Jim Kelley wrote:
The simplest answer is that charges move in response to the local
electric field they experience. That field has only one value at that
point, at that instant, and is determined by the superposition of all
local electric fields.

Hi Jim, we missed you.

For RF, it is certainly possible for the network charges, at t(x), to
be moving in the opposite direction from force exerted by the network
electric field (voltage) at t(x). Remember, dQ/dt can have a different
sign from the sign of the electric field voltage. This ain't DC.
--
73, Cecil http://www.qsl.net/w5dxp



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