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#1
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Tom,
I expect there's not supposed to be any feedline between the antenna and the tuner in this installation, so I think that it probably is to moderate the impedance for a ham band antenna cut for the lowest band. It is witchcraft, but if you're selling antenna tuners to people who don't know anything about the impedance issues with an all band wire, it's better to give them a rule of thumb to avoid cooking the tuner, especially when they don't read the bit in the manual where it's a "100W" tuner on SSB and they fire up on RTTY. BKR, where did you get that explanation? I think you should measure the RF on the outside of your coax when it's an odd multiple of a quarter wave long including the loading effect of the case of the radio and the ground half of your dipole is made 5% longer than the other half. Listen to Tom. He knows common-mode current on the feedline! Dan N3OX |
#2
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#3
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![]() If I have a different length on the case of the tuner compared to the length on the hot terminal, how does that moderate impedance? Assuming you're speaking of a resonant dipole or verticle, it would seem to me that by doing that you are moving the feedpoint away from the 50 ohm (70 ohm?) feedpoint at the center.... and probably towards a higher impedance feedpoint. Not sure what effect that would have on those autotuners, but perhaps they work better with a bit higher impedance than 50 ohms? Ed K7AAT |
#5
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I was thinking along the same lines as Jon, LA4RT when I posted my
comment... using an 80m dipole on 40m, maybe you want to move the feedpoint away from the current node. How about this. If you make one leg 5% longer than the other: The length of leg 1 is L, the length of leg 2 is 1.05L. What do you need to have an integer number of half wavelengths on each side of the feedpoint? (This is the only time you can get a mid element current node, right?) L=m*lambda/2 1.05L=n*lambda/2 = 1.05(m*lambda/2)=n*lambda/2 The lowest integers that satisfy this: n/m = 105/100 = 21/20. So until you hit 21 halfwaves on one side and 20 halfwaves on the other, I think you don't have a current node at the feedpoint. Is this desirable? I think it probably is, but I am not a tuner expert. 73, Dan |
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