Is CW a digital mode?
 

Take the Hamwave poll...
www.hamwave.com

In article ,
says...
Take the Hamwave poll...
www.hamwave.com

__________________________________________________ _________

No need for a poll. CW is a binary mode, but not digital.

--
Bill, W6WRT

From URL: http://www.webopedia.com/TERM/d/digital.html

DIGITAL: Describes any system based on discontinuous data or events.

I leave it to you for interpretation

--
Support Ham Radio - Only Game in Town



"Bill Turner" wrote in message
. ..
In article ,
says...
Take the Hamwave poll...
www.hamwave.com

__________________________________________________ _________

No need for a poll. CW is a binary mode, but not digital.

--
Bill, W6WRT

Bill Turner wrote:
In article ,
says...

Take the Hamwave poll...
www.hamwave.com


__________________________________________________ _________

No need for a poll. CW is a binary mode, but not digital.


Say, isn't binary base 2 digital?

In article 6ODyd.478$Q%4.350@fed1read06, says...
DIGITAL: Describes any system based on discontinuous data or events.

__________________________________________________ _________

Nonsense. "Digital" refers to a system where data is represented by
numbers, I.e., digits.

Is the light switch on the wall "digital"? According to your
definition, it is. While it is binary, having two states, the states do
not represent numbers. It's purely analog.

--
Bill, W6WRT

In article ,
says...

Say, isn't binary base 2 digital?
__________________________________________________ _________

Binary arithmetic is base 2 digital, but not everything binary is
arithmetic. You've probably heard of binary nerve gas. Is that
digital? The word "binary" just means having two possible states.
Those two states may or may not represent numeric values.

Not everything binary is digital and not everything digital is binary.

--
Bill, W6WRT

Bill Turner ) writes:

In Baudot, like OOK, bit length is critical. Think about it.



But consider that in OOK Morse, the characters for example are
A 10111000
B 111010101000
C 11101011101000

In each case, the last 3 zeroes (or should it be 5 zeroes?) are the
intercharacter space. Perfectly digital, so long as you can accept that
not all characters are the same digital length.

.... Martin VE3OAT

In article ,
says...
But consider that in OOK Morse, the characters for example are
A 10111000
B 111010101000
C 11101011101000

In each case, the last 3 zeroes (or should it be 5 zeroes?) are the
intercharacter space. Perfectly digital, so long as you can accept that
not all characters are the same digital length.

... Martin VE3OAT


__________________________________________________ _________

You're making a fundamental mistake. You are assigning numbers to
something which does not inherently have any numeric content, and then
calling the *original* thing digital.

Look at it this way: Is the music from a violin digital? No, of course
not. Is the recording of a violin on a CD digital? Yes, of course.
Does that make a violin a digital instrument? If you can figure out the
rationale behind the question, you will then be able to discern what
really is digital and what really is not. Otherwise, just go on calling
all binary things digital and we'll do our best to ignore the error.

--
Bill, W6WRT