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#1
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wondering if someone can provide me with the length or the plans of a
6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh |
#2
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physical or electrical?
With such a question I'm wondering what "technician licence class" means... BTW looking at your mail address, I think I'll rather send anything via eqsl. Or perhaps did I miss something? My English is not really perfect. Keep on trying. BILL GRIESCH -K2WDG trolled: wondering if someone can provide me with the length or the plans of a 6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh |
#3
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![]() "BILL GRIESCH -K2WDG" wrote in message ... wondering if someone can provide me with the length or the plans of a 6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh the general rule is L = 234/F, where F is the frequency in megahertz, and L is the length of a quarter wave element in feet. this is a strange troll, can't you come up with something better? Gravity |
#4
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gravity wrote:
"BILL GRIESCH -K2WDG" wrote in message ... wondering if someone can provide me with the length or the plans of a 6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh the general rule is L = 234/F, where F is the frequency in megahertz, and L is the length of a quarter wave element in feet. this is a strange troll, can't you come up with something better? Gravity The formula, which I learned as a novice, I think, is length is=468/f(in mHz) |
#5
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On Mon, 19 Jun 2006 19:35:37 -0500, Butch Magee
wrote: gravity wrote: the general rule is L = 234/F, where F is the frequency in megahertz, and L is the length of a quarter wave element in feet. this is a strange troll, can't you come up with something better? Gravity The formula, which I learned as a novice, I think, is length is=468/f(in mHz) Read the text carefully, he is talking about each of the two 1/4 wave elements that make up a half wave dipole. BTW, what is 468/2 ??? -- 73 for now Buck N4PGW |
#6
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3 meters.
Almost 10 years licensed ... WOW BILL GRIESCH -K2WDG wrote: wondering if someone can provide me with the length or the plans of a 6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh |
#7
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In message , BILL GRIESCH -K2WDG
writes wondering if someone can provide me with the length or the plans of a 6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh By chance I made one at the weekend. 113.5", 1/2 " diam ali tubing. I used the yoke of an old TV CRT as a choke balun with a few turns of UR67. If you don't have space, a simple cubical quad is pretty compact. 73 Brian GM4DIJ -- Brian Howie |
#8
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![]() BILL GRIESCH -K2WDG wrote: wondering if someone can provide me with the length or the plans of a 6m dipole.. i have 6m's but i dont have the room to put up a full blowen ant i think that a dipole would work fo me please email at k2wdg@k2wdg with any information thanks in advance bill k2wdgh Boy, that's a tough question! Wonder why you bothered to post - would think a ham could calculate that one - additionally, its so simple to calculate or to find the length on the Internet these days, probably took you longer to type the question...boy, makes ya wonder...remember when? |
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