Tam/WB2TT wrote:
You have 2 equations, so you can solve for K1 and K2. You know it can't
*really* measure power, because there is no multiplier. Just like the Bird,
it *adds* (vector wise) voltage and current.

Exactly, and if you work out the math, you will find it yields
a meter deflection that can be calibrated in watts of forward
or reflected power.

In your example, assume that 70.7v yields a 5v sample and 1.414a
yields a 5v sample. If they are in phase, 10v will indicate 100
watts forward and zero volts will indicate zero watts reflected.
If they are not equal and not in phase, their sum still indicates
forward watts and their difference still indicates reflected watts.
--
73, Cecil http://www.qsl.net/w5dxp



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