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Old July 14th 03, 08:30 PM
donut
 
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(Tom Bruhns) wrote in
m:

So by making the
loop a conductor with a gap, the EMF given by Faraday's law is
delivered almost completely to the gap. Doesn't matter if the loop
conductor is grounded at some point or not.


Thank you for your clear and concise answer. The part quoted above is what
was missing from my viewpoint.

As some seem to have concluded, I was not trying to be facetious.