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With all this discussion of phasing fun... could someone answer the
following question for me? Say I'm transmitting binaural audio, with I being L and Q being R. I receive this signal and generate my own I' and Q' outputs. However, if the RF carrier and my LO have a phase difference, the entire IQ (phasor) diagram is rotated by that difference and, e.g., a 90 degree difference will result in the left and right channels I receive being swapped. How do IQ-binaural receivers recover a phase lock to present this? If you do the quadrature detector thing with DSB-suppressed carrier, then when one of the two is just the wrong phase (and you get no output from that one), the other will be just the right phase, and vice-versa. When it's in between, does it work out right to just sum the two? I suppose so, though it's worth going through the math to make sure. I went through the math and you end up with the magnitude of the original signal. What's unclear to me is how to recover the phase offset between your signal and the original -- although adding a DC component (or some other unique frequency component) to either I or Q (or placed at some strategic angle between them) would allow you to synchronize the phases. Have any suggestions for a nice simple mixer (ala the NE602) that retains both the I and Q signals at the output? ---Joel Kolstad |
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