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what a 1:1 choke balum used for
Roy Lewallen wrote:
Broadband transformers, which can operate well over several decades of frequency, commonly use ferrite cores which are essentially resistive over most of the operating frequency range. The sign of the impedance is unimportant to the transformer's operation; all that's necessary is that its magnitude be adequately high over the operating range (and of course that the core's permeability be adequately high). The wide band high impedance requirement is virtually impossible to meet with an inductive core whose impedance is approximately proportional to frequency, but easily done with cores whose impedance is essentially resistive. As long as the impedance is high enough, what is the need for it to be constant (or even nearly so) over a useful frequency range? |
what a 1:1 choke balum used for
On Wed, 29 Mar 2006 17:30:54 -0500, John Popelish
wrote: Richard Clark wrote: (snip) #64 material is going to offer about 3 Ohms per bead; #43 material is going to offer about 8 Ohms per bead; #73 & 77 material is going to offer about 18 Ohms per bead; #75 material is going to show offer 28 Ohms per bead. (snip) What dimension cores produce these impedances at 75 meters? Hi John, It is called a 101 sized bead: .138" OD .051" ID .128" high 73's Richard Clark, KB7QHC |
what a 1:1 choke balum used for
Richard Clark wrote:
Breaking magnetic lines (flux) is a commonplace ... If magnetic lines can be broken, doesn't that imply the existence of magnetic monopoles which have never been found to exist in reality? :-) -- 73, Cecil http://www.qsl.net/w5dxp |
what a 1:1 choke balum used for
John Popelish wrote:
You'll learn a lot by reading the information in the Fair-Rite catalog, available at their web site. I have a hard copy right beside me, and refer to it often. I also have a fold-up brochure from Amidon dated March 1991 and titled: "Iron-Powder and Ferrite Coil Forms". -- 73, Cecil http://www.qsl.net/w5dxp |
what a 1:1 choke balum used for
Roy Lewallen wrote:
John Popelish wrote: . . . I appreciate you taking the time and effort to try to straighten me out on this, but if there is no magnetic lines broken (whatever that means) why use a magnetic core? Why wouldn't disks of carbon work just as well. They are certainly resistive. But resistive impedance isn't the only characteristic of ferrite. Disks of carbon won't work because they have a relative permeability of one. I know that. I wanted to see if Richard does. (snip) You'll learn a lot by reading the information in the Fair-Rite catalog, available at their web site. (snip) I have a hard copy right beside me, and refer to it often. |
what a 1:1 choke balum used for
Richard Clark wrote:
Hi John, Breaking magnetic lines (flux) is a commonplace of fields, motors, and generators. A single wire that passes through a bead, torus, or core will build a magnetic field concentrated within that structure when the circuit is completed outside of it. The flux lines of half the loop will penetrate the core to reach the other half of the loop. The core breaks the magnetic line of flux. The dissymmetry of penetration builds a magnetic field in the core. I cannot picture what you are saying. I guess I need a picture. The way I understand flux, is that, any current has flux wrapped around it. Putting a core material around the current allows the flux to increase in magnitude in proportion to the permeability of the material. However, when the complete current loop is within the same structure, the flux lines do not fulfill that same function. The simplest way to say that is that two equal currents going in opposite directions have magnetic fields that cancel well outside the pair of conductors. It doesn't make a lot of difference if the two currents are coaxial or side by side, as long as the flux path surrounds both of them. The flux lines that do emerge from the tightly bound wires can be said to penetrate the torus, but here the symmetry creates bucking fields, the net effect is as though there was no core at all (except to add capacitance). Since the magnetic fields from the two currents cancel (at sufficient distance), there is no flux to enter a surrounding core. The only way bucking takes place is if the two currents are side by side. Then there is some flux leakage near the two current paths, but the fields these create buck each other in the two halves of the core, so there is only local flux fringing into and back out of the core. Both models attempt to stimulate a current within the toroid, the common mode of the single wire model above is lossy, the differential mode of the twin line model that followed sees nothing. Superpose these two for the coaxial solution. As I understand common mode current, it is the net imbalance between the current through the center conductor and the current through the shield. To put this to a test. Load up your rig, through a SWR meter to a dummy load using two short connection wires (this will undoubtedly require adapters and such to break out both paths). You should note a 1:1 indication. Place two #75 beads on ONE wire. You should note a 2:1 indication. You have just inserted 40 to 60 Ohms of additional resistance into the circuit. Now, move the same two beads to encompass BOTH wires. This should return the SWR meter to a 1:1 indication. Yes, obvious to the casual observer. You can string beads all along a coax, and if it had no common mode current in it, this will make absolutely no difference in how the coax acts. |
what a 1:1 choke balum used for
Richard Clark wrote:
On Wed, 29 Mar 2006 17:30:54 -0500, John Popelish wrote: Richard Clark wrote: (snip) #64 material is going to offer about 3 Ohms per bead; #43 material is going to offer about 8 Ohms per bead; #73 & 77 material is going to offer about 18 Ohms per bead; #75 material is going to show offer 28 Ohms per bead. (snip) What dimension cores produce these impedances at 75 meters? Hi John, It is called a 101 sized bead: .138" OD .051" ID .128" high Are these what you recommend as coax choke balun beads? That is some fine coax. |
what a 1:1 choke balum used for
John Popelish wrote: rocky wrote: To sort of sum things up, then what should I use for a choke balun on 75 meters, 77, 73 or 43 mix? More the better? I read the W2DU article and he used 73, but I thought 77 may be better? If you are going to have to go out and buy the cores, type 43 (and its competitors) is way more common and cheap than any of the others. It is also readily available in long form toroids called shield beads. You are going to get into trouble with the W2DU balun at high power levels or with high commonn mode voltages across the balun. Each bead suggested is only good for about 1/2 watt dissipation in open air during long duty cycle. Also, a string of beads is a terribly inefficient use of ferrite materials. If you double the expense of the balun by doubling the number of beads, you only double the common mode impedance. If you use a less resistive material with lower loss tangent and multiple turns through the core, you can greatly increase power capacity and choking impedance with much less increase in cost. 73 or 75 material beads are great in 50 ohm systems at modest power on higher frequencies when the common mode excitation is low, but I'd stay away from that method at kilowatt power levels especially if common mode exciting the shield is high in level or frequency is low. For high stress applications a string of beads is terribly inefficient. 73 Tom |
what a 1:1 choke balum used for
John Popelish wrote:
Roy Lewallen wrote: Broadband transformers, which can operate well over several decades of frequency, commonly use ferrite cores which are essentially resistive over most of the operating frequency range. The sign of the impedance is unimportant to the transformer's operation; all that's necessary is that its magnitude be adequately high over the operating range (and of course that the core's permeability be adequately high). The wide band high impedance requirement is virtually impossible to meet with an inductive core whose impedance is approximately proportional to frequency, but easily done with cores whose impedance is essentially resistive. As long as the impedance is high enough, what is the need for it to be constant (or even nearly so) over a useful frequency range? None. Roy Lewallen, W7EL |
what a 1:1 choke balum used for
John Popelish wrote:
. . . As I understand common mode current, it is the net imbalance between the current through the center conductor and the current through the shield. If you consider the sum of the physically separate currents on the inside and outside of the shield to be the current "through the shield", that's correct. And it's equal to the current on the outside of the shield. . . . Roy Lewallen, W7EL |
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