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[email protected] May 18th 06 12:53 AM

FIGHT? Here is another W8JI myth bone!
 

Richard Harrison wrote:
Tom, W8JI wrote:
"I did not claim that effect. Terman certainly did not. (Yuri claims the
shield "blocks electric fields" or stops "electrostatic fields".)"

I`ll requote Terman from page 38 of his 1955 edition which Tom ignored:
"It is possible to shield electrostatic flux without simultaneously
affecting the magnetic field by surrounding the space to be shielded wih
a conducting cage that is made in such a way as to provide no
low-resistance path for the flow of eddy currents while at the same time
offering a metallic terminal upon which electrostatic flux lines can
terminate."


Richard.

I know anything Roy Lewallen agrees with, you disagree with. I know
anything I say (or even what I don't say) sets Yuri off into a foaming
lather. I really wish you guys could put personal hate or dislike aside
and look at facts. This is an imporant issue because the myth about
shields is imbedded in amateur circles despite many clearly written
engineering texts and very simple experiments that prove the concept of
time-varying magnetic fields penetating the shield. It's just a fact
when the time-varying electric field is taken to zero so is the
time-varying magnetic field.

Static by definition is not moving or varying. Don't confuse jargon
describing a different coupling mode with the mechanics of a loop
operating at radio frequencies.

When we receive noise or signals, the fields are time-varying. Just as
with a piece of coaxial cable, the inner wall of a "shielded loop" is
isolated by the skin depth of the conductor from the outside wall. The
electric and magnetic coupling effects are what causes a coaxial cable
with a dense shield more than a few skin depths thick to ALWAYS have
the same current on the inside of the shield as the inner conductor
has, and all radiation or common mode current flow over the outside.

This isn't something I invented. It has been in nearly every textbook
long before I was born.

I'm pleased that Yuri credits me for the work, but unfortunately I had
little to do with it. It really was people from the 1700's and 1800's
that did all the work.

You (and Yuri) appear to be confusing how time-varying fields work.

I suggest you put Terman aside and actually read some textbooks on
fields.

It's helpful to actually make a few measurements. A few minutes spent
with some very simple test equipment would go a long way to "turning on
the light".

The loop shield is thus a true Faraday screen, not a Faraday car body or
screened room.


If you say so. And as one, it also must block any time-varying magnetic
field. As K7ITM points out it is the gap in the loop that is actually
the feedpoint, and it is the outside of the loop that is the actual
antenna.

If you do not think a loop behaves this way, you need to get busy doing
some real important work. You need to get all the Handbooks to quit
talking about common mode currents on shield outsides. You need to get
them to quit treating the inside of the shield as a isolated conductor
that is independent of the outside.

As I and others have suggested it only takes a moment to prove the
books are correct. You can prove it with a single sheet of copper and a
minimum of test equipment.

73 Tom


Yuri Blanarovich May 18th 06 01:14 AM

FIGHT? Here is another W8JI myth bone!
 

wrote in message
ps.com...

Richard Harrison wrote:
Tom, W8JI wrote:
"I did not claim that effect. Terman certainly did not. (Yuri claims the
shield "blocks electric fields" or stops "electrostatic fields".)"

I`ll requote Terman from page 38 of his 1955 edition which Tom ignored:
"It is possible to shield electrostatic flux without simultaneously
affecting the magnetic field by surrounding the space to be shielded wih
a conducting cage that is made in such a way as to provide no
low-resistance path for the flow of eddy currents while at the same time
offering a metallic terminal upon which electrostatic flux lines can
terminate."


Richard.

I know anything Roy Lewallen agrees with, you disagree with. I know
anything I say (or even what I don't say) sets Yuri off into a foaming
lather. I really wish you guys could put personal hate or dislike aside
and look at facts. This is an imporant issue because the myth about
shields is imbedded in amateur circles despite many clearly written
engineering texts and very simple experiments that prove the concept of
time-varying magnetic fields penetating the shield. It's just a fact
when the time-varying electric field is taken to zero so is the
time-varying magnetic field.


That really nails it! His "technical" response!
Perfect picture of a jerk parading as an engineer!
Yep, I hate your guts and I made up phony claims on your web site for all to
see, so I can "hate you"! Brilliant! Keep it up!
Halleluja, now we know that shields are antennas, praise the guru!


Bada BUm







Cecil Moore May 18th 06 04:30 AM

FIGHT? Here is another W8JI myth bone!
 
wrote:
I know anything Roy Lewallen agrees with, you disagree with.


Absolutely false. I'll bet they agree on 99% of technical
topics, e.g. ohm's law, Maxwell's equations, etc.
--
73, Cecil
http://www.qsl.net/w5dxp

Richard Harrison May 18th 06 06:52 AM

FIGHT? Here is another W8JI myth bone!
 
Tom, W8JI wrote:
"This is an important issue because the myth about shields is embedded
in amateur circles despite many clearly written engineering texts and
very simple experiments that prove the concept of time-varying magnetic
fields penetrating the shield."

Some of that poison reached the 2006 ARRL Handbook on page 13.18. Fig
13.26 says:
"Electrostatically-shielded loop for RDF. To prevent shielding of the
loop from magnetic fields, leave the shield unconnected at one end."

Terman`s RDF loop should have better balance than ARRL`s because
Terman`s shield gap is squarely in the center of the loop
and not at one end. However, as long as the shield is broken preventing
induced current from flowing around the shield, Lenz`s law will be
thwarted and magnetic coupling to the coil under the shield will be
obtained. Electric field coupling to the coil beneath the shield will be
disallowed by the shield`s connection to ground wherever it occurs,
though not as elegantly as when care is taken to get the best balance
possible.

I`ve worked with such Faraday screens in my broadcasting career.

Best regards, Richard Harrison, KB5WZI


Richard Clark May 18th 06 06:57 AM

FIGHT? Here is another W8JI myth bone!
 
On Wed, 17 May 2006 10:19:39 -0700, Richard Clark
wrote:

It's still the same "1/2 inch copper water tubing (non ferrous
material passing the magnetic field)."

So, does that wire make the "shield" better, or worse?


Hmm, this one must've been experienced exactly as an existential
question about the infinite cosmos.

Super-extra credit question:
If we replaced the non ferrous material (same gap, no link) with (most
have probably anticipated this) a ferrous material, does this allow
near field region electrical field interference to pass un-impeded?


