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On Mon, 11 Oct 2004 23:54:00 GMT, "Joe Rocci" wrote:
Steve, If the inductor was not there to hold the zero-crossings of the input sine wave at zero volts, then the whole waveform would sink toward a lower DC voltage because it is capacitively coupled. You can prove this to yourself by taking a large capacitor and driving a diode that is connected to ground. The test can easily be done with audio frequencies if you don't have RF equipment. You could also simulate it on a program like SPICE. If the choke were removed from the circuit, this input DC shift would reverse bias the BE junction, preventing the abiltiy of the waveform to drive current into the BE junction. No base current = no collector current = no gain. BTW, I was almost sure your original post said this was a multiplier circuit. Did the word "multiplier" not appear in it anywhere? Hmmm... Thanks for the explanation, Joe, but no. I never said anythink about multiplicaiton. steve -- Fat, sugar, salt, beer: the four essentials for a healthy diet. |