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John Woodgate April 17th 04 05:26 PM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

John Woodgate April 17th 04 05:26 PM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

John Larkin April 17th 04 06:04 PM

On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote:

On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted
this:

John Larkin wrote:


Well, all the usual methods: resonance width, phase shift, ringdown,
stuff like that. I work with gadgets with Qs over 1e9, and people
measure them without difficulty.

John


Ringdown is the easist way when Qs are extremely high.


You must still account for the energy you extract from the circuit in
order to measure the ringdown. Even the energy needed to drive a high impedance
probe is significant when the Q gets high.

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Of course, you can account for the probe loss when you do the math. Or
leave the probe disconnected during a ringdown, and add it after some
delay to see how much energy is left in the system.

John


John Larkin April 17th 04 06:04 PM

On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote:

On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted
this:

John Larkin wrote:


Well, all the usual methods: resonance width, phase shift, ringdown,
stuff like that. I work with gadgets with Qs over 1e9, and people
measure them without difficulty.

John


Ringdown is the easist way when Qs are extremely high.


You must still account for the energy you extract from the circuit in
order to measure the ringdown. Even the energy needed to drive a high impedance
probe is significant when the Q gets high.

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Of course, you can account for the probe loss when you do the math. Or
leave the probe disconnected during a ringdown, and add it after some
delay to see how much energy is left in the system.

John


Tom Bruhns April 17th 04 06:09 PM

Robert Baer wrote in message ...
....
Yes, but the emphasis was on small size, and a helical resonator
allows a goodly shrinkage of volume wihout a corresponding loss large of
Q.


As compared with what? A given coil in a helical resonator will
result in lower Qu than that same coil unshielded and simply resonated
with a good capacitor.


....
Maybe his requirements are not too realistic?


Seems to commonly be the case.

Tom Bruhns April 17th 04 06:09 PM

Robert Baer wrote in message ...
....
Yes, but the emphasis was on small size, and a helical resonator
allows a goodly shrinkage of volume wihout a corresponding loss large of
Q.


As compared with what? A given coil in a helical resonator will
result in lower Qu than that same coil unshielded and simply resonated
with a good capacitor.


....
Maybe his requirements are not too realistic?


Seems to commonly be the case.

James Meyer April 17th 04 08:05 PM

On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

Jim


James Meyer April 17th 04 08:05 PM

On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

Jim


James Meyer April 17th 04 08:07 PM

On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this:

On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote:

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Of course, you can account for the probe loss when you do the math. Or
leave the probe disconnected during a ringdown, and add it after some
delay to see how much energy is left in the system.

John


If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


James Meyer April 17th 04 08:07 PM

On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this:

On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote:

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Of course, you can account for the probe loss when you do the math. Or
leave the probe disconnected during a ringdown, and add it after some
delay to see how much energy is left in the system.

John


If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


James Meyer April 17th 04 08:11 PM

On 17 Apr 2004 10:09:22 -0700, (Tom Bruhns) posted this:

Robert Baer wrote in message ...
...
Yes, but the emphasis was on small size, and a helical resonator
allows a goodly shrinkage of volume wihout a corresponding loss large of
Q.


As compared with what? A given coil in a helical resonator will
result in lower Qu than that same coil unshielded and simply resonated
with a good capacitor.


Not so. And others have pointed that out. If you take an unshielded
coil to it's ultimate configuration you are confronted with a resonant antenna
that is loaded by its radiation resistance and that results in a *lower* Q than
a properly shielded resonator.

Jim



James Meyer April 17th 04 08:11 PM

On 17 Apr 2004 10:09:22 -0700, (Tom Bruhns) posted this:

Robert Baer wrote in message ...
...
Yes, but the emphasis was on small size, and a helical resonator
allows a goodly shrinkage of volume wihout a corresponding loss large of
Q.


As compared with what? A given coil in a helical resonator will
result in lower Qu than that same coil unshielded and simply resonated
with a good capacitor.


Not so. And others have pointed that out. If you take an unshielded
coil to it's ultimate configuration you are confronted with a resonant antenna
that is loaded by its radiation resistance and that results in a *lower* Q than
a properly shielded resonator.

