Home |
Search |
Today's Posts |
#10
![]() |
|||
|
|||
![]()
On Mon, 27 Nov 2006 06:02:29 GMT, Telamon
wrote: In article , "Robert11" wrote: To make the measure simple you can set both generators to 0 dB and then make a measurement of the appropriate mixing products for either IP2 or IP3. Lets say the IP2 was -66 on the difference and -68 on the plus. The IP2 would then be 66 dB, which is the worst of the two. Lets say 2 times generator 1 frequency plus the generator 2 frequency product had the highest level of -75 dB of the IP3 possibilities. The the IP3 would be 75 dB. Wrong. IP3 is a theoretical point in space above a graph. What you have described is the ratio of a single unwanted product to a desired signal. |