This one must never been experienced either. I've always wondered why
perfect academic set-ups like "non ferrous material" (as if it were
lossless) always appear in the context of a populist aw-shucks kind of
posting.

Sorry All,

But when such simple questions become imponderables of the century,
they merit Cecil's 5 forbidden words woven in. Of course, it makes
only the most strained of sense, but there's nothing to compete! ;-)

73's
Richard Clark, KB7QHC

p.s. as viewed through the bottom of a bottle of Dick's Working Man's
Brown Ale (Centralia, Washington)

[email protected] May 18th 06 07:13 AM

FIGHT? Here is another W8JI myth bone!
 
Sooo, in shielded loop the shield is the antenna according to W8JI and
worshippers. But you take the shield (W8JI antenna) away, now the wires are
antenna, some say don't need no stinkin' shield and "antenna" to work as an
antenna.


I don't know what a W8JI antenna is, except for those I've heard on
160m... :/
But I do know that I've tested various versions of both shielded and
unshielded
loops, and have never been able to tell a lick of difference as far as
close local
noise pickup. I spent a whole week testing that very thing. It's not
something I just
made up, or picked up from W8JI.

Amazing how selective in reading and digestion of postings some people are.
They tend to ignore the reality and description of it, they pick on
selective "proof" of what they were taught and figered out.


Only my test results were used to come up with my conclusion. So I
guess
I taught myself. I've never built a shielded loop yet that was any
"quieter" to
local noise than any of my good unshielded loops. But my unshielded
loops
are well balanced. Were yours?

So shield works as a electrostatic shield, if you guys like it or not, or
refuse to admit.


I refuse to admit it, if I can't prove it. And I haven't been able to
prove it yet.
One thing...How in the heck is a solid shield going to filter one
source of RF,
and ignore another. In reality, it will shield *all* RF, unless I am
missing
something here. So the outer shield *must* be the antenna, unless the
sky is
now green. No RF is going to prevail past the outer skin depth of the
solid
shield. None. Nada...

Sooo, antenna works without shield (not just my assertion), but when you
insert it in the shield then shield becomes W8JI antenna.


It does? I'm sure if this is the case, it probably tunes 160m.... :/

So his shield,
untuned becomes antenna, but my tuned and tunable inside the shield antenna
is not the antenna? Makes as much sense as "there is equal current along the
loading coil doesn't matter what", riiiiight?


If you say so....

Let's stick to some reality in antennas.


Thats all I do. I've made a load of loops. I have a diamond loop 44
inches
per side right next to me. Almost is as tall as the ceiling... Heck, I
even
have tried using shielded loops as the coupling loop to unshielded
loops.
Works pretty well to maintain balance, but mine work just as well with
just
a simple unshielded coupling loop. Probably cuz my loops are very
symmetrical
and balanced naturally. The coax feedline itself is the only real issue
in my case,
and even it's not really very critical. I never saw any indication
that using a
shielded coupling loop made the loop quieter than not using one. Not
once.
Myself, I don't really like small loops for receiving on 160m. They are
good for
cutting the noise when working loud locals, but in my experience they
are
pretty ho-hum when receiving weak dx. For 160m, I would use the biggest
loop
I could manage. Probably outside to have enough room...
My loops are mainly for MW BC receiving, although the one next to me
tunes
500-2300 kc in two stages, by switching cap gangs. I can go LW if I
tack on
more fixed caps. The real value of small loops are not the "quiet", or
the s/n
or whatever. It's the nulls... But nulls have much more value in the BC
band,
than they do on 160m unless maybe you have a noise source in the area
you wanna null out. Thats how a loop reduces noise. Using the nulls...
:/
I do have to agree with Tom. I think the "shielded loop" theory many
hams
adhere to is just another batch of wive tailery.. Along with grounds to
cure
antenna/feedline problems, sticking coax ends in bottles hoping to
thwart
lightning, etc... And I've never once talked to Tom about small loops.
It's all my idea to shun this "shield=quiet" theory, not W8JI's.
MK


Mike Coslo May 18th 06 12:33 PM

FIGHT? Here is another W8JI myth bone!
 
Cecil Moore wrote:
wrote:

I know anything Roy Lewallen agrees with, you disagree with.



Absolutely false. I'll bet they agree on 99% of technical
topics, e.g. ohm's law, Maxwell's equations, etc.


Just like arguing whether Coke or Pepsi tastes best. The closer the
product, the worse the arguing...

- 73 de Mike KB3EIA -

Richard Harrison May 18th 06 05:48 PM

FIGHT? Here is another W8JI myth bone!
 
Mark, NM5K wrote:
"I refuse to admit it, if I can`t prove it."

A shield is extra work, weight, and cost but despite that, many are in
use.

As electrons move along a conductor a magnetic field expands from some
depth inside the conductor itself. The magnetic lines of force sweep
outward from the conductor while inducing an emf in the conductor
itself. The self induced emf opposes instantaneous change of current in
the inductance of the conductor. This is the basis of Lenz`s law:
"In all cases of electromagnetic induction, induced electromotive force
and resultant current are in such a direction as to oppose the effect
producing them."

Skin effect prevents penetration of RF very deep into a good conductor.
Skin effect makes RF coil shields impenetrable. Electric hields are
shorted to ground by the conductive shield. Magnetic fields induce
counter fields from the currents they induce on the surface of the
shield.

A Faraday screen breaks the current path on the shield preventing the
counter fields from being magneticly induced. Result is a shield that is
penetrable by the magnetic field but impenetrable by the electric field.
The electric field is still shorted to ground by its conductive path.
Faraday screens are used because they work.

Best regards, Richard Harrison, KB5WZI


Richard Clark May 18th 06 06:44 PM

FIGHT? Here is another W8JI myth bone!
 
On Thu, 18 May 2006 11:48:52 -0500, (Richard
Harrison) wrote:

A Faraday screen breaks the current path on the shield preventing the
counter fields from being magneticly induced. Result is a shield that is
penetrable by the magnetic field but impenetrable by the electric field.
The electric field is still shorted to ground by its conductive path.
Faraday screens are used because they work.


