not long ago. . . . I am also experimenting with designs that do not necessarily have a small, coil, close to the rod. (My interest in the discussion of extended coils is showing.) One of the possibilities that shows a significant increase in tuned Q is an hour glass shaped coil (small diameter in the center, but sweeping to a larger diameter at the ends). I have been asked to try putting a rod through the center of a flat spiral coil. It seems to me that, at some extreme, the above formula will fail, because it assumes that essentially all the signal energy exiting the coil was collected by the rod, and that the signal the coil would collect by itself would be insignificant. But if my coils get large enough, they become loop antennas in their own right, and the rod, though it may have a significant length and area, is only a part of what is happening. In other words, the mueff can get pretty small, even though the rod has significant dimensions. I guess, what I am asking are what assumptions about coil dimensions (that are not explicitly referenced in the formula) are being made in the above formula? I'm sorry, I don't know. The reference it came from doesn't say. It in turn references Laurent, H.J. and Carvalho, C.A.B., "Ferrite Antennas for AM Broadcast Receivers", an application note from Bendix Corporation. That app note, if you can find it, might or might not tell. I'm sure it's not valid anywhere near self resonance, though. Your concept of signal energy getting collected separately by the rod and the coil, or exiting the coil and being collected by the rod doesn't fit at all with what I know of the behavior of electromagnetic fields, so I won't even try to comment on that aspect or the conclusions resulting from it. Maybe it makes sense to Cecil or art -- they seem to view things in a different way. Roy Lewallen, W7EL |
capacity hat antennas
(My information for this comes from a number of websites including
commercial antenna sites. Needless to say, the accuracy of any information, especially that of commercial sites is suspect.) I have been reading about reduced size antennas using capacity hats instead of, or in addition to, inductor loading. Most sites claim that capacity hats reduce size with much less (or no) signal loss compared to a full size antenna. At least one site claims a vertical 1/4 dipole using cap-hats has gain over a 1/4 vertical ground plane. The consensus seems to be that size for size, the antenna shortened by capacity hats has less loss than the same size antenna shortened by inductors as per http://www.sommerantennas.com/gain.html (taken from another thread in this newsgroup.) Some claims are that the capacity hat antennas have equal signal strength to their full-sized counterparts. My research, thus far, my theory is: 1) any shortened antenna will have some loss compared to its full-sized counterpart. (i.e. an 80 meter dipole shortened by one foot using capacity hats will not be as efficient as the full length version, even though one might be hard pressed to find the instrument that could measure it.) 2) antennas shortened with capacity hats have less loss than those shortened by inductors 3) capacity hat antennas exhibit slightly more bandwidth than inductor loaded antennas 4) given equal length, a cap-hat vertical dipole will exhibit equal, (or according to some sites, greater) signal strength to a vertical monopole either reduced or full-size. Size Loss vs efficiency of a cap-hat dipole. Assuming my first point of theory is correct, there must be a point in which the reduced size of a dipole using only capacity hats is noticeable. Continued reduction finds additional noticeable points of loss. What I would like to know is approximately where those points might be so the 'value' of a cap-hat dipole antenna can be determined given some acceptable size or loss. An example might be I have 25 feet of antenna pole. I can build an antenna with what I have. However, it may be that for ten more feet of pole, I can have a much better signal. Should I use what I have, or order the additional ten feet of aluminum? Another example would be to estimate the maximum power I can run on 60 meters using a given length antenna. If a 1/4 wave dipole will radiate almost as effectively as a 1/2 wave, then I would not worry about adding the extra 5 or ten watts I would need to max the ERP out, but if the loss were significant, I would know I can leave my radio on full power (100 watts) without committing a violation. Thank you for your thoughts. -- 73 for now Buck N4PGW |
capacity hat antennas
"Buck" wrote in message ... (My information for this comes from a number of websites including commercial antenna sites. Needless to say, the accuracy of any information, especially that of commercial sites is suspect.) I have been reading about reduced size antennas using capacity hats instead of, or in addition to, inductor loading. Most sites claim that capacity hats reduce size with much less (or no) signal loss compared to a full size antenna. At least one site claims a vertical 1/4 dipole using cap-hats has gain over a 1/4 vertical ground plane. The consensus seems to be that size for size, the antenna shortened by capacity hats has less loss than the same size antenna shortened by inductors as per http://www.sommerantennas.com/gain.html (taken from another thread in this newsgroup.) Some claims are that the capacity hat antennas have equal signal strength to their full-sized counterparts. My research, thus far, my theory is: 1) any shortened antenna will have some loss compared to its full-sized counterpart. (i.e. an 80 