Yuri Blanarovich wrote:
"Becomes very lossy" or paraphrased "lose its conductivity" to make the point?

I agree that a wire laid on the ground does not become very lossy
although energy is lost to the lossy medium in proximity to the wire.
What is happening is decreasing ExH power caused by field attenuation
in the ground. In free space, the E-field causes an equal energy H-field
which causes an equal energy E-field, ad infinitum. In the presence of a
lossy medium, like earth, the fields undergo an attenuation factor so
that each field strength is less than the previous cycle. The decrease
of the voltage and the current on/in the wire on the ground is *caused*
by the attenuation of the surrounding fields and would occur even if
the wire were a super-conductor. The wire itself does not "become very
lossy". The ground around the wire becomes very lossy.

Consider the power transferred through a transformer. The primary
has highly conductive insulated wire but "loses" virtually all of
its power, not through conduction, but through induction, to the
secondary. The losses through an insulated wire laid on the ground
are through induction, not conduction.
--
73, Cecil http://www.qsl.net/w5dxp



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