Hi Richard, Yuri,

In regard to my last question that so stumped you two, there is
absolutely nothing inherent in non-ferrous vs. ferrous materials that
changes this one particular aspect of shielding. Both materials are
conductive, and both are selected for their lowest conductivity (hence
their lowest Ohmic loss). The only substantive difference is that a
ferrous material offers the prospect of using a thinner covering for
the same isolation. Above LF, this is hardly useful unless you are
planning on using very thin foils. Art's selection of mylar films
with conductive coatings is one such example that works with a
conductive surface thickness in the 100s of microns.

The "shielded dipole" observes the one principle requirement of
insuring that a break in continuity is maintained. Otherwise, the
shorted turn snuffs the antenna for any design held within it. This
prohibition in continuity is paramount to all designs and is driven by
both magnetic as well as electric considerations, as in the RF field
they are inextricably coupled.

To cut to the chase: there is no way to separate these fields and
select one of them over the other. If you choose to run your arc
welder within a loop's diameter of the antenna while also DXing; then
it is the balance of the antenna design, not the shielding that will
determine your success. Screw up the geometry of that gap, and you
will hear as much hash as if the "shield" never existed.

For the standard single turn "shielded dipole," the arms of the dipole
are the shield. There must be 10 million examples of this particular
model on 1 million repeater installations world-wide. There are also
tri-axial or twin-axial designs of the "shielded dipole" that wholly
divorce themselves of the exterior shield. All such designs, to work
effectively, exhibit a balanced configuration that is identical to the
standard single turn. The balance is the only consideration at issue,
and shielding is a means, but hardly a necessary ends to that
achievement. As such, shielding is simply insurance and a brute force
means to force balance through what in engineering terms is called
"swamping."

73's
Richard Clark, KB7QHC

Michael Tope May 20th 06 03:47 AM

FIGHT? Here is another W8JI myth bone!
 

"Richard Harrison" wrote in message
...

As electrons move along a conductor a magnetic field expands from some
depth inside the conductor itself. The magnetic lines of force sweep
outward from the conductor while inducing an emf in the conductor
itself. The self induced emf opposes instantaneous change of current in
the inductance of the conductor. This is the basis of Lenz`s law:
"In all cases of electromagnetic induction, induced electromotive force
and resultant current are in such a direction as to oppose the effect
producing them."

Skin effect prevents penetration of RF very deep into a good conductor.
Skin effect makes RF coil shields impenetrable. Electric hields are
shorted to ground by the conductive shield. Magnetic fields induce
counter fields from the currents they induce on the surface of the
shield.

A Faraday screen breaks the current path on the shield preventing the
counter fields from being magneticly induced. Result is a shield that is
penetrable by the magnetic field but impenetrable by the electric field.
The electric field is still shorted to ground by its conductive path.
Faraday screens are used because they work.

Best regards, Richard Harrison, KB5WZI


I would agree, Richard, but at HF frequencies the current path
around the shield isn't really broken by the gap. Due to the skin
effect, the RF current flowing on the inside of the loop shield is free
to flow around the edge of the shield conductor and onto the outside
of the shield at the gap. At very low frequencies, where the skin
depth is large, this wouldn't necessarily be true, but at HF as long
as there are a few skin depths between the outside and the inside
surface of the conductor, then the inside surface of the shield and
the outside surface of the shield can be treated as independent
conductors.

73, Mike W4EF........................



Richard Harrison May 21st 06 04:46 AM

FIGHT? Here is another W8JI myth bone!
 
Mike, W4EF wrote:
"I would agree, Richard, but at HF frequencies, the current path around
the shield isn`t real;ly broken by the gap."

To best describe what broken means, a picture helps. There is a picture
on page 13.18 of the 2006 ARRL Handbook. Fig 13.26 has a legend which
says:
"To prevent shielding of the loop from magnetic fields, leave the shield
unconnected at one end."

I think the handbook has it right.

Best regards, Richard Harrison, KB5WZI


Michael Tope May 21st 06 08:57 AM

FIGHT? Here is another W8JI myth bone!
 

"Richard Harrison" wrote in message
...
Mike, W4EF wrote:
"I would agree, Richard, but at HF frequencies, the current path around
the shield isn`t real;ly broken by the gap."

To best describe what broken means, a picture helps. There is a picture
on page 13.18 of the 2006 ARRL Handbook. Fig 13.26 has a legend which
says:
"To prevent shielding of the loop from magnetic fields, leave the shield
unconnected at one end."


I am a bit behind on ARRL Handbooks, Richard, but from
what you describe, this is the same figure that appears in my
1992 edition (chapter 38, figure 2). In any case, what is
shown in the figure agrees with my understanding of "broken",
although admittedly when I made my previous post, I was
thinking of the case where the shield is broken on the side of
the loop opposite the feedpoint. For the purposes of this
discussion, however, it doesn't matter whether the break is
at the top (opposite the feed) or at the bottom (adjacent
to the feed). In either case, current induced on the inside
of the shield by current flowing on the center conductor loop
has a continuous back to ground via the outside surface of the
shield. IOW, the gap doesn't suppress the eddy current, rather
it forces it to flow on the outside surface of the shield, thereby
causing the loop to radiate.


I think the handbook has it right.


Yes, I agree it does. If you connect the shield at both ends, the
loop can't radiate because the eddy current caused by current
flowing on the inner conductor loop will confined to the inside of
the shield. Likewise, eddy currents induced on the outside of the
shield by EM waves passing the antenna will be confined to the
outside of the shield if there is no gap (reciprocity holds - the
antenna won't receive with no gap).

73, Mike W4EF.............................................. ...

Best regards, Richard Harrison, KB5WZI




[email protected] May 21st 06 10:42 AM

FIGHT? Here is another W8JI myth bone!
 

Michael Tope wrote:
I am a bit behind on ARRL Handbooks, Richard, but from

what you describe, this is the same figure that appears in my
1992 edition (chapter 38, figure 2). In any case, what is
shown in the figure agrees with my understanding of "broken",
although admittedly when I made my previous post, I was
thinking of the case where the shield is broken on the side of
the loop opposite the feedpoint. For the purposes of this
discussion, however, it doesn't matter whether the break is
at the top (opposite the feed) or at the bottom (adjacent
to the feed). In either case, current induced on the inside
of the shield by current flowing on the center conductor loop
has a continuous back to ground via the outside surface of the
shield. IOW, the gap doesn't suppress the eddy current, rather
it forces it to flow on the outside surface of the shield, thereby
causing the loop to radiate.