Jim



John Larkin April 17th 04 08:21 PM

On Sat, 17 Apr 2004 19:07:12 GMT, James Meyer
wrote:

On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this:

On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote:

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Of course, you can account for the probe loss when you do the math. Or
leave the probe disconnected during a ringdown, and add it after some
delay to see how much energy is left in the system.

John


If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim



How can you calculate Q from first principles? 3D EM simulation?
Quantum mechanics?

John


John Larkin April 17th 04 08:21 PM

On Sat, 17 Apr 2004 19:07:12 GMT, James Meyer
wrote:

On Sat, 17 Apr 2004 10:04:36 -0700, John Larkin
posted this:

On Sat, 17 Apr 2004 15:46:59 GMT, James Meyer
wrote:

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Of course, you can account for the probe loss when you do the math. Or
leave the probe disconnected during a ringdown, and add it after some
delay to see how much energy is left in the system.

John


If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim



How can you calculate Q from first principles? 3D EM simulation?
Quantum mechanics?

John


Roy Lewallen April 17th 04 08:22 PM

Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of
current around the conductors)? What reference, equation, or program do
you use? Nearly all "first principle" calculations of Q I've seen
grossly overestimate Q, and I believe the failure to take this into
account is at least part of the reason. I haven't seen a decent
analytical method of dealing with it, and an anxious to see how you do it.

Then there's surface corrosion and roughness, radiation, and coupling to
nearby objects. How do you deal with those? Have you identified some of
the other factors that often make a simplistic "first principle"
calculation disagree so badly with carefully made measurements?

Roy Lewallen, W7EL

James Meyer wrote:

If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


Roy Lewallen April 17th 04 08:22 PM

Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of
current around the conductors)? What reference, equation, or program do
you use? Nearly all "first principle" calculations of Q I've seen
grossly overestimate Q, and I believe the failure to take this into
account is at least part of the reason. I haven't seen a decent
analytical method of dealing with it, and an anxious to see how you do it.

Then there's surface corrosion and roughness, radiation, and coupling to
nearby objects. How do you deal with those? Have you identified some of
the other factors that often make a simplistic "first principle"
calculation disagree so badly with carefully made measurements?

Roy Lewallen, W7EL

James Meyer wrote:

If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


John Woodgate April 17th 04 09:05 PM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

IIRC, the Marconi unit used a 10 nH inductor (maybe less) made of a
short length of silver wire, gold-plated to eliminate sulfide attack.
The effect on Q would be minimal in the extreme.
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

John Woodgate April 17th 04 09:05 PM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

IIRC, the Marconi unit used a 10 nH inductor (maybe less) made of a
short length of silver wire, gold-plated to eliminate sulfide attack.
The effect on Q would be minimal in the extreme.
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

Barry Lennox April 17th 04 10:06 PM

On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
wrote:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


I can recall using one of those, some little time back. Anybody have
the schematic diagram for it?

Barry Lennox

Barry Lennox April 17th 04 10:06 PM

On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
wrote:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.


Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


I can recall using one of those, some little time back. Anybody have
the schematic diagram for it?

Barry Lennox

James Meyer April 18th 04 12:48 AM

On Sat, 17 Apr 2004 12:22:03 -0700, Roy Lewallen posted this:

Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of
current around the conductors)? What reference, equation, or program do
you use? Nearly all "first principle" calculations of Q I've seen
grossly overestimate Q, and I believe the failure to take this into
account is at least part of the reason. I haven't seen a decent
analytical method of dealing with it, and an anxious to see how you do it.

Then there's surface corrosion and roughness, radiation, and coupling to
nearby objects. How do you deal with those? Have you identified some of
the other factors that often make a simplistic "first principle"
calculation disagree so badly with carefully made measurements?

Roy Lewallen, W7EL

James Meyer wrote:

If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


I was responding to a suggestion that one could do the math to calculate
what the Q would have been if you hadn't tried to measure it. I was pointing
out that if you could do that math, and get it correct, that you could do the
whole exercise with math and forget measuring anything.

And how do you know for sure that calculations overestimate Q when
measuring Q to verify the calculations disturbs the very thing you're measuring?

An engineer knows when to say "close enough". A mathematician is never
satisfied.

