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#1
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#2
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![]() There was NO company named "Motorola" until 1947. Until then, "Motorola" was just the model name for car radios...No company... So...how did "Motorola" do anything for Army communications in 1940...?!?! Must have been the Galvin(sp) company, the ancestor of Motorola. |
#3
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![]() robert casey wrote: There was NO company named "Motorola" until 1947. Until then, "Motorola" was just the model name for car radios...No company... So...how did "Motorola" do anything for Army communications in 1940...?!?! Must have been the Galvin(sp) company, the ancestor of Motorola. Absolutely correct, Mr Casey. From: http://www.hitechwireless.cc/html/history.html To wit: The company was founded by Paul V. Galvin as the Galvin Manufacturing Corporation, in Chicago, Illinois, in 1928. Its first product was a "battery eliminator," allowing consumers to operate radios directly from household current instead of the batteries supplied with early models. In the 1930s, the company successfully commercialized car radios under the brand name "Motorola," a word suggesting sound in motion. During this period, the company also established home radio and police radio departments; instituted pioneering personnel programs; and began national advertising. The name of the company was changed to Motorola, Inc., in 1947. UNQUOTE 73 Steve, K4YZ |
#4
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![]() "K4YZ" wrote in message oups.com... robert casey wrote: There was NO company named "Motorola" until 1947. Until then, "Motorola" was just the model name for car radios...No company... So...how did "Motorola" do anything for Army communications in 1940...?!?! Must have been the Galvin(sp) company, the ancestor of Motorola. Absolutely correct, Mr Casey. From: http://www.hitechwireless.cc/html/history.html To wit: The company was founded by Paul V. Galvin as the Galvin Manufacturing Corporation, in Chicago, Illinois, in 1928. Its first product was a "battery eliminator," allowing consumers to operate radios directly from household current instead of the batteries supplied with early models. In the 1930s, the company successfully commercialized car radios under the brand name "Motorola," a word suggesting sound in motion. During this period, the company also established home radio and police radio departments; instituted pioneering personnel programs; and began national advertising. The name of the company was changed to Motorola, Inc., in 1947. UNQUOTE 73 Steve, K4YZ Steve, Please don't mention 1947. I just had a birthday last month and I am feeling *very* antiquated LOL. I have been unable to learn new concepts, such as measuring your antenna impedance with a volt-ohm meter. I still cannot understand the concept of a class A amplifier being 50% efficient (taught by the U.S. Navy in 1967). I had a problem even as a youngster when a teacher told me that there was a complex formula for finding resonant frequency, but L times C was close enough. I was 14 at the time and already apparently suffering the beginning of Altzheimer's. I admit to having some problems with The Calculus but managed some months ago to borrow a book and get back a bit of what I had forgotten. Unbelieveably, The Calculus appears to work, but how can it when my algebra is so poor that I am unable to transform F=L*C into F=1/(6.28*sqr(L*C))? I can only assume that I have memorized many things in error. I don't generally use calculators like many do to make change (I caught an error one time a kid did use a calculator), so I suspect my basic addition, subraction, multiplication, and division have not disappeared. Obviously, however, my idea of equations must be in error. Many folks state that pi is equal to 3. Well, that still doesn't work for resonant frequency = L times C. So, in any case, Steve, welcome to the club. You are likely as brain dead as I. 73 from Rochester, NY Jim AA2QA ps - try to avoid these kind of threads LOL |
#5
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![]() Jim Hampton wrote: "K4YZ" wrote in message oups.com... robert casey wrote: There was NO company named "Motorola" until 1947. Until then, "Motorola" was just the model name for car radios...No company... So...how did "Motorola" do anything for Army communications in 1940...?!?! Must have been the Galvin(sp) company, the ancestor of Motorola. Absolutely correct, Mr Casey. From: http://www.hitechwireless.cc/html/history.html To wit: The company was founded by Paul V. Galvin as the Galvin Manufacturing Corporation, in Chicago, Illinois, in 1928. Its first product was a "battery eliminator," allowing consumers to operate radios directly from household current instead of the batteries supplied with early models. In the 1930s, the company successfully commercialized car radios under the brand name "Motorola," a word suggesting sound in motion. During this period, the company also established home radio and police radio departments; instituted pioneering personnel programs; and began national advertising. The name of the company was changed to Motorola, Inc., in 1947. UNQUOTE 73 Steve, K4YZ Steve, Please don't mention 1947. I just had a birthday last month and I am feeling *very* antiquated