Absolutely nothing, neither electic nor magnetic, couplesthrough the
wall of a conductor more than several skin depths thick. This isn't
anything that can be debated, it is simply how it works. It is very
easy to demonstrate, it takes only a few minutes and a minimum of test
equipment.

It is something very basic in physics and underlies how coaxial cables
and things with shields of all types work.

The gap is the feedpoint no matter where the gap is placed. The
radiation and coupling of any time-varying field, magnetic or electric,
occurs on a frequency where the shield is more than a few skin depths
thick comes by the gap.

This is such a very basic thing it is important everyone understand it.


I think the handbook has it right.


Yes, I agree it does. If you connect the shield at both ends, the
loop can't radiate because the eddy current caused by current
flowing on the inner conductor loop will confined to the inside of
the shield.


Absolutely. When the gap is closed there is no potential difference
across the gap the outside of the shield is not connected to the inside
of the shield via the potential developed across the gap. The outer
wall is not coupled to the inner wall, the feedpoint is shorted.

When the gap is opened, the outside of the shield IS the antenna. Not
the inside or anything inside the inside.

Likewise, eddy currents induced on the outside of the
shield by EM waves passing the antenna will be confined to the
outside of the shield if there is no gap (reciprocity holds - the
antenna won't receive with no gap).


Again true. This is a very basic thing we must understand if we are to
understand how shields, walls, or conductors of any kind or form work
with HF currents, voltages, or fields of any type.

There isn't any way to change this effect.

73 Tom


Michael Tope May 21st 06 11:38 AM

FIGHT? Here is another W8JI myth bone!
 

wrote in message
ups.com...

Michael Tope wrote:
I am a bit behind on ARRL Handbooks, Richard, but from

what you describe, this is the same figure that appears in my
1992 edition (chapter 38, figure 2). In any case, what is
shown in the figure agrees with my understanding of "broken",
although admittedly when I made my previous post, I was
thinking of the case where the shield is broken on the side of
the loop opposite the feedpoint. For the purposes of this
discussion, however, it doesn't matter whether the break is
at the top (opposite the feed) or at the bottom (adjacent
to the feed). In either case, current induced on the inside
of the shield by current flowing on the center conductor loop
has a continuous back to ground via the outside surface of the
shield. IOW, the gap doesn't suppress the eddy current, rather
it forces it to flow on the outside surface of the shield, thereby
causing the loop to radiate.


Absolutely nothing, neither electic nor magnetic, couplesthrough the
wall of a conductor more than several skin depths thick. This isn't
anything that can be debated, it is simply how it works. It is very
easy to demonstrate, it takes only a few minutes and a minimum of test
equipment.


I don't think we disagree on that point, Tom. Perhaps I should
have chosen my words more carefully. I didn't mean to imply
that gap somehow forces the current on the inside of the shield
to pass through shield. When I said that the gap forces the current
to flow on the outside surface of the shield, I meant that in the
sense that the eddy current flows on the inside of the shield until
it reaches the break in the shield at which point the current flow
wraps around the edge of the shield and onto the outside surface
(thereby reversing direction relative to the direction of the eddy
current on the inside of the shield). The skin effect in effect
separates the shield into two distinct conductors, the inner surface
being one conductor and the outer surface of the shield being the
other. The gap is the circuit node where these two independent
conductors are connected. The eddy current flows out of one
conductor (the inner surface of the shield ) and into the other
conductor (the outer surface of the shield).

73, Mike W4EF.............................................. ...........






Cecil Moore May 21st 06 03:06 PM

FIGHT? Here is another W8JI myth bone!
 
wrote:
Absolutely nothing, neither electic nor magnetic, couplesthrough the
wall of a conductor more than several skin depths thick.


Do 60 Hz magnetic fields penetrate RF coax since
the conductor is not more than several skin depths
thick?
--
73, Cecil
http://www.qsl.net/w5dxp

Richard Harrison May 21st 06 10:07 PM

FIGHT? Here is another W8JI myth bone!
 
Tom, W8JI wrote:
"Absolutely nothing, neither electric nor magnetic, couples through the
wall of a conductor several skin depths thick."

That`s wrong for a "Faraday screen".

Terman is right. At the bottom of page 38 of his 1955 edition he writes:
"It is possible to shield electrostatic flux without simultaneously
affecting the magnetic field by surrounding the space to be shielded
with a conducting cage that is made in such a way as to provide no
low-resistance path for the flow of eddy currents, while at the same
time offering a metallic terminal upon which electrostatic flux lines
can terminate."

An example exists in the AM broadcast stations I`ve worked in. Every
tower was coupled to its transmission line through a 1:1 air-core
traansformer. Two identical single-layer solenoids sharing the same
axis. Between the coils was a metal picket fence. One end of the pickets
was firmly grounded to the coupling cabinet. The other end of all
pickets was an open circuit. Electric lines of force were intercepted by
the pickets and directly shorted to ground. However, the fences had no
effect on the magnetic coupling between them because the open circuit at
the ends of the pickets prevented circulating currents which would have
opposed magnetic coupling according to Lenz`s law.

Voila! Magnetic coupling but no electrostatic coupling between coils of
a transformer.

It`s time for W8JI to turn-off his misinformation machine.

Best regards, Richard Harrison, KB5WZI


Yuri Blanarovich May 22nd 06 01:07 AM

FIGHT? Here is another W8JI myth bone!
 
Richard,
"this can't be" because "gurus" know otherwise.
Why do you hate Tom? You don't like anything he says on his "myth
overturning" web pages. He describes in a such detail and explains that
"shield is an antenna" - why don't you get it? :-))))
According to Tom, RF gets induced on the outside "wire" of the shield, then
it crolls to the "inside" wire of the shield around the edge of the tubing
and sees another wire and jumps over, and then to coax.
If tubing or shield was the antenna, then it would receive DX and near field
signals the same way. The fact that shield is shielding the near field
signals should make any guru wonder.
There was ZS1 on TopBand reflector reporting that he used shielded loop and
other loop antennas, and shielded loop was the only one that suppressed the
local TV birdies. Tom "explained" to him "how things work" and he apologized
that he did not mean to have this as an example of what I was saying.