meter dipole shortened by one foot using capacity hats will not be as efficient as the full length version, even though one might be hard pressed to find the instrument that could measure it.) 2) antennas shortened with capacity hats have less loss than those shortened by inductors 3) capacity hat antennas exhibit slightly more bandwidth than inductor loaded antennas 4) given equal length, a cap-hat vertical dipole will exhibit equal, (or according to some sites, greater) signal strength to a vertical monopole either reduced or full-size. Size Loss vs efficiency of a cap-hat dipole. Assuming my first point of theory is correct, there must be a point in which the reduced size of a dipole using only capacity hats is noticeable. Continued reduction finds additional noticeable points of loss. What I would like to know is approximately where those points might be so the 'value' of a cap-hat dipole antenna can be determined given some acceptable size or loss. An example might be I have 25 feet of antenna pole. I can build an antenna with what I have. However, it may be that for ten more feet of pole, I can have a much better signal. Should I use what I have, or order the additional ten feet of aluminum? Another example would be to estimate the maximum power I can run on 60 meters using a given length antenna. If a 1/4 wave dipole will radiate almost as effectively as a 1/2 wave, then I would not worry about adding the extra 5 or ten watts I would need to max the ERP out, but if the loss were significant, I would know I can leave my radio on full power (100 watts) without committing a violation. ======================================== Buck, For the same reduction in height a top hat has greater efficiency than a loading coil. It can amount to 3 or more decibels. But a top hat gets in the way and is more unsightly than a coil. Have you seen program TOPHAT available from website below. ---- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... |
Capture Area (was antenna theory for idiots?)
Roy Lewallen wrote:
(snip) Do a groups.google.com search of this newsgroup for my postings containing "effective height" or "effective length" -- I posted quite a bit about it not long ago. Will do. Thanks. |
Capture Area (was antenna theory for idiots?)
Is "height" in "effective height" really referring to effective
radiating length, rather than something to do with elevation above ground (assuming that one is talking about a monopole above a ground plane)? In other words, is the "effective height" of a horizontal dipole actually related to its end to end length, not its distance above ground? I am just trying to get started on the right foot in my reading. |
capacity hat antennas
wrote:
(snip) I suggest you read: http://www.w8ji.com/radiation_and_fields.htm (snip) I am trying to soak up the information on this page. In the graph of field impedance versus distance (about half way down the page, is this showing the ratio of E field to H field intensities I would measure with very small electric and magnetic pickups placed at these distances? It looks like this is showing that a mag loop creates a larger E field at some distances than a dipole that is creating the same far field energy propagation. This is quite counter intuitive, so I want to make sure I have not got it wrong. |
Capture Area (was antenna theory for idiots?)
John Popelish wrote:
Is "height" in "effective height" really referring to effective radiating length, rather than something to do with elevation above ground (assuming that one is talking about a monopole above a ground plane)? In other words, is the "effective height" of a horizontal dipole actually related to its end to end length, not its distance above ground? I am just trying to get started on the right foot in my reading. Never mind. I found something you wrote in an earlier thread: "There's a common term for the relationship between the field strength and the length of a conductor, called the "effective height" or "effective length". The voltage at the center of a dipole in a field of E volts/m is simply E * the effective length. The concept is valid for any length conductor, not just short ones. The effective length of a uniform-current dipole is equal to the wire length. The effective length of a short conventional dipole is 0.5 times the wire length. The effective length for receiving is the same as the effective length for transmitting -- in transmitting, it relates the strength of the field produced to the *voltage* -- not power -- applied across the feedpoint. If you apply 0.5 volts to a standard dipole and 1.0 volts to a uniform-current dipole, the power applied to each will be the same because of the 1:4 ratio of radiation resistance, and the generated fields will be the same. This is consistent with the antenna gains being the same." This cleared up a lot of the terminology and concepts for me. |
Capture Area (was antenna theory for idiots?)
"Effective length" refers to dipole type antennas in free space.
"Effective height" is the equivalent property of a grounded monopole. They're often used somewhat interchangeably. Roy Lewallen, W7EL John Popelish wrote: Is "height" in "effective height" really referring to effective radiating length, rather than something to do with elevation above ground (assuming that one is talking about a monopole above a ground plane)? In other words, is the "effective height" of a horizontal dipole actually related to its end to end length, not its distance above ground? I am just trying to get started on the right foot in my reading. |
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