Jim


James Meyer April 18th 04 12:48 AM

On Sat, 17 Apr 2004 12:22:03 -0700, Roy Lewallen posted this:

Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of
current around the conductors)? What reference, equation, or program do
you use? Nearly all "first principle" calculations of Q I've seen
grossly overestimate Q, and I believe the failure to take this into
account is at least part of the reason. I haven't seen a decent
analytical method of dealing with it, and an anxious to see how you do it.

Then there's surface corrosion and roughness, radiation, and coupling to
nearby objects. How do you deal with those? Have you identified some of
the other factors that often make a simplistic "first principle"
calculation disagree so badly with carefully made measurements?

Roy Lewallen, W7EL

James Meyer wrote:

If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


I was responding to a suggestion that one could do the math to calculate
what the Q would have been if you hadn't tried to measure it. I was pointing
out that if you could do that math, and get it correct, that you could do the
whole exercise with math and forget measuring anything.

And how do you know for sure that calculations overestimate Q when
measuring Q to verify the calculations disturbs the very thing you're measuring?

An engineer knows when to say "close enough". A mathematician is never
satisfied.

Jim


James Meyer April 18th 04 12:53 AM

On Sat, 17 Apr 2004 21:05:34 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

IIRC, the Marconi unit used a 10 nH inductor (maybe less) made of a
short length of silver wire, gold-plated to eliminate sulfide attack.
The effect on Q would be minimal in the extreme.


But what about the energy extracted from the probe to make the
measurement? Any load on the probe is transformed into a load on the resonator.
Compensating for that load requires a very small number be divided by another
very small number. Any error in either number makes a much larger error in the
result of the calculation.

Jim


James Meyer April 18th 04 12:53 AM

On Sat, 17 Apr 2004 21:05:34 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).


Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

IIRC, the Marconi unit used a 10 nH inductor (maybe less) made of a
short length of silver wire, gold-plated to eliminate sulfide attack.
The effect on Q would be minimal in the extreme.


But what about the energy extracted from the probe to make the
measurement? Any load on the probe is transformed into a load on the resonator.
Compensating for that load requires a very small number be divided by another
very small number. Any error in either number makes a much larger error in the
result of the calculation.

Jim


Roy Lewallen April 18th 04 02:56 AM

James Meyer wrote:
. . .
And how do you know for sure that calculations overestimate Q when
measuring Q to verify the calculations disturbs the very thing you're measuring?

An engineer knows when to say "close enough". A mathematician is never
satisfied.


I've measured quite a number of inductors both with a homebrew setup, in
which I account for the losses in the input and output networks, and
with an HP Q meter of specified accuracy. With simple input and output
networks consisting of a small series C and shunt R, the effect on Q is
predictable and easy to calculate. Results from the two methods agree
quite closely, even though they use somewhat different methods to arrive
at the Q, giving a fair amount of confidence in both results. And both
disagree quite dramatically in some cases to Q calculated simply from
theoretical calculations which include only conductor resistance
(including skin effect, of course), inductance, and shunt capacitance.
This is with inductors of only moderate Q -- calculation of very high Q
inductors, which is being discussed here, would require more attention
to second order effects -- as would measurement.

Thanks for the profound observation about mathematicians and engineers.
In which category does one put a person who's satisfied with
calculations made without thinking about, caring about, or considering
the errors caused by ignoring fundamental effects? Certainly not an
engineer as I use the term.

Roy Lewallen, W7EL

Roy Lewallen April 18th 04 02:56 AM

James Meyer wrote:
. . .
And how do you know for sure that calculations overestimate Q when
measuring Q to verify the calculations disturbs the very thing you're measuring?

An engineer knows when to say "close enough". A mathematician is never
satisfied.


I've measured quite a number of inductors both with a homebrew setup, in
which I account for the losses in the input and output networks, and
with an HP Q meter of specified accuracy. With simple input and output
networks consisting of a small series C and shunt R, the effect on Q is
predictable and easy to calculate. Results from the two methods agree
quite closely, even though they use somewhat different methods to arrive
at the Q, giving a fair amount of confidence in both results. And both
disagree quite dramatically in some cases to Q calculated simply from
theoretical calculations which include only conductor resistance
(including skin effect, of course), inductance, and shunt capacitance.
This is with inductors of only moderate Q -- calculation of very high Q
inductors, which is being discussed here, would require more attention
to second order effects -- as would measurement.