There are other examples where shield "doesn't shield" - like link coupling
made of coax with end shield open and center conductor soldered to the
shield. As I mentioned I have magnetothermia machine that produces about
200W from single shielded loop, according to Tom, it should be frying the
coax in the gap, with all that RF power trying to make the corner :-)

There is more nonsense on his web site.

73 Yuri, K3BU


"Richard Harrison" wrote in message
...
Tom, W8JI wrote:
"Absolutely nothing, neither electric nor magnetic, couples through the
wall of a conductor several skin depths thick."

That`s wrong for a "Faraday screen".

Terman is right. At the bottom of page 38 of his 1955 edition he writes:
"It is possible to shield electrostatic flux without simultaneously
affecting the magnetic field by surrounding the space to be shielded
with a conducting cage that is made in such a way as to provide no
low-resistance path for the flow of eddy currents, while at the same
time offering a metallic terminal upon which electrostatic flux lines
can terminate."

An example exists in the AM broadcast stations I`ve worked in. Every
tower was coupled to its transmission line through a 1:1 air-core
traansformer. Two identical single-layer solenoids sharing the same
axis. Between the coils was a metal picket fence. One end of the pickets
was firmly grounded to the coupling cabinet. The other end of all
pickets was an open circuit. Electric lines of force were intercepted by
the pickets and directly shorted to ground. However, the fences had no
effect on the magnetic coupling between them because the open circuit at
the ends of the pickets prevented circulating currents which would have
opposed magnetic coupling according to Lenz`s law.

Voila! Magnetic coupling but no electrostatic coupling between coils of
a transformer.

It`s time for W8JI to turn-off his misinformation machine.

Best regards, Richard Harrison, KB5WZI




Gene Fuller May 22nd 06 01:35 AM

FIGHT? Here is another W8JI myth bone!
 
Richard,

Think again about what you wrote. The "Faraday screen" is full of
openings between the wires of the picket fence. There is no evidence
that anything magnetic or electric penetrates the walls of the
conductors beyond a very shallow layer.

Terman certainly did not deny the existence of skin effect that keeps
the fields out of the interior of conductors.

73,
Gene
W4SZ

Richard Harrison wrote:
Tom, W8JI wrote:
"Absolutely nothing, neither electric nor magnetic, couples through the
wall of a conductor several skin depths thick."

That`s wrong for a "Faraday screen".

Terman is right. At the bottom of page 38 of his 1955 edition he writes:
"It is possible to shield electrostatic flux without simultaneously
affecting the magnetic field by surrounding the space to be shielded
with a conducting cage that is made in such a way as to provide no
low-resistance path for the flow of eddy currents, while at the same
time offering a metallic terminal upon which electrostatic flux lines
can terminate."

An example exists in the AM broadcast stations I`ve worked in. Every
tower was coupled to its transmission line through a 1:1 air-core
traansformer. Two identical single-layer solenoids sharing the same
axis. Between the coils was a metal picket fence. One end of the pickets
was firmly grounded to the coupling cabinet. The other end of all
pickets was an open circuit. Electric lines of force were intercepted by
the pickets and directly shorted to ground. However, the fences had no
effect on the magnetic coupling between them because the open circuit at
the ends of the pickets prevented circulating currents which would have
opposed magnetic coupling according to Lenz`s law.

Voila! Magnetic coupling but no electrostatic coupling between coils of
a transformer.

It`s time for W8JI to turn-off his misinformation machine.

Best regards, Richard Harrison, KB5WZI


Michael Tope May 22nd 06 01:42 AM

FIGHT? Here is another W8JI myth bone!
 

"Yuri Blanarovich" wrote in message
...

There are other examples where shield "doesn't shield" - like link
coupling made of coax with end shield open and center conductor soldered
to the shield. As I mentioned I have magnetothermia machine that produces
about 200W from single shielded loop, according to Tom, it should be
frying the coax in the gap, with all that RF power trying to make the
corner :-)


Yuri, think about how the "link coupling" magnetic loop you describe
above works. When the loop is energized where does the RF current
leaving the center conductor go? It has to flow onto the outside of the
shield. Where else could it go?

RF current "makes the corner" around to the outside surface of the
shield in coax all the time. If it didn't we wouldn't need choke
balun's.

73, Mike
W4EF.............................................. ...................




[email protected] May 22nd 06 01:32 PM

FIGHT? Here is another W8JI myth bone!
 
Gene Fuller wrote:
Richard,

Think again about what you wrote. The "Faraday screen" is full of
openings between the wires of the picket fence. There is no evidence
that anything magnetic or electric penetrates the walls of the
conductors beyond a very shallow layer.

Terman certainly did not deny the existence of skin effect that keeps
the fields out of the interior of conductors.


Gene,

You might have to find a book that quotes the description of a screen
with parallel wires and large air gaps as compared to a wall or
cylinder several skin depths thick.
:-)

73 Tom


Yuri Blanarovich May 22nd 06 03:42 PM

FIGHT? Here is another W8JI myth bone!
 

"Michael Tope" wrote in message
. ..

"Yuri Blanarovich" wrote in message
...

There are other examples where shield "doesn't shield" - like link
coupling made of coax with end shield open and center conductor soldered
to the shield. As I mentioned I have magnetothermia machine that produces
about 200W from single shielded loop, according to Tom, it should be
frying the coax in the gap, with all that RF power trying to make the
corner :-)


Yuri, think about how the "link coupling" magnetic loop you describe
above works. When the loop is energized where does the RF current
leaving the center conductor go? It has to flow onto the outside of the
shield. Where else could it go?

RF current "makes the corner" around to the outside surface of the
shield in coax all the time. If it didn't we wouldn't need choke
balun's.


We need RF chokes and baluns to supress curents induced on the shield from
the unbalance at the antenna feedpoint.
Sooo, according to W8JI "teachings", RF current gets induced onto the
outside surface of tubing, then crolls around the edges and goes inside the
tubing?
Sooo, we should cork the elements, or the current will get confused inside
of dark tubing elements, Eh?
Any formulas to calculate the resonance of such "antenna"??

73, Mike
W4EF.............................................. ...................


--
Yuri Blanarovich, K3BU, VE3BMV



Richard Harrison May 22nd 06 04:04 PM

FIGHT? Here is another W8JI myth bone!
 
