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Kevin Aylward wrote:
gwhite wrote: The simple fact is you are wrong in thinking you can all of the sudden make up your own definition of linearity, or carry forward without challenge the mistaken definition of others. Absolute crap. Show me one respectable math reference that says if y=exp(x), that y is a linear function of x. You were right about one Show me one real practical example that does not use a device with a functional relation between input and output voltage/current that is linear, as I defined above. As did note as an after thought, it may be possible in principle, for example, maybe one could construct a true, linear with voltage, voltage controlled resistor. However, I am not aware of such magic devices. The physical reality is that it is not possible. Produce one and I will retract my claim. A light dependant resistor. One input drives a LED via a linearizer to compensate for LDR non-linearity. The LDR resistance is unaffected by the voltage across it. Therefore, the resulting current Io=f(V1,V2)= k.V1*V2 (4-quadrant multiplier or compensated gilbert cell) The circuit output is *superposition linear* relative to each input. dIo/dV1=k.V2, dIo/dV2=k.V1 (partial derivatives). In mixer operation, Io=f(Vin,Vosc). Vosc is an independant time-varying signal. Therefore, Io=f(Vin,Vosc(t)) or Io(t)=g(Vin,t). Because Io vs Vin is linear (4-quad multiplier), then dIo/dVin= g'(t) ie: a function of time only. This is the definition of a linear time-varying circuit. that is incorrect. You confuse the time-invariance property with the linearity property. You believe LTI systems are the *only* linear systems -- they are not according to the widely accepted and published definition of linearity. No. Linearity is widely understood to have many definitions. I have explained some of these already. An ideal multiplier is considered nonlinear with respect to a certain signal if a component of that signal is applied to *both* inputs simultaneously. Then: Io=k.(V1+a.V2)(a.V1+V2)= k.( aV1^2 + a.V2^2 + (1+a^2).V1.V2 ) |
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