Thanks for the profound observation about mathematicians and engineers.
In which category does one put a person who's satisfied with
calculations made without thinking about, caring about, or considering
the errors caused by ignoring fundamental effects? Certainly not an
engineer as I use the term.

Roy Lewallen, W7EL

John Woodgate April 18th 04 09:50 AM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 21:05:34 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you

insert
the probe to measure the Q.

Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).

Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

IIRC, the Marconi unit used a 10 nH inductor (maybe less) made of a
short length of silver wire, gold-plated to eliminate sulfide attack.
The effect on Q would be minimal in the extreme.


But what about the energy extracted from the probe to make the
measurement?


The sensing inductor was connected to the grid of a triode tube, with,
IIRC, a 1 Mohm grid leak. With 1 mV across the sensor, that's a whole
1 uJ/s of energy extraction.

Any load on the probe is transformed into a load on the resonator.
Compensating for that load requires a very small number be divided by another
very small number. Any error in either number makes a much larger error in the
result of the calculation.

Check your math. It's small errors in *differences*, not in ratios, that
result in large errors in results.
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

John Woodgate April 18th 04 09:50 AM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 21:05:34 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
On Sat, 17 Apr 2004 17:26:15 +0100, John Woodgate
posted this:

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sat, 17 Apr 2004:
IOW, the Q without the probe will be higher than the Q when you

insert
the probe to measure the Q.

Use an inductive current pick-off. That how the Marconi Instruments 1245
series Q-meters work(ed).

Nevertheless, *ANY* method used to probe the field associated with the
resonator will load the resonator and degrade the Q.

IIRC, the Marconi unit used a 10 nH inductor (maybe less) made of a
short length of silver wire, gold-plated to eliminate sulfide attack.
The effect on Q would be minimal in the extreme.


But what about the energy extracted from the probe to make the
measurement?


The sensing inductor was connected to the grid of a triode tube, with,
IIRC, a 1 Mohm grid leak. With 1 mV across the sensor, that's a whole
1 uJ/s of energy extraction.

Any load on the probe is transformed into a load on the resonator.
Compensating for that load requires a very small number be divided by another
very small number. Any error in either number makes a much larger error in the
result of the calculation.

Check your math. It's small errors in *differences*, not in ratios, that
result in large errors in results.
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

Robert Baer April 18th 04 10:53 AM

James Meyer wrote:

On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted
this:

John Larkin wrote:


Well, all the usual methods: resonance width, phase shift, ringdown,
stuff like that. I work with gadgets with Qs over 1e9, and people
measure them without difficulty.

John


Ringdown is the easist way when Qs are extremely high.


You must still account for the energy you extract from the circuit in
order to measure the ringdown. Even the energy needed to drive a high impedance
probe is significant when the Q gets high.

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Not a problem; use two different loads.
Just like measuring the internal resistance of a battery or a curent
meter...
...Never done directly.

Robert Baer April 18th 04 10:53 AM

James Meyer wrote:

On Sat, 17 Apr 2004 07:43:49 GMT, Robert Baer posted
this:

John Larkin wrote:


Well, all the usual methods: resonance width, phase shift, ringdown,
stuff like that. I work with gadgets with Qs over 1e9, and people
measure them without difficulty.

John


Ringdown is the easist way when Qs are extremely high.


You must still account for the energy you extract from the circuit in
order to measure the ringdown. Even the energy needed to drive a high impedance
probe is significant when the Q gets high.

IOW, the Q without the probe will be higher than the Q when you insert
the probe to measure the Q.

Jim


Not a problem; use two different loads.
Just like measuring the internal resistance of a battery or a curent
meter...
...Never done directly.

Tom Bruhns April 18th 04 12:35 PM

James Meyer wrote in message . ..
On 17 Apr 2004 10:09:22 -0700, (Tom Bruhns) posted this:

Robert Baer wrote in message ...
...
Yes, but the emphasis was on small size, and a helical resonator
allows a goodly shrinkage of volume wihout a corresponding loss large of
Q.


As compared with what? A given coil in a helical resonator will
result in lower Qu than that same coil unshielded and simply resonated
with a good capacitor.


Not so. And others have pointed that out. If you take an unshielded
coil to it's ultimate configuration you are confronted with a resonant antenna
that is loaded by its radiation resistance and that results in a *lower* Q than
a properly shielded resonator.


