What if the source doesn't or can't dissipate?

--
73
Hank WD5JFR
"Cecil Moore" wrote in message
...
Henry Kolesnik wrote:
I know they work! One of my reasons for asking the question is I've
not
found any mention in the literature of where the
"attenuation/rejection/reflection/filter residue" goes.

An open 1/4WL stub detours all the associated frequency
energy into the stub and then reflects it back to the source.
Consider the following:

XMTR---------feedline-------+----load
|
| 1/4WL
| open
| stub

The stub causes complete destructive interference between the
forward voltage and reflected voltage at the mouth of the stub.
Since the net voltage at the mouth of the stub is zero, no
current flows into the load. All the current in the feedline
is flowing in the stub and is reflected at the open end. The
reflected waves head back to the source. Therefore, for lossless
feedlines, all the attenuation/interference occurs in the source.
Of course, for real-world feedlines, I^2*R losses will occur
because of the high SWR at the associated frequency.

The effect of the above stub is much like shorting out the load.
Shorting out the load increases the dissipation in the source.
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73, Cecil http://www.qsl.net/w5dxp