Gene Fuller wrote:
"Terman certainly did not deny the existence of skin effect that keeps
fields out of the interior of conductors.'

true. The point is, shielding from magnetic fields is different from
electric fields. On page 35 of his 1955 edition, Terman writes:
"Magnetic flux in attempting to pass through a shield (copper or
aluminum) induces voltage in the shield which gives rise to eddy
currents. These eddy currents oppose the action of the flux, and in
large measure prevent its penetration through the shield."

On page 38, Terman writes:
"Electrostatic shielding is obtained by enclosing free space to be
shielded by a conducting surface."

On page 45, is problem 2-45 which contains an illustration of a grid of
open-circuit wires which "will provide electrostatic shielding without
magnetic shielding---." This works just like the picket fences used in
broadcast stations to inhibit harmonic transmission.

Terman did not make this stuff up. It was already in wide use at the
time.

Best regards, Richard Harrison, KB5WZI


Gary Schafer May 22nd 06 04:59 PM

FIGHT? Here is another W8JI myth bone!
 
On Mon, 22 May 2006 10:42:40 -0400, "Yuri Blanarovich"
wrote:


"Michael Tope" wrote in message
...

"Yuri Blanarovich" wrote in message
...

There are other examples where shield "doesn't shield" - like link
coupling made of coax with end shield open and center conductor soldered
to the shield. As I mentioned I have magnetothermia machine that produces
about 200W from single shielded loop, according to Tom, it should be
frying the coax in the gap, with all that RF power trying to make the
corner :-)


Yuri, think about how the "link coupling" magnetic loop you describe
above works. When the loop is energized where does the RF current
leaving the center conductor go? It has to flow onto the outside of the
shield. Where else could it go?

RF current "makes the corner" around to the outside surface of the
shield in coax all the time. If it didn't we wouldn't need choke
balun's.


We need RF chokes and baluns to supress curents induced on the shield from
the unbalance at the antenna feedpoint.
Sooo, according to W8JI "teachings", RF current gets induced onto the
outside surface of tubing, then crolls around the edges and goes inside the
tubing?
Sooo, we should cork the elements, or the current will get confused inside
of dark tubing elements, Eh?
Any formulas to calculate the resonance of such "antenna"??

73, Mike
W4EF.............................................. ...................


Yuri,

It is true that current will not flow on the inside of a tube from
current on the outside. The "waveguide beyond cutoff" effect keeps it
from doing so. The currents quickly cancel a short distance inside the
tube.
However, if you put a conductor inside that tube (wire) now it acts
like a coax cable and the energy on the center conductor couples to
the inside wall of the tube. At the end of the tube the current is
free to wrap around to the outside.

73
Gary K4FMX


Michael Tope May 22nd 06 05:49 PM

FIGHT? Here is another W8JI myth bone!
 

"Yuri Blanarovich" wrote in message
...

RF current "makes the corner" around to the outside surface of the
shield in coax all the time. If it didn't we wouldn't need choke
balun's.


We need RF chokes and baluns to supress curents induced on the shield from
the unbalance at the antenna feedpoint.


Actually what oftentimes happens with a coax feed is that the RF
current leaving the inside of the feedline shield can flow in two
directions. It can flow down the antenna element half connected to the
shield (desired path), or it can flow down the outside of the shield
(undesired path). The electrons are dumb, all they are looking for is
the path of least resistance. They can't tell that the metal surface
on the outside of the coax isn't supposed to be part of the antenna.
The only way to keep current from flowing down the shield is make
the antenna element-half connected to the shield look like a lower
impedance than the outside of the shield. If you place ferrite beads
around the outside of the shield, this will raise the impedance of the
shield path, thereby diverting the bulk of the RF current into the
element-half and off of the shield's outside surface.

Sooo, according to W8JI "teachings", RF current gets induced onto the
outside surface of tubing, then crolls around the edges and goes inside
the tubing?


As per K4FMX's comments, this can only happen if there is a
center conductor inside the tubing, or if the tubing diameter is greater
than ~1/2 wavelength in diameter, otherwise the inside of the tubing
looks like a circular waveguide beyond cutoff. This is why coax
of a given diameter becomes useless above a certain upper frequency
limit. Once the I.D. of the coax becomes a significant fraction of a
wavelength in diameter, the coax will start to support propagation of
waveguide modes (e.g. non-TEM modes). At HF frequencies, even
large diameter tubing is well beyond waveguide cutoff, so there is no
concern about "corking" open tubing with no center conductor (it
corks itself).

73, Mike W4EF.............................................. .......

Sooo, we should cork the elements, or the current will get confused inside
of dark tubing elements, Eh?
Any formulas to calculate the resonance of such "antenna"??




Cecil Moore May 22nd 06 06:23 PM

FIGHT? Here is another W8JI myth bone!
 
Michael Tope wrote:
The electrons are dumb, all they are looking for is
the path of least resistance.


Hmmmm, electrons that know ohm's law sound pretty
smart to me. :-)
--
73, Cecil http://www.qsl.net/w5dxp

Roy Lewallen May 23rd 06 06:00 PM

FIGHT? Here is another W8JI myth bone!
 
Richard Harrison wrote:
Gene Fuller wrote:
"Terman certainly did not deny the existence of skin effect that keeps
fields out of the interior of conductors.'

true. The point is, shielding from magnetic fields is different from
electric fields. On page 35 of his 1955 edition, Terman writes:
"Magnetic flux in attempting to pass through a shield (copper or
aluminum) induces voltage in the shield which gives rise to eddy
currents. These eddy currents oppose the action of the flux, and in
large measure prevent its penetration through the shield."
. . .


Am I mistaken, but is this not a clear statement that a copper or
aluminum shield will block magnetic flux, along with an explanation of
why it happens?

Roy Lewallen, W7EL

K7ITM May 23rd 06 06:17 PM

FIGHT? Here is another W8JI myth bone!
 
Seems pretty clear to me, Roy. The effectiveness of a copper strap
around a mains-frequency power transformer at reducing the exterior
magnetic field is well known and often used. It's all very clear from
Faraday's law of magnetic induction: the net magnetic flux through an
area enclosed by a perfect conductor may not change, so time-varying
magnetic fields are perfectly blocked by perfect conductors. Copper's
a reasonable approximation of a perfect conductor in the case of RF
shields.

