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Supporting theory that Antennas "Match" to 377 Ohms (Free space)
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August 21st 03, 09:52 AM
Dr. Slick
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wrote in message ...
"Dr. Slick" wrote:
So then that would be Work = 2*pi*(radius**2)*force.
Right. But it's a bit strange with rotational work, because if
you do one rotation, you are essentially back where you started. I
believe this has something to do with the fact that the rotational
displacement is dimensionless, and linear displacement is in units of
length.
If it takes one newton to make a block move and I push it north 1
metre, then east 1 metre, then south 1 metre, then west 1 metre,
I am back where I started but I did 4 joules worth of work (but
probably not useful work).
Ok, this is what i meant, "usefull work".
If I push the same block in a circle of radius 1 metre then I do
2pi joules of work: the circumference (distance travelled) times
the force.
So the expression at the top should not have a square in it.
...Keith
Nope. It needs another radius term...one for the circumference,
and one for the moment arm.
Slick
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