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Radiating Efficiency
"Frank's" wrote W7EL tells us that EZNEC doesn't display the surface wave which obviously contains power. Would that affect the efficiency using the integration technique? ====================================== The surface or ground wave is the most important fraction of total radiated power. The correct radiation pattern of a vertical antenna shows maximum radiation along the ground. Angle of maximum radiation = 0 degrees. When deducing efficiency, to omit power radiated along the ground from the hemispherical integration will result in serious error. ( Efficiency by NEC4 ) / ( Efficiency by formula ) = 0.38 I can imagine other losses in addition to loss in the radials but to have the other losses several times greater is a bit much. Where are these large losses? Are they in the soil surface - the only other candidate? ---- Reg. |
Radiating Efficiency
This thread is getting interesting...
Reg, your point that the resonant radial effects are more pronounced at higher frequencies makes me think that a small experiment might be in order. A 21MHz or so ground mounted monopole with a small radial field would be a minimal investment in materials to do a BLE style empirical investigation, at least compared to that at 3MHz. It wouldn't be a minimal investment in time but might be an interesting experiment. Given that it would be an epic challenge to measure field strength at a grid of points on a hemisphere surrounding the monopole, I imagine a single point field strength measurement would be an acceptable metric? Thoughts on doing the measurement? I guess BLE would be a good guide for the empiricist. Dan |
Radiating Efficiency
"Reg Edwards" wrote in message ... "Frank's" wrote W7EL tells us that EZNEC doesn't display the surface wave which obviously contains power. Would that affect the efficiency using the integration technique? ====================================== The surface or ground wave is the most important fraction of total radiated power. The correct radiation pattern of a vertical antenna shows maximum radiation along the ground. Angle of maximum radiation = 0 degrees. When deducing efficiency, to omit power radiated along the ground from the hemispherical integration will result in serious error. ( Efficiency by NEC4 ) / ( Efficiency by formula ) = 0.38 I can imagine other losses in addition to loss in the radials but to have the other losses several times greater is a bit much. Where are these large losses? Are they in the soil surface - the only other candidate? ---- Reg. Correct Reg, I had thought the modified RP card considered ground wave, but it does not. I am working on a combined integration including the surface wave, which should provide a more accurate indication of the overall efficiency. I will also attempt the analysis of various lengths of radial wires. Frank |
Radiating Efficiency
Dan wrote -
A 21MHz or so ground mounted monopole with a small radial field would be a minimal investment in materials to do a BLE style empirical investigation, at least compared to that at 3MHz. It wouldn't be a minimal investment in time but might be an interesting experiment. Given that it would be an epic challenge to measure field strength at a grid of points on a hemisphere surrounding the monopole, I imagine a single point field strength measurement would be an acceptable metric? Thoughts on doing the measurement? I guess BLE would be a good guide for the empiricist. ======================================== The results of such experiments would probably generate far less interest than BLE's original work and would not be of great use. But somebody might possibly create a reputation out of it. To repeat BLE's experiments at HF, and to be of use, would require measurements to be made over a wide range of frequencies, over various lengths of radials, over various numbers of radials, over a range of soil resistivities and over a range of soil permittivities. Complexity and cost would be enormous. Financial returns would be relatively small. Who would invest in such a project? How many people wishing to erect a 28 MHz vertical over a set of radials need more knowledge than what already exists. Even CB-ers could do it! It would be far more economic, with a guessed understanding of how radials work, to write and dedicate a computer program to do the job. With a little more tidying-up, program Radial_3 would do. And it's FREE to USA citizens. No licence required! ;o) ---- Reg. |
Radiating Efficiency
The surface or ground wave is the most important fraction of total
radiated power. The correct radiation pattern of a vertical antenna shows maximum radiation along the ground. Angle of maximum radiation = 0 degrees. When deducing efficiency, to omit power radiated along the ground from the hemispherical integration will result in serious error. ( Efficiency by NEC4 ) / ( Efficiency by formula ) = 0.38 I can imagine other losses in addition to loss in the radials but to have the other losses several times greater is a bit much. Where are these large losses? Are they in the soil surface - the only other candidate? ---- Reg. Correct Reg, I had thought the modified RP card considered ground wave, but it does not. I am working on a combined integration including the surface wave, which should provide a more accurate indication of the overall efficiency. I will also attempt the analysis of various lengths of radial wires. Frank Reg, with the antenna we have established as our test model: All wires #14, monopole 9 m, 36 X 10m radials 25 mm below ground. Ground parameters Er = 16, resistivity 150 ohm-m. I have calculated the radiation efficiency including the surface wave. What is interesting is that the surface wave contributes very little at elevation angles over 10 degrees. For 100 W input the total radiated power, not considering the surface wave, is 31 W. When the surface wave is included the total radiated power is 36 W. Frank |
Radiating Efficiency