ONLY if it's really big. See Reg's posting in this thread on that
subject. We're talking about making things small here, like smaller
than a 1 inch diameter coil at 18MHz. The cavity for a standard
helical resonator design will ding the Q by 15% or more; for such a
small unshielded coil do you expect that much radiation? I don't.
Not even close.

Cheers,
Tom

Tom Bruhns April 18th 04 12:35 PM

James Meyer wrote in message . ..
On 17 Apr 2004 10:09:22 -0700, (Tom Bruhns) posted this:

Robert Baer wrote in message ...
...
Yes, but the emphasis was on small size, and a helical resonator
allows a goodly shrinkage of volume wihout a corresponding loss large of
Q.


As compared with what? A given coil in a helical resonator will
result in lower Qu than that same coil unshielded and simply resonated
with a good capacitor.


Not so. And others have pointed that out. If you take an unshielded
coil to it's ultimate configuration you are confronted with a resonant antenna
that is loaded by its radiation resistance and that results in a *lower* Q than
a properly shielded resonator.


ONLY if it's really big. See Reg's posting in this thread on that
subject. We're talking about making things small here, like smaller
than a 1 inch diameter coil at 18MHz. The cavity for a standard
helical resonator design will ding the Q by 15% or more; for such a
small unshielded coil do you expect that much radiation? I don't.
Not even close.

Cheers,
Tom

James Meyer April 18th 04 02:36 PM

On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this:


Thanks for the profound observation about mathematicians and engineers.
In which category does one put a person who's satisfied with
calculations made without thinking about, caring about, or considering
the errors caused by ignoring fundamental effects? Certainly not an
engineer as I use the term.

Roy Lewallen, W7EL


Such a person as you describe is commonly known as a physicist. I have
had to work with several. That some of them are still alive is a testament to
my degree of self control.

Jim



James Meyer April 18th 04 02:36 PM

On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this:


Thanks for the profound observation about mathematicians and engineers.
In which category does one put a person who's satisfied with
calculations made without thinking about, caring about, or considering
the errors caused by ignoring fundamental effects? Certainly not an
engineer as I use the term.

Roy Lewallen, W7EL


Such a person as you describe is commonly known as a physicist. I have
had to work with several. That some of them are still alive is a testament to
my degree of self control.

Jim



John Woodgate April 18th 04 04:08 PM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sun, 18 Apr 2004:
On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this:


Thanks for the profound observation about mathematicians and engineers.
In which category does one put a person who's satisfied with
calculations made without thinking about, caring about, or considering
the errors caused by ignoring fundamental effects? Certainly not an
engineer as I use the term.

Roy Lewallen, W7EL


Such a person as you describe is commonly known as a physicist. I have
had to work with several. That some of them are still alive is a testament to
my degree of self control.

LOL! But physicists are usually *preoccupied* with fundamental effects
and tend to ignore others.

In my brief skirmish with aeronautical engineering, I formed the opinion
that most of the calculations were as pragmatic as RL suggests; the only
consolation is that they seem to work.
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

John Woodgate April 18th 04 04:08 PM

I read in sci.electronics.design that James Meyer
wrote (in ) about 'A neat
and compact way to generate RF harmonics...', on Sun, 18 Apr 2004:
On Sat, 17 Apr 2004 18:56:14 -0700, Roy Lewallen posted this:


Thanks for the profound observation about mathematicians and engineers.
In which category does one put a person who's satisfied with
calculations made without thinking about, caring about, or considering
the errors caused by ignoring fundamental effects? Certainly not an
engineer as I use the term.

Roy Lewallen, W7EL


Such a person as you describe is commonly known as a physicist. I have
had to work with several. That some of them are still alive is a testament to
my degree of self control.

LOL! But physicists are usually *preoccupied* with fundamental effects
and tend to ignore others.

In my brief skirmish with aeronautical engineering, I formed the opinion
that most of the calculations were as pragmatic as RL suggests; the only
consolation is that they seem to work.
--
Regards, John Woodgate, OOO - Own Opinions Only.
The good news is that nothing is compulsory.
The bad news is that everything is prohibited.
http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk

John Larkin April 18th 04 05:32 PM

On Sat, 17 Apr 2004 23:48:01 GMT, James Meyer
wrote:

On Sat, 17 Apr 2004 12:22:03 -0700, Roy Lewallen posted this:

Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of
current around the conductors)? What reference, equation, or program do
you use? Nearly all "first principle" calculations of Q I've seen
grossly overestimate Q, and I believe the failure to take this into
account is at least part of the reason. I haven't seen a decent
analytical method of dealing with it, and an anxious to see how you do it.