Cheers,
Tom


[email protected] May 23rd 06 06:18 PM

FIGHT? Here is another W8JI myth bone!
 

Roy Lewallen wrote:
Richard Harrison wrote:
Gene Fuller wrote:
"Terman certainly did not deny the existence of skin effect that keeps
fields out of the interior of conductors.'

true. The point is, shielding from magnetic fields is different from
electric fields. On page 35 of his 1955 edition, Terman writes:
"Magnetic flux in attempting to pass through a shield (copper or
aluminum) induces voltage in the shield which gives rise to eddy
currents. These eddy currents oppose the action of the flux, and in
large measure prevent its penetration through the shield."
. . .


Am I mistaken, but is this not a clear statement that a copper or
aluminum shield will block magnetic flux, along with an explanation of
why it happens?

Roy Lewallen, W7EL


It would only be a clear statement to those who understand what was
quoted from Terman.

If a person is confused by or somehow DOESN'T understand what Terman is
saying, he or she might take it to mean magnetic fields can travel
unimpeded through a shield.

It sure is difficult to drive a stake through the heart of myths like
the loop shield "shielding the electric field and not the magnetic
field" when clearly written text in dozens of engineering textbooks is
misunderstood.

73 Tom


Richard Clark May 23rd 06 06:20 PM

FIGHT? Here is another W8JI myth bone!
 
On 23 May 2006 10:17:31 -0700, "K7ITM" wrote:

Seems pretty clear to me, Roy. The effectiveness of a copper strap
around a mains-frequency power transformer at reducing the exterior
magnetic field is well known and often used. It's all very clear from
Faraday's law of magnetic induction: the net magnetic flux through an
area enclosed by a perfect conductor may not change, so time-varying
magnetic fields are perfectly blocked by perfect conductors. Copper's
a reasonable approximation of a perfect conductor in the case of RF
shields.


Hi Tom,

However, Richard's explanation is the analogue of the effectiveness of
a copper strap (with a non-contacting overlap so as to not be a
shorted turn) between windings of a mains-frequency power transformer,
and grounded to provide electrostatic separation of the two circuits.

73's
Richard Clark, KB7QHC

Cecil Moore May 23rd 06 08:22 PM

FIGHT? Here is another W8JI myth bone!
 
wrote:
If a person is confused by or somehow DOESN'T understand what Terman is
saying, he or she might take it to mean magnetic fields can travel
unimpeded through a shield.


I have asked this simple question a number of times and, so
far, no one has answered. It should have a simple answer so
here it is again. Does a 60 Hz magnetic field travel virtually
unimpeded through a coax shield? This question involves 60 Hz
noise being coupled through coax.
--
73, Cecil
http://www.qsl.net/w5dxp

Roy Lewallen May 23rd 06 10:16 PM

FIGHT? Here is another W8JI myth bone!
 
Richard Harrison wrote:
Roy Lewallen, W7EL wrote:
"Am I mistaken, but is this not a clear statement that a copper or
aluminum shield will block magnetic flux along with explanation of why
it happens?"

Yes. And now the rest of the story which I`ve already posted several
times.

At the bottom of page 38 in Terman`s 1955 edition;
"It is possible to shield slectrostatic flux WITHOUT simultaneously
affecting the magnetic field by surrounding the space to be shielded
with a conducting cage that is made in such a way as to provide NO
low-resistance path for the flow of eddy currents, while at the same
time offering a metallic terminal upon which electrostatic flux can
terminate."

I invited readers to look at page 43 in the same book whe
"A grid of wires such as shown in the accompanying figure will provide
electrostatic shielding WITHOUT magnetic shielding---."

I also said that similar grids (metal picket fences) were used in AM
broadcast stations I`d worked in to eliminate capacitive coupling to the
antennas which would otherwise favor harmonics of the broadcast
frequency.

W8JI is yet desiring to drive a stake in the heart of the "myth" that
E&H fields are separable if even for an instant. He is dead wrong.


Certainly the E or H field can disappear for part of a cycle. This
happens routinely in a transmission line or in free space, as the energy
is swapped back and forth between the two components. Tom has never said
this is not so. And for whole cycles you can locally change the ratio of
E/H, but you cannot separate them. Maxwell's equations show this. And if
you do change the ratio of E/H, the normal free space ratio is restored
within a small distance.

The magnetic field alone does quite well in transferring all the wave`s
energy through a special transformer which completely bars the electric
field. Of course, current in the transformer`s secondary produces a
voltage and the E-field is immediately restored.


Yes. And does this restored E field not occupy the space between the
winding and the wire grid? If so, how can you tell that the grid has
"stopped" the E field if it exists on both sides of the grid?

This is not witchcraft. In free-space the electric field and the
magnetic field are repeatedly exchanging all the energy back and forth.
It keeps the wave going.


With this I totally agree. That explanation is related to why you can't
simply remove one component or the other.

At a short or open on a transmission line energy is not lost. It is
merely transferred for an instant into the surviving field.

Similarly, all the energy can be transferred through the electric field
with zero magnetic coupling. Imagine two separately shielded coils. Now,
use a coupling capacitor to transfer the energy from one coil to the
other. Voila! E-field transfer with zero magnetic coupling. It`s no
myth. It`s a fact.


It's a myth that there's no magnetic field in the space between a
capacitor's plates.

Roy Lewallen, W7EL

Richard Harrison May 23rd 06 11:14 PM

FIGHT? Here is another W8JI myth bone!
 
Roy, W7EL wrote:
"It`s a myth that there`s no magnetic field in the space between a
capacitor`s plates."

Maxwell`s great speculation was that "displacement current", as between
a capacitor`s plates, produced magnetic flux as does conduction current.
His speculation is now proved.

Best regards, Richard Harrison, KB5WZI



Tom Donaly May 23rd 06 11:19 PM

FIGHT? Here is another W8JI myth bone!
 
Richard Harrison wrote:
Cecil, W5DXP wrote:
"Does a 60 Hz magnetic field travel virtually unimpeded through a
coaxial shield?"

Surely many readers have toiled with shielded audio cables similar to
coax and they know the answer is yes, if the shield is broken (this
often happens at the ends of the cable).

