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![]() 'Doc wrote: JJ, Got a book, even read it. You might do the same... 'Doc I did, some time ago and here is what I found. Just for you....from "The Radio Amateur's Handbook". This is concerning the amount of audio power to modulate a carrier. "The modulator must be capable of supplying to the modulated r.f. stage sine-wave audio power equal to 50 per cent of the d.c. plate input. For example, if the d.c plate power input to the r.f. stage is 100 watts, the sine-wave audio power output of the modulator must be 50 watts." "With a sine-wave modulating signal, the average power in a 100 per cent modulated wave is one and one-half times the value of unmodulated carrier power; that is, the power output if the transmitter increases 50 per cent with 100 per cent modulation." From "Elements of Radio", by William Marcus "It can be calculated mathematically that the average power of the modulated carrier is one and one half times that of the unmodulated carrier. Since this 50 per cent increase in power must come from the modulator, the audio frequency power must be ONE HALF the unmodulated carrier." In other words Doc, for 100% plate modulation of a 1000 watt carrier you need 500 watts of audio. Your calculation that 1000 watts carrier divided by 500 watts audio equals 50 per cent modulation proves you know nothing about the subject. |
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