Steve Nosko wrote:
"Then there`s the solid-state power amplifier standard output resistance
formula.
Rs = Vcc^2 / (2*Po)
The implication should be obvious."

It looks like Ohm`s law to me, P=Vsq / R.

The implication of (2*Po) is that 50% of the power is in the source and
50% of the power is in the load. If so, it`s a Class-A amplifier
formula, but the semiconductors could be biased to cut-off (Class-B) to
reduce dissipation in the transistors when they are idle. The best
collector load resistance is often not that which produces maximum
output, but that which produces maximum "undistorted output".

Best regards, Richard Harrison, KB5WZI