Steve Nosko wrote:
OK, OK, OK. How come voltage dB and power dB are different, huh? Yhy is it
that power dB carry twice the weight of voltage dB?

dB= 10 LOG(power ratio) = 20 LOG(voltage ratio)

Because log(v^2) = 2*log(v)? :-)
--
73, Cecil http://www.qsl.net/w5dxp



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