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#1
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"John Popelish" wrote in message
... Tfort wrote: On Mon, 02 Feb 2004 00:52:18 GMT, Uwe Langmesser wrote: I need a 12-14 V power supply for my new 2m tranceiver. ... Uwe look at this... http://www.rason.org/Projects/powsupply/powsupply.htm Tracy It can be easily improved. Eliminate the two .1 ohm emitter resistors and connect one emitter to R6 and one to R7. Good inputs, John. Yea. That is strange. Then replace R4 with a pair of resistors, one going to R6 and one to R7, to average the voltage from them to reproduce the current limit signal. I'd say this is ok. Don't know how important. Haven't done a 723 regulator in a long time... You will have to double the value so that two in parallel have the same total effect. This change will not only eliminate two 10 watt resistors, but will improve the current sharing between Q2 and Q3.... John Popelish Remember. Cap input filters like this draw high peak current at the peak of the sinewave when the caps get charged. It is not a sinewave current waveform. Make sure that you have enough filter cap (& diode capability) so that at the lowest point of the ripple on the filter caps you still have voltage on the series pass transistors (the 3055's) which is "enough" Here are some rough numbers, but should be close. To figure how much drop you'll have with given caps or how much cap you need to get a given drop you can use the formula I=C dV/dt where I is the DC current (in amps), dVis the drop (in volts) you have room for over dt which is about 7 miliseconds. Solve for C or V as appropriate. The minimum cap voltage is somethign like 13.8 PLUS the drop across the 0.15s PLUS 2 volts for the darlington connected 3055's base and some left over for collector voltage on the driver 3055. If I have it right that is: 13.8 + (7.5 x 0.15) + 2 (transistors 2 x Vbe) +2 (minimum driver Vcb) and this is at low line voltage. I get around 13.8 + 1.2 + 2 + 2 = 19V. Oh yea, the transformer has to have 2V more to allow for the bridge diodes also. SO at 30-35 peak amps the xfmr needs to have 21 volts peak, if I did it right -- that's around 15V RMS (there is flatening of the peaks due to the peak current). FYI: On one I built, I wound a few extra turns on the transformer and added some diodes to provide the driver collector voltage. This was a 5V 30A supply and I was trying to minimize loss. When TTL was in vogue... -- Steve N, K,9;d, c. i My email has no u's. |
#2
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Steve Nosko wrote:
(snip) FYI: On one I built, I wound a few extra turns on the transformer and added some diodes to provide the driver collector voltage. This was a 5V 30A supply and I was trying to minimize loss. When TTL was in vogue... That is a very good idea. You can do something like that very cheaply by just providing a small extra filter cap that is fed by two extra diodes, to make a positive supply that doesn't have the full ripple sag of the big caps. I would build the thing with a 15 or 16 volt transformer instead of the 18 volt one specified, unless you have lots of trouble with low line voltage. If you do use an 18 volt one, you can lower the peak currents and cool the transformer, capacitors and output transistors off by putting a big resistor in series with the transformer primary, such that at full load you just barely have enough DC to keep the regulator functioning. You still get the heat, but it is dumped into a resistor, instead of those other components. It also reduces the current thump when you turn the thing on and have to both charge the caps and handle transformer core saturation. I think you can also improve the load transient response by putting a 10 ohm resistor across the output transistors, base to emitter, and a 100 ohm resistor base to emitter on the driver transistor. I haven't calculated the closed loop frequency response of this design. -- John Popelish |
#4
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Uwe Langmesser wrote in message ...
Wonderful, I might learn something here. Here are some more details about the existing parts. I use an existing center tapped transformer which gives twice 10.7 V. I also have 4 caps of 167 000mF at 7.5 V (which are currently hooked up for 15V max voltage) and two fat diodes. The transformer is probably good for 25 to 30A ( it has a 3.5 X 4.5 X 6 inch core). If the 15 V I get right now at my filter stage is barely enough for decent regulation I could double that (and also use a bridge rectifier) but then I would have to regulate that higher voltage down to the 13.8V I will most often use. I looked at the design http://www.rason.org/Projects/powsupply/powsupply.htm that Tracy had suggested and it looks manageable to me (the Astron design someone suggested have additional windings on their transformers which I do not have on mine) but I do not have the expertise to change parts in the design to accommodate the higher voltage and current I could get out of my transformer. I am not sure if I only have to change the current limiting resisitor at the 723 as well as the resistors which determine the output voltage or if more elaborate changes involving the 2N3055's are necessary. This transformer is so close to the desired 13.8 volt output that I would be tempted to use it unregulated. But you might want ot hang a big 12 volt, 5 watt zener and a 10 ohm 2 watt resistor (in series) across it to provide a minimum load. It will have some ripple voltage, but it should do for most loads designed to operate from an automotive charging system (which also has considerable variation). If you want a regulated output, this transformer is not a very good fit, unless you go with a switching regulator. |
#5
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"John Popelish" wrote in message
... Steve Nosko wrote: (snip) FYI: On one I built, I wound a few extra turns on the transformer and added some diodes to provide the driver collector voltage. ... That is a very good idea. You can do something like that very cheaply by just providing a small extra filter cap that is fed by two extra diodes, to make a positive supply that doesn't have the full ripple sag of the big caps. FYI: It was a 28 V supply when I started. I re-wound the secondary, I think it was #10 wire, so a few extra turns of smaller wire (added to each end of the secondary, as I recall) was a treat at the end. ...lower the peak currents and cool the transformer, capacitors and output transistors off by putting a big resistor in series with the transformer primary, such that at full load you just barely have enough DC to keep the regulator functioning. You still get the heat, but it is dumped into a resistor, instead of those other components. This is interesting. I have to think about it. It'll slow the filter cap charge time and lower and spread out the peak current. T=RC and all that.... It also reduces the current thump I like that. I think you can also improve the load transient response by putting a 10 ohm resistor across the output transistors, base to emitter, and a 100 ohm resistor base to emitter on the driver transistor. I haven't calculated the closed loop frequency response of this design. John Popelish Yikes! Shades of my final year in control theory. I don't think I even bothered to look at this for the supply above. -- Steve N, K,9;d, c. i My email has no u's. |
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