LOL. I have been unable to learn new concepts, such as measuring your antenna impedance with a volt-ohm meter. I still cannot understand the concept of a class A amplifier being 50% efficient (taught by the U.S. Navy in 1967). I had a problem even as a youngster when a teacher told me that there was a complex formula for finding resonant frequency, but L times C was close enough. I was 14 at the time and already apparently suffering the beginning of Altzheimer's. I admit to having some problems with The Calculus but managed some months ago to borrow a book and get back a bit of what I had forgotten. Unbelieveably, The Calculus appears to work, but how can it when my algebra is so poor that I am unable to transform F=L*C into F=1/(6.28*sqr(L*C))? I can only assume that I have memorized many things in error. I don't generally use calculators like many do to make change (I caught an error one time a kid did use a calculator), so I suspect my basic addition, subraction, multiplication, and division have not disappeared. Obviously, however, my idea of equations must be in error. Many folks state that pi is equal to 3. Well, that still doesn't work for resonant frequency = L times C. So, in any case, Steve, welcome to the club. You are likely as brain dead as I. 73 from Rochester, NY Jim AA2QA ps - try to avoid these kind of threads LOL At this point, an honorable person would not only admit that they were wrong, but would apologize to the person they were claiming was wrong, ---and--- apologize to that person for starting yet another slam thread. Let's see what Steve does. |
#6
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![]() bb wrote: Jim Hampton wrote: "K4YZ" wrote in message oups.com... robert casey wrote: There was NO company named "Motorola" until 1947. Until then, "Motorola" was just the model name for car radios...No company... So...how did "Motorola" do anything for Army communications in 1940...?!?! Must have been the Galvin(sp) company, the ancestor of Motorola. Absolutely correct, Mr Casey. From: http://www.hitechwireless.cc/html/history.html To wit: The company was founded by Paul V. Galvin as the Galvin Manufacturing Corporation, in Chicago, Illinois, in 1928. Its first product was a "battery eliminator," allowing consumers to operate radios directly from household current instead of the batteries supplied with early models. In the 1930s, the company successfully commercialized car radios under the brand name "Motorola," a word suggesting sound in motion. During this period, the company also established home radio and police radio departments; instituted pioneering personnel programs; and began national advertising. The name of the company was changed to Motorola, Inc., in 1947. UNQUOTE 73 Steve, K4YZ Steve, Please don't mention 1947. I just had a birthday last month and I am feeling *very* antiquated LOL. I have been unable to learn new concepts, such as measuring your antenna impedance with a volt-ohm meter. I still cannot understand the concept of a class A amplifier being 50% efficient (taught by the U.S. Navy in 1967). I had a problem even as a youngster when a teacher told me that there was a complex formula for finding resonant frequency, but L times C was close enough. I was 14 at the time and already apparently suffering the beginning of Altzheimer's. I admit to having some problems with The Calculus but managed some months ago to borrow a book and get back a bit of what I had forgotten. Unbelieveably, The Calculus appears to work, but how can it when my algebra is so poor that I am unable to transform F=L*C into F=1/(6.28*sqr(L*C))? I can only assume that I have memorized many things in error. I don't generally use calculators like many do to make change (I caught an error one time a kid did use a calculator), so I suspect my basic addition, subraction, multiplication, and division have not disappeared. Obviously, however, my idea of equations must be in error. Many folks state that pi is equal to 3. Well, that still doesn't work for resonant frequency = L times C. So, in any case, Steve, welcome to the club. You are likely as brain dead as I. 73 from Rochester, NY Jim AA2QA ps - try to avoid these kind of threads LOL At this point, an honorable person would not only admit that they were wrong, but would apologize to the person they were claiming was wrong, ---and--- apologize to that person for starting yet another slam thread. Let's see what Steve does. Apologize for what, Brain...?!?! Motorola was NOT a company in 1940. THAT is a fact. References provided. Lennie was WRONG. Let's see what LENNIE does, other than provide yet another verbose spindance to hide behind his error... OOOOOOOOOOOOOOOOOOOPS! TOO LATE! He already did that! It was no "slam thread". Lennie got his ego in front of his common sense again...Wasn't paying attention. But he CLAIMS to be a "professional". Obviously THIS professional got his "facts" wrong. I just showed him his error. Steve, K4YZ |
#7
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![]() Unbelieveably, The Calculus appears to work, but how can it when my algebra is so poor that I am unable to transform F=L*C into F=1/(6.28*sqr(L*C))? I enjoyed calculus so much I took it twice. :-) Now if you actually learned enough to actually *USE* calculus to solve something, you're one leg up on me.... :-) |
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