Then there's surface corrosion and roughness, radiation, and coupling to
nearby objects. How do you deal with those? Have you identified some of
the other factors that often make a simplistic "first principle"
calculation disagree so badly with carefully made measurements?

Roy Lewallen, W7EL

James Meyer wrote:

If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


I was responding to a suggestion that one could do the math to calculate
what the Q would have been if you hadn't tried to measure it. I was pointing
out that if you could do that math, and get it correct, that you could do the
whole exercise with math and forget measuring anything.


The math in question is trivial. Qs from 1 to 1e9 can be measured
accurately without difficulty.


An engineer knows when to say "close enough". A mathematician is never
satisfied.


But then, mathematicians don't measure things, do they?

John



John Larkin April 18th 04 05:32 PM

On Sat, 17 Apr 2004 23:48:01 GMT, James Meyer
wrote:

On Sat, 17 Apr 2004 12:22:03 -0700, Roy Lewallen posted this:

Ah, just the person I've been waiting for. How do you account for
current bunching on the conductors (that is, non-uniform distribution of
current around the conductors)? What reference, equation, or program do
you use? Nearly all "first principle" calculations of Q I've seen
grossly overestimate Q, and I believe the failure to take this into
account is at least part of the reason. I haven't seen a decent
analytical method of dealing with it, and an anxious to see how you do it.

Then there's surface corrosion and roughness, radiation, and coupling to
nearby objects. How do you deal with those? Have you identified some of
the other factors that often make a simplistic "first principle"
calculation disagree so badly with carefully made measurements?

Roy Lewallen, W7EL

James Meyer wrote:

If you have to "do the math", you might as well just calculate the Q
from first principles and forget the "measurement".

Jim


I was responding to a suggestion that one could do the math to calculate
what the Q would have been if you hadn't tried to measure it. I was pointing
out that if you could do that math, and get it correct, that you could do the
whole exercise with math and forget measuring anything.


The math in question is trivial. Qs from 1 to 1e9 can be measured
accurately without difficulty.


An engineer knows when to say "close enough". A mathematician is never
satisfied.


But then, mathematicians don't measure things, do they?

John



Don Young July 6th 04 08:54 AM

John,
Are you saying you have some SRDs available?
I could use a couple in a GPR I'm working on.
Part of the Sample pulse generator.
Don

John Larkin wrote:

On Mon, 12 Apr 2004 19:09:51 GMT, "Harold E. Johnson"
wrote:


If you do use diodes for higher-order harmonic generation, and not
just a simple full-wave-rectifier type frequency doubler, I suppose
you want something of the nature of a step recovery diode. That
implies minority carrier stored charge in the diode, and that would
preclude using a Schottky diode (which would work great in the
full-wave-rectifier type doubler). If you get into actually wanting
to generate harmonic combs out to microwave frequencies, it's probably
worthwhile looking for diodes actually characterized for step recovery
service. But I really think that's way beyond what you are trying to
accomplish right now.

My turn to learn something here. Tom, would you elaborate a bit on the above
please? I know SRD's are comb generators out to visible light, but they're
also 50 percent hard to find and 50 percent magic. I've been using
Schottky's for X16 multipliers to 2 GHz, am I doing something wrong? (I keep
promising myself that I'm gonna substitute an MMIC for that one day, I DID
find the "Filter Gain" in the line length from generator to filter), THAT
was both impressive AND helpful. If I go with the MMIC, any preference of
Silicon over GaAs?

Regards

W4ZCB



The only distributor-stock SRDs I know of are the M/Acom MA44767,
MA44768, MA44769 parts, all SOT-23 and dirt cheap. I think Penstock
carries them. The '68 or '69 should be good for multiplication to 2
GHz. For high ratios, an SRD will beat a plain diode by a huge amount.
There are lots of appnotes around about using them as multipliers.

I have a bunch in stock and can send a few to anybody who wants to
play.

John




--
My web pages ....................VVVVVVVV.................
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