On Tue, 26 Aug 2003 09:17:33 -0500, W5DXP
wrote:

Richard Clark wrote:
W5DXP wrote:
Two waves are flowing with unchanging energies and producing an absolutely
black ring, i.e. zero irradiance equals zero power.

Only when you violate conservation of energy, ...

No violation at all, Richard. The power (irradiance) that is lost
in the black rings is gained in the bright rings as explained in
_Optics_, by Hecht where he says constructive interference is
always equal to destructive interference.

Hi Cecil,

So you contradict yourself. Two waves do not produce a black ring,
they produce two rings (one dark, one bright) over an interval of one
wavelength (the proper bounds for an energy solution) and the sum of
them are the same as the applied powers - not zero. Choosing lesser
bounds to craft your "proof" constitutes an invalid proof.

73's
Richard Clark, KB7QHC