Best regards, Richard Harrison, KB5WZI


The skin depth of copper at 60 hertz is supposed to be 8.53mm. That's
too thick to make a practical shield. No wonder they're having problems.
73,
Tom Donaly, KA6RUH

Roy Lewallen May 23rd 06 11:31 PM

FIGHT? Here is another W8JI myth bone!
 
Richard Harrison wrote:
Roy, W7EL wrote:
"It`s a myth that there`s no magnetic field in the space between a
capacitor`s plates."

Maxwell`s great speculation was that "displacement current", as between
a capacitor`s plates, produced magnetic flux as does conduction current.
His speculation is now proved.


Yes. So how does a capacitor between two inductors constitute "E-field
transfer with zero magnetic coupling" as you stated?

Roy Lewallen, W7EL

Tom Donaly May 23rd 06 11:35 PM

FIGHT? Here is another W8JI myth bone!
 
Richard Harrison wrote:

Roy Lewallen, W7EL wrote:
"Am I mistaken, but is this not a clear statement that a copper or
aluminum shield will block magnetic flux along with explanation of why
it happens?"

Yes. And now the rest of the story which I`ve already posted several
times.

At the bottom of page 38 in Terman`s 1955 edition;
"It is possible to shield slectrostatic flux WITHOUT simultaneously
affecting the magnetic field by surrounding the space to be shielded
with a conducting cage that is made in such a way as to provide NO
low-resistance path for the flow of eddy currents, while at the same
time offering a metallic terminal upon which electrostatic flux can
terminate."

I invited readers to look at page 43 in the same book whe
"A grid of wires such as shown in the accompanying figure will provide
electrostatic shielding WITHOUT magnetic shielding---."

I also said that similar grids (metal picket fences) were used in AM
broadcast stations I`d worked in to eliminate capacitive coupling to the
antennas which would otherwise favor harmonics of the broadcast
frequency.

W8JI is yet desiring to drive a stake in the heart of the "myth" that
E&H fields are separable if even for an instant. He is dead wrong.

The magnetic field alone does quite well in transferring all the wave`s
energy through a special transformer which completely bars the electric
field. Of course, current in the transformer`s secondary produces a
voltage and the E-field is immediately restored.

This is not witchcraft. In free-space the electric field and the
magnetic field are repeatedly exchanging all the energy back and forth.
It keeps the wave going.

At a short or open on a transmission line energy is not lost. It is
merely transferred for an instant into the surviving field.

Similarly, all the energy can be transferred through the electric field
with zero magnetic coupling. Imagine two separately shielded coils. Now,
use a coupling capacitor to transfer the energy from one coil to the
other. Voila! E-field transfer with zero magnetic coupling. It`s no
myth. It`s a fact.

Best regards, Richard Harrison, KB5WZI


When did you perform this experiment, Richard? (Perfectly shielding two
coils and then coupling them with a capacitor.) And how did you manage
to shield them if, as you seem to think, the magnetic fields are capable
of penetrating the shield?
73,
Tom Donaly, KA6RUH

Cecil Moore May 24th 06 01:24 AM

FIGHT? Here is another W8JI myth bone!
 
Roy Lewallen wrote:
It's a myth that there's no magnetic field in the space between a
capacitor's plates.


What quantum particles support that magnetic field?
--
73, Cecil http://www.qsl.net/w5dxp

Cecil Moore May 24th 06 01:26 AM

FIGHT? Here is another W8JI myth bone!
 
Tom Donaly wrote:
The skin depth of copper at 60 hertz is supposed to be 8.53mm. That's
too thick to make a practical shield. No wonder they're having problems.


So 60 Hz magnetic fields penetrate shielded coax?
--
73, Cecil http://www.qsl.net/w5dxp

Michael Tope May 24th 06 02:59 AM

FIGHT? Here is another W8JI myth bone!
 

"Cecil Moore" wrote in message
om...
Tom Donaly wrote:
The skin depth of copper at 60 hertz is supposed to be 8.53mm. That's
too thick to make a practical shield. No wonder they're having problems.


So 60 Hz magnetic fields penetrate shielded coax?
--
73, Cecil http://www.qsl.net/w5dxp


Cecil, if ever I had the feeling that I was about to answer a loaded
question, this is it, but here goes anyway - "Yes, I believe a 60 Hz
magnetic field impinging on a piece of shielded coax would penetrate
the shield of that coax significantly if the shield were made of a
non-ferrous conductor."

73, Mike W4EF.............................................




Cecil Moore May 24th 06 04:20 AM

FIGHT? Here is another W8JI myth bone!
 
Michael Tope wrote:

"Cecil Moore" wrote:
So 60 Hz magnetic fields penetrate shielded coax?


Cecil, if ever I had the feeling that I was about to answer a loaded
question, this is it, but here goes anyway - "Yes, I believe a 60 Hz
magnetic field impinging on a piece of shielded coax would penetrate
the shield of that coax significantly if the shield were made of a
non-ferrous conductor."


It's not a loaded question. I just always assumed that coax
would shield the system from 60 Hz noise and I guess I was
wrong.
--
73, Cecil http://www.qsl.net/w5dxp

Yuri Blanarovich May 24th 06 04:34 AM

FIGHT? Here is another W8JI myth bone!
 

"Richard Harrison" wrote

Similarly, all the energy can be transferred through the electric field
with zero magnetic coupling. Imagine two separately shielded coils. Now,
use a coupling capacitor to transfer the energy from one coil to the
other. Voila! E-field transfer with zero magnetic coupling. It`s no
myth. It`s a fact.

Best regards, Richard Harrison, KB5WZI


I wonder how the gurus 'splain the different behavior of vertical vs.
horizontally polarized antennas, where E field determines the way signals
reflect and form the pattern. If E and H fields are so "inseparable" there
should be no difference, right?

They are ignoring behavior of E and H fields within the near field of
antennas and workings of the shield.

Another example of shield's performance was when I had small shielded loop
next to the Beverage. The combination gave better S/N performance and better
signal levels than each of them alone. Again, shield performing shielding
function in the vicinity of near field of both antennas. Loops were tunable
and performing as an antenna, shield was shielding from the near by
interference and providing symmetry. FACTS - verifiable not subject to wild
speculations about current crawling around the edge to inside of tubing, or
antenna inside of electrostatic shield quitting to work as antenna because
of "W8JI shield is antenna teachings".

--
Yuri Blanarovich, K3BU, VE3BMV




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