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#1
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John Smith wrote:
... One thing I do totally agree with, it WILL work well with just a wire reflector. Regards, JS I built this, actually, a while back. Toss in a director (what is one more wire?); I found that to be a worthwhile mod ... Regards, JS |
#2
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I built this, actually, a while back. Toss in a director (what is one
more wire?); I found that to be a worthwhile mod ... Regards, JS Suggestions re. dimensions and location of a director? Thanks. |
#3
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SparkyGuy wrote:
I built this, actually, a while back. Toss in a director (what is one more wire?); I found that to be a worthwhile mod ... Regards, JS Suggestions re. dimensions and location of a director? Thanks. I believe I tried lengths of a 3% to 5% shorter length with the director, than the drive element (i.e., the one in front of the reflector), settling on a 4% shorter length ... anyway, that is common in HF parasitic arrays ... this is equiv. to a 3-element quad on HF. I just dug it out and measured it, this is what it appears to be, alright. With a spacing between driven element and director of ~0.2 wavelength, center-to-center. Regards, JS |
#4
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I believe I tried lengths of a 3% to 5% shorter length with the
director, than the drive element (i.e., the one in front of the reflector), settling on a 4% shorter length ... So about 26.8mm square? With a spacing between driven element and director of ~0.2 wavelength, center-to-center. So the director should be 25 mm forward (toward the uwave source) of the driven element? (3e8 / 2.4e9) x 0.2 = ~25mm Do these numbers look right? Thanks. |
#5
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SparkyGuy wrote:
I believe I tried lengths of a 3% to 5% shorter length with the director, than the drive element (i.e., the one in front of the reflector), settling on a 4% shorter length ... So about 26.8mm square? With a spacing between driven element and director of ~0.2 wavelength, center-to-center. So the director should be 25 mm forward (toward the uwave source) of the driven element? (3e8 / 2.4e9) x 0.2 = ~25mm Do these numbers look right? Thanks. My elements are made from #14 bare copper wire. It is difficult to measure each side, individually, when constructing the antenna. Better to cut the wire to 1 wavelength, then make your bends forming it into a square. Of course, every attempt possible should be made to keep each side 1/4 of this length, exactly. In measuring the one before me, which I constructed, this total length, about the quad, is ~12.5cm. However, here is a calculator I referenced in my constructions: It is a java application, you must have java on your computer. Let me know if you can't access it and I will give you the figures it spits out, 2.4ghz = 2400mhz. Just let me know what wifi channel you wish to center on (frequency.) Regards, JS |
#6
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John Smith wrote:
... However, here is a calculator I referenced in my constructions: It is a java application, you must have java on your computer. Let me know if you can't access it and I will give you the figures it spits out, 2.4ghz = 2400mhz. Just let me know what wifi channel you wish to center on (frequency.) Regards, JS Well, da! It would help if I cut loose with the URL. sheepish smile http://www.n6mrx.com/Antenna/Cubical-Quad1.htm Regards, JS |
#7
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http://www.n6mrx.com/Antenna/Cubical-Quad1.htm
Thanks for the link. The calculator works for me. One remaining Q: how do I take into account the "pigtails" of the driven element? A nice square loop is nice, but I've got to connect it to the (relatively) big diode, and this requires a bit more wire from the loop to the diode (on the + side of the loop) and to the meter connector (on the - side). Do I include these wire lengths in the loop size calculation? Or ignore them? Or does the 1000pF cap effectively terminate the loop (re. size)? Thanks. |
#8
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SparkyGuy wrote:
... Suggestions re. dimensions and location of a director? Thanks. Had company today, been in and out all day ... sorry I didn't offer more. A wavelength at 2.4Ghz will be approx. 12cm, half-wave ~6cm, 1/4 wave ~3cm. (with a very thin wire 1/2 wave monopole-omni-element I find ~12.25cm works for me, element dia. will affect this, as other factors ...) Anyway, I looked though my old emails for something a friend sent me, thought if you were interested in the 2.4g fsm, you might be interested in this, if nothing else, just because the dude is so complete!: http://www.users.bigpond.com/darren....enna_for_2.htm You will notice, he uses a plate reflector ... Regards, JS |
#9
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On Sun, 07 Dec 2008 21:40:38 -0800, John Smith
wrote: A wavelength at 2.4Ghz will be approx. 12cm, half-wave ~6cm, 1/4 wave ~3cm. (with a very thin wire 1/2 wave monopole-omni-element I find ~12.25cm works for me, element dia. will affect this, as other factors ...) Anyway, I looked though my old emails for something a friend sent me, thought if you were interested in the 2.4g fsm, you might be interested in this, if nothing else, just because the dude is so complete!: http://www.users.bigpond.com/darren....enna_for_2.htm You will notice, he uses a plate reflector ... Regards, JS I also noticed that he cut his elements to a precision of 0.1mm. That would be correct if the boom were an insulator or the elements were inserted in insulating sleeves. However, since the 10mm square boom is metal and effectively "shorts" part of each element, the actual element length includes part of the diameter of the boom, thus adding approximately 5mm to each element length (not including the reflector and driven element). A VSWR sweep test would have shown the problem. -- Jeff Liebermann 150 Felker St #D http://www.LearnByDestroying.com Santa Cruz CA 95060 http://802.11junk.com Skype: JeffLiebermann AE6KS 831-336-2558 |
#10
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Jeff Liebermann wrote:
... I also noticed that he cut his elements to a precision of 0.1mm. That would be correct if the boom were an insulator or the elements were inserted in insulating sleeves. However, since the 10mm square boom is metal and effectively "shorts" part of each element, the actual element length includes part of the diameter of the boom, thus adding approximately 5mm to each element length (not including the reflector and driven element). A VSWR sweep test would have shown the problem. I have always used #8 wire as a boom on ghz yagis' (constructed a 7 element once.) Since the boom is at a current antinode (voltage node), I ignored the boom. The boom you mention is rather LARGE, give the freqs in question. One of my next projects is a GOOD VSWR meter for ghz ... unfortuantly, on the list of priorities here, it is low on the list ... :-( I have just tended to take the % signal readings on the chans as good enough, and trimmed my antennas accordingly. I know, this does NOT take into account the functioning/power-fluctuations/antenna(s)/etc. of the AP over these ranges ... But, excellent point, glad you mentioned it ... but you are right, my elements end up being filed down a bit from the figures the calculator spits out ... Warm regards, JS |
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