"Frank's" wrote Reg, with the antenna we have established as our test model: All wires #14, monopole 9 m, 36 X 10m radials 25 mm below ground. Ground parameters Er = 16, resistivity 150 ohm-m. I have calculated the radiation efficiency including the surface wave. What is interesting is that the surface wave contributes very little at elevation angles over 10 degrees. For 100 W input the total radiated power, not considering the surface wave, is 31 W. When the surface wave is included the total radiated power is 36 W. ========================================== Frank, So the missing 64 watts, if not dissipated in the radials must be dissipated in the soil under the antenna. To prove something, what is the efficiency when the ground is sea water. Resistivity = 0.22 ohm-metres and permittivity = 80. PLEASE CONFIRM THE NUMBER OF RADIALS. I thought you were unable to model 36 radials. Were you using only 1 radial? With only 1 radial my program makes efficiency = 28 percent. Which would be satisfactory agreement with your 36 % ) Or did you substitute the radial system with a lumped resistance of 5 ohms which I suggested could be used when estimating efficiency? ---- Reg. |
Radiating Efficiency
Frank's wrote:
The surface or ground wave is the most important fraction of total radiated power. The correct radiation pattern of a vertical antenna shows maximum radiation along the ground. Angle of maximum radiation = 0 degrees. When deducing efficiency, to omit power radiated along the ground from the hemispherical integration will result in serious error. ( Efficiency by NEC4 ) / ( Efficiency by formula ) = 0.38 I can imagine other losses in addition to loss in the radials but to have the other losses several times greater is a bit much. Where are these large losses? Are they in the soil surface - the only other candidate? ---- Reg. Correct Reg, I had thought the modified RP card considered ground wave, but it does not. I am working on a combined integration including the surface wave, which should provide a more accurate indication of the overall efficiency. I will also attempt the analysis of various lengths of radial wires. Frank Reg, with the antenna we have established as our test model: All wires #14, monopole 9 m, 36 X 10m radials 25 mm below ground. Ground parameters Er = 16, resistivity 150 ohm-m. I have calculated the radiation efficiency including the surface wave. What is interesting is that the surface wave contributes very little at elevation angles over 10 degrees. For 100 W input the total radiated power, not considering the surface wave, is 31 W. When the surface wave is included the total radiated power is 36 W. Frank Good. Now all you have to do is verify your calculations experimentally. 73, Tom Donaly, KA6RUH |
Radiating Efficiency
Reg, with the antenna we have established as our test model:
All wires #14, monopole 9 m, 36 X 10m radials 25 mm below ground. Ground parameters Er = 16, resistivity 150 ohm-m. I have calculated the radiation efficiency including the surface wave. What is interesting is that the surface wave contributes very little at elevation angles over 10 degrees. For 100 W input the total radiated power, not considering the surface wave, is 31 W. When the surface wave is included the total radiated power is 36 W. Frank Good. Now all you have to do is verify your calculations experimentally. 73, Tom Donaly, KA6RUH You got that right. I need a serious VNA so bad, I can taste it! 73, Frank |
Radiating Efficiency
Tom Donaly wrote: Frank's wrote: The surface or ground wave is the most important fraction of total radiated power. The correct radiation pattern of a vertical antenna shows maximum radiation along the ground. Angle of maximum radiation = 0 degrees. When deducing efficiency, to omit power radiated along the ground from the hemispherical integration will result in serious error. ( Efficiency by NEC4 ) / ( Efficiency by formula ) = 0.38 I can imagine other losses in addition to loss in the radials but to have the other losses several times greater is a bit much. Where are these large losses? Are they in the soil surface - the only other candidate? ---- Reg. Correct Reg, I had thought the modified RP card considered ground wave, but it does not. I am working on a combined integration including the surface wave, which should provide a more accurate indication of the overall efficiency. I will also attempt the analysis of various lengths of radial wires. Frank Reg, with the antenna we have established as our test model: All wires #14, monopole 9 m, 36 X 10m radials 25 mm below ground. Ground parameters Er = 16, resistivity 150 ohm-m. I have calculated the radiation efficiency including the surface wave. What is interesting is that the surface wave contributes very little at elevation angles over 10 degrees. For 100 W input the total radiated power, not considering the surface wave, is 31 W. When the surface wave is included the total radiated power is 36 W. Frank Good. Now all you have to do is verify your calculations experimentally. 73, Tom Donaly, KA6RUH That's right. Without verification by direct measurements any program like this is guesswork. 73 Tom |
Radiating Efficiency
"Reg Edwards" wrote in message ... "Frank's" wrote Reg, with the antenna we have established as our test model: All wires #14, monopole 9 m, 36 X 10m radials 25 mm below ground. Ground parameters Er = 16, resistivity 150 ohm-m. I have calculated the radiation efficiency including the surface wave. What is interesting is that the surface wave contributes very little at elevation angles over 10 degrees. For 100 W input the total radiated power, not considering the surface wave, is 31 W. When the surface wave is included the total radiated power is 36 W. ========================================== Frank, So the missing 64 watts, if not dissipated in the radials must be dissipated in the soil under the antenna. To prove something, what is the efficiency when the ground is sea water. Resistivity = 0.22 ohm-metres and permittivity = 80. PLEASE CONFIRM THE NUMBER OF RADIALS. I thought you were unable to model 36 radials. Were you using only 1 radial? With only 1 radial my program makes efficiency = 28 percent. Which would be satisfactory agreement with your 36 % ) Or did you substitute the radial system with a lumped resistance of 5 ohms which I suggested could be used when estimating efficiency? Reg, The antenna has thirty-six 10 m radials, 25 mm below ground. The input impedance at 8.07 MHz is 36.3 - j 2.0. I used 0.2 ohm-m for sea water resistivity as it seems to the accepted standard. The radiation efficiency, not including the surface wave, is 93.6 %. I can add the surface wave if you are interested, but it is a little tedious to convert the far field surface wave, in cylindrical coordinates, to normalized spherical coordinates; which is the form NEC produces for the sky-